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AP Statistics study notes

7.6.3 Determining the Margin of Error for Two Means

AP Syllabus focus:
‘The margin of error for the difference in two sample means is computed using the critical value t* from the t-distribution with appropriate degrees of freedom, multiplied by the standard error of the difference. The standard error is calculated with the formula: SE = √((s1²/n1) + (s2²/n2)), where s1 and s2 are the sample standard deviations, and n1 and n2 are the sample sizes.’

The margin of error for two means quantifies how much random sampling variation may affect an estimate of the difference between population means, guiding the precision of statistical conclusions.

Margin of Error in Two-Sample Inference

The margin of error for the difference in two means reflects the maximum expected difference between the sample-based estimate and the true population difference under repeated sampling. It is central to constructing a confidence interval for the difference in population means and directly incorporates information about variability, sample sizes, and the chosen confidence level.

Why Margin of Error Matters

In two-sample problems, students measure how much uncertainty surrounds the estimate x̄₁ − x̄₂, the observed difference between sample means. Because both samples introduce variability, the margin of error must account for each sample's spread and size. A larger margin of error indicates reduced precision, while a smaller one reflects stronger evidence that the sample difference closely approximates the true population difference.

Components of the Margin of Error

The AP specification emphasizes two essential components: the critical value and the standard error. Understanding these parts helps clarify how changes in sample size, variability, or confidence level influence the interval’s width.

The Critical Value t*

The critical value t* is selected from a t-distribution, not a normal distribution, because the population standard deviations are unknown. It increases as the desired confidence level increases and depends on the degrees of freedom, which are approximated using statistical software for two-sample procedures. A higher t* produces a wider confidence interval and a larger margin of error.

The Standard Error of the Difference

The standard error measures the expected variability in the sampling distribution of x̄₁ − x̄₂ when random samples of sizes n₁ and n₂ are repeatedly drawn. It combines uncertainty from both samples. Introducing the term standard error requires a precise definition.

Standard Error of the Difference: A measure of the variability in the sampling distribution of the difference in sample means, combining the spreads and sizes of both samples.

Because each sample contributes to overall variability, increasing either sample size lowers the standard error and therefore reduces the margin of error, improving precision.

A complete mathematical expression follows, showing how these components work together.

EQUATION

Margin of Error=t×SE \text{Margin of Error} = t^* \times SE
SE=s12n1+s22n2 SE = \sqrt{\frac{s_1^2}{n_1} + \frac{s_2^2}{n_2}}
t t^* = Critical value from the t-distribution based on degrees of freedom
s1,s2 s_1, s_2 = Sample standard deviations for samples 1 and 2
n1,n2 n_1, n_2 = Sample sizes for samples 1 and 2

This formulation highlights the role of sample variability, emphasizing that the standard error grows when standard deviations are large or sample sizes are small.

The margin of error for a confidence interval for μ₁ − μ₂ is the distance from the center point estimate xˉ1−xˉ2\bar x_1 - \bar x_2xˉ1​−xˉ2​ to either endpoint of the interval.

This diagram illustrates a normal sampling distribution with a central confidence interval, highlighting the total width of the interval and the margin of error on one side. The shaded region shows plausible values for the parameter at a given confidence level, and the braces demonstrate that the margin of error is half the interval’s width. Although shown for a single mean, this structure applies equally to confidence intervals for the difference between two population means. Source.

Interpreting the Margin of Error

Interpreting the margin of error requires understanding how each term contributes to uncertainty. A wider margin of error suggests that the sample difference may vary substantially from sample to sample, limiting precision. A narrower margin of error signals greater stability across repeated sampling.

Factors That Increase the Margin of Error

Students should be aware of the specific components that enlarge the margin of error and therefore widen the confidence interval:

  • Larger critical value (t)**, which results from choosing a higher confidence level. A 99% interval will always have a larger t than a 95% interval.

  • Larger sample standard deviations (s₁ or s₂), which indicate more variability within samples.

  • Smaller sample sizes (n₁ or n₂), which heighten uncertainty in estimating each population mean.

These factors interact multiplicatively, so even moderate increases in variability or confidence level can noticeably widen the interval.

Because the standard error term s12n1+s22n2\sqrt{\dfrac{s_1^2}{n_1} + \dfrac{s_2^2}{n_2}}n1​s12​​+n2​s22​​​ becomes smaller as either sample size increases, larger samples produce a smaller margin of error and a narrower confidence interval for μ₁ − μ₂.

This figure compares sampling distributions of the sample mean for multiple sample sizes. As sample size grows, the distributions narrow, reflecting a smaller standard error. The same principle explains why increasing n1n_1n1​ or n2n_2n2​ reduces the standard error for xˉ1−xˉ2\bar x_1 - \bar x_2xˉ1​−xˉ2​ and therefore the margin of error. Source.

Factors That Decrease the Margin of Error

Because research often aims for precise estimates, students should recognize circumstances that make the margin of error smaller and more useful:

  • Increasing sample sizes, which reduce the standard error by stabilizing estimates of each population mean.

  • Lower variability within samples, resulting in smaller standard deviations.

  • Choosing a lower confidence level, which reduces t*, though at the cost of decreased certainty that the interval captures the true population difference.

Holding the confidence level and population variability fixed, doubling the sample sizes in both groups reduces the standard error term, which in turn cuts the margin of error for μ₁ − μ₂ and tightens the interval.

This chart illustrates how margins of error change with sample size, with larger samples producing narrower intervals. Although created for survey proportions, the inverse relationship between sample size and margin of error also governs confidence intervals for the difference of two means. The surrounding article includes additional polling context not required for this topic. Source.

Relationship to Confidence Intervals

The margin of error directly determines the width of the confidence interval for two means because it establishes the distance added and subtracted from the observed difference in sample means. A larger margin of error yields a wider interval, while a smaller one produces a narrower interval. In all cases, the margin of error expresses how sampling uncertainty influences the reliability of conclusions about population differences.

FAQ

The t-distribution accounts for the additional uncertainty that comes from estimating population standard deviations using sample values. This is essential when working with real data where true variability is unknown.

As sample sizes increase, the t-distribution becomes closer to the normal distribution, but for smaller samples it provides more accurate critical values by allowing heavier tails.

When one group has a much larger standard deviation, that group contributes more heavily to the standard error, increasing the margin of error overall.

Large inequality in variability can make the interval noticeably wider, even if both sample sizes are large. This is because the standard error formula weights each group’s variability separately.

Yes. A small observed difference does not guarantee a precise estimate of the population difference.

A large margin of error can occur when:
• Both samples have high variability.
• One or both sample sizes are small.
• A high confidence level is chosen, increasing the critical value.

Higher confidence levels require larger critical values, increasing the margin of error and widening the interval.

Lower confidence levels reduce the margin of error but decrease certainty that the interval contains the true population difference. This creates a trade-off between confidence and precision.

Because the standard error depends on two components, each sample contributes its own variability term. If one sample remains small or highly variable, the overall standard error may still be dominated by that group.

Increasing both sample sizes is usually the most effective way to reduce the margin of error meaningfully.

Practice Questions

Question 1 (1–3 marks)
A researcher collects two independent random samples to estimate the difference in mean reaction time between athletes and non-athletes. The sample standard deviations are s1 = 12 ms and s2 = 20 ms, with sample sizes n1 = 25 and n2 = 40.
Calculate the standard error of the difference in sample means.

Question 1
• 1 mark: Correct substitution into the standard error formula: SE = sqrt( (12^2 / 25) + (20^2 / 40) ).
• 1 mark: Correct intermediate values (12^2 / 25 = 5.76 and 20^2 / 40 = 10).
• 1 mark: Correct final answer: SE = sqrt(15.76) ≈ 3.97 ms.

Award full marks for correct working and answer. Minor rounding differences are acceptable.

Question 2 (4–6 marks)
A nutrition scientist is comparing average iron levels (in mg/day) between two independent groups: adolescents and adults. She constructs a 95% confidence interval for the difference in population means (adolescents minus adults) using the formula (x̄1 − x̄2) ± t* × SE.
The calculated standard error is SE = 1.8, and the critical value is t* = 2.06.
(a) Calculate the margin of error.
(b) Explain how increasing both sample sizes would affect the margin of error, and justify your explanation using the structure of the standard error formula.

Question 2

(a):
• 1 mark: Correct use of margin-of-error formula: MOE = t* × SE.
• 1 mark: Correct calculation: 2.06 × 1.8 = 3.708 (allow rounding to 3.71 or 3.7).

(b):
• 1 mark: Statement that increasing both sample sizes decreases the margin of error.
• 1 mark: Correct justification referencing the standard error formula: SE = sqrt( (s1^2 / n1) + (s2^2 / n2) ).
• 1 mark: Clear explanation that increasing n1 and n2 reduces each variance term, lowering SE and therefore reducing the margin of error.

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