Provide an example of the solubility product constant of different ionic compounds.

The solubility product constant (Ksp) is a measure of the extent to which an ionic compound dissolves in water.

For example, the Ksp of calcium carbonate (CaCO3) is 3.3 x 10^-9. This means that in water, CaCO3 will dissociate into calcium ions (Ca2+) and carbonate ions (CO32-) until the concentration of these ions reaches a certain equilibrium point, at which the product of their concentrations equals 3.3 x 10^-9.

In contrast, the Ksp of silver chloride (AgCl) is 1.8 x 10^-10. This indicates that AgCl is less soluble in water than CaCO3, as the equilibrium concentration of Ag+ and Cl- ions in solution is much lower than that of Ca2+ and CO32- ions in solution.

The Ksp values of different ionic compounds can vary widely depending on factors such as temperature, pressure, and the presence of other ions in solution. Understanding the Ksp of a compound is important for predicting its solubility and for designing experiments to measure its concentration in solution.

Study and Practice for Free

Trusted by 100,000+ Students Worldwide

Achieve Top Grades in your Exams with our Free Resources.

Practice Questions, Study Notes, and Past Exam Papers for all Subjects!

Need help from an expert?

4.93/5 based on546 reviews

The world’s top online tutoring provider trusted by students, parents, and schools globally.

Related Chemistry a-level Answers

    Read All Answers
    Loading...