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IBDP Maths AA SL Predicted Paper 1 set 1

Questions

Question 1

The diagram shows five small graphs on the same axes grid. Use the sketches to answer the questions.

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Part a
[2]

From the set of five sketches, select all the relations that are functions. Give a brief reason using the vertical line test.

Part b
[2]

From those that are functions, select any one that is not one-to-one and explain why using the horizontal line test.

Part c
[3]

For one graph that is a one-to-one function, state its domain and range as suggested by the sketch and describe how the graph of its inverse would relate to it. No sketch required.

[7]

Question 2

The diagram shows the curve y=x2y = x^2 with a point A(1,1)A(1, 1), its normal at AA, and the origin OO.

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Part a
[2]

Find the equation of the normal to y=x2y = x^2 at A(1,1)A(1, 1).

Part b
[3]

The normal meets the parabola again at BB. Find the coordinates of BB.

Part c
[2]

Let θ\theta be the angle AO^BA\hat{O}B (the angle between OAOA and OBOB). Show that tanθ=5\tan \theta = 5.

[7]

Question 3

The diagram shows a circle with centre OO, radius OA=rOA = r, and arc ABAB subtending angle θ\theta at OO. Point MM is the midpoint of OAOA, so OM=r2OM = \frac{r}{2}.

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Part a
[2]

Write down, in terms of rr and θ\theta (radians), the length of arc ABAB and the area of sector OABOAB.

Part b
[3]

Consider the smaller, concentric sector OMBOMB of radius r2\frac{r}{2} and angle θ\theta. Show that area(OMB):area(MAB)=1:3\mathrm{area}(OMB) : \mathrm{area}(MAB) = 1 : 3, where MABMAB denotes the annular sector between radii OMOM and OAOA.

Part c
[2]

If r=8 cmr = 8\ \mathrm{cm} and arc ABAB has length 10 cm10\ \mathrm{cm}, find θ\theta and hence the area of region MABMAB.

[7]

Question 4

Part a
[3]

Solve for xx: 32x=279x13^{2x} = 27 \cdot 9^{x-1}.

Part b
[3]

Solve for xx: 2log2(x+1)log2(x3)=22\cdot \log_{2}(x+1) - \log_{2}(x-3) = 2, given x>3x > 3.

[6]

Question 5

A small sample of seven measurements (in mm) is:
4, 7, 8, 9, 10, 10, 25

Part a
[2]

Find the median and the interquartile range (IQR).

Part b
[2]

Using the 1.5×IQR1.5\times \mathrm{IQR} rule, decide whether 25 mm25\ \mathrm{mm} is an outlier. Show working.

Part c
[2]

If all values were decreased by 3, state the new mean and state what happens to the standard deviation.

[6]

Question 6

A quadratic function has vertex (2,3)(2, -3) and passes through (0,1)(0, 1).

Part a
[3]

Write f(x)f(x) in vertex form and then in expanded form.

Part b
[2]

Find the discriminant and hence the number of real roots.

Part c
[2]

Solve f(x)=0f(x) = 0 exactly.

[7]

Question 7

The diagram shows the curves y=2x+9y = \sqrt{2x + 9} and y=4e2x1y = 4e^{-2x} - 1. They intersect at the point on the yy-axis. The shaded region is bounded by the curves and the xx-axis.

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Part a
[2]

Show that the curves intersect at (0,3)(0, 3).

Part b
[3]

Find the xx-intercepts of each curve.

Part c
[3]

Write an exact expression, as a sum of definite integrals, for the total shaded area.

Part d
[6]

Hence find the exact value of the shaded area.

[14]

Question 8

Let f(x)=2cos!(3(xπ6))+1f(x) = 2\cos!\left(3\left(x - \frac{\pi}{6}\right)\right) + 1.

Part a
[3]

State the amplitude, the midline, and the period of ff.

Part b
[3]

Find the maximum value of ff and one xx-value in [0,2π][0, 2\pi] at which it occurs.

Part c
[7]

Solve 2cos!(3(xπ6))+1=122\cos!\left(3\left(x - \frac{\pi}{6}\right)\right) + 1 = \frac{1}{2} for xx in [0,2π][0, 2\pi]. Give exact values.

[13]

Question 9

A rectangle has its upper vertices on the curve y=9x2y = 9 - x^2 and its base on the xx-axis. The rectangle is symmetric about the yy-axis.

Part a
[3]

Show that if the right-hand upper vertex is (x,9x2)(x, 9 - x^2) with x>0x > 0, then the area AA of the rectangle is A=2x(9x2)A = 2x(9 - x^2).

Part b
[6]

Find the value of xx that maximises AA and the maximum area.

Part c
[4]

Determine the yy-coordinate of the rectangle’s upper side at maximum area.

[13]

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