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IBDP Maths AI HL Predicted Paper 2 set 1

Questions

Question 1

A small ball PP is projected from point AA with speed 39,m s139,\text{m s}^{-1} at an angle θ\theta to the horizontal, where sinθ=513\sin\theta=\frac{5}{13} and cosθ=1213\cos\theta=\frac{12}{13}. Point AA is 20,m20,\text{m} above horizontal ground. The ball first lands at point CC on the ground. Let g=9.8,m s2g=9.8,\text{m s}^{-2}. Take the horizontal through AA as the xx-axis (positive to the right) and the vertical through AA as the yy-axis (positive upwards). BB is the point on the ground vertically below AA.

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Part a
[2]

Resolve the initial velocity into horizontal and vertical components.

Part b
[5]

Show that the vertical position satisfies y(t)=20+15t12gt2y(t)=20+15t-\frac{1}{2}gt^{2}. Hence find the time of flight to CC, giving your answer to 33 significant figures.

Part c
[3]

Find the horizontal distance BCBC. Give your answer to 33 significant figures.

Part d
[3]

Find the maximum height above the ground reached by PP.

Part e
[5]

Find the speed and the angle to the horizontal of PP on impact at CC (angle below the horizontal). Give both to 33 significant figures.

[18]

Question 2

An inverted conical tank has semi-vertical angle 3030^\circ and height 50,cm50,\text{cm}. It is initially full of water. The outflow is modelled by dVdt=2h\frac{dV}{dt}=-2h, where V,(cm3)V,(\text{cm}^3) is the volume of water and h,(cm)h,(\text{cm}) is the depth.

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Part a
[4]

Express VV as a function of hh.

Part b
[5]

Using dVdt=(dVdh)(dhdt)\frac{dV}{dt}=\left(\frac{dV}{dh}\right)\left(\frac{dh}{dt}\right), derive a differential equation for h(t)h(t) and hence find dhdt\frac{dh}{dt} in terms of hh.

Part c
[6]

Solve your differential equation to obtain h(t)h(t), given that h(0)=50h(0)=50.

Part d
[5]

Find (i) the time taken for the tank to empty; (ii) the value of dhdt\frac{dh}{dt} when h=30,cmh=30,\text{cm}. State appropriate units.

[20]

Question 3

Consider the region RR bounded by the curve y=13x23x+1y=\frac{1}{\sqrt{3x^{2}-3x+1}}, the xx-axis, and the vertical lines x=12x=\frac{1}{2} and x=1x=1. Distances are in centimetres.

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Part a
[3]

Show that 3x23x+1>03x^{2}-3x+1>0 for all real xx.

Part b
[9]

The pendant is formed when RR is rotated 2π2\pi radians about the xx-axis. Show that
V=πx=12x=1[13x23x+1],dxV=\pi\int_{x=\frac{1}{2}}^{x=1}\left[\frac{1}{3x^{2}-3x+1}\right],dx,
and evaluate VV exactly.

Part c
[4]

Using your GDC, find the surface area S=2πx=12x=1y1+(y)2,dxS=2\pi\int_{x=\frac{1}{2}}^{x=1}y\sqrt{1+(y')^{2}},dx, giving your answer to 33 significant figures.

[16]

Question 4

Two curves intersect on the yy-axis and a shaded region is bounded by the curves and the xx-axis. The curves are y=2x+9y=\sqrt{2x+9} and y=4e2x1y=4e^{-2x}-1.

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Part a
[2]

Verify that the curves meet at (0,3)(0,3).

Part b
[4]

Find the xx-intercepts of each curve.

Part c
[8]

Write AA, the total shaded area, as a sum of definite integrals and evaluate AA exactly.

Part d
[4]

Using your GDC, plot both curves on the interval 5x2-5\le x\le 2 with an appropriate viewing window, and state which curve lies above the other on 0xln20\le x\le \ln 2.

[18]

Question 5

The velocity–time graph “Velocity-Time Graph for Two Cars_OCR.png” shows two cars AA and BB moving along a straight, level road. At t=0,st=0,\text{s}, car BB is travelling at 12,m s112,\text{m s}^{-1} and is overtaken by car AA travelling at 20,m s120,\text{m s}^{-1}. From t=0t=0 to t=30,st=30,\text{s}, AA decelerates uniformly to 8,m s18,\text{m s}^{-1}, then continues at 8,m s18,\text{m s}^{-1} thereafter.

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Part a
[3]

Find the deceleration of car AA in m s2\text{m s}^{-2}.

Part b
[5]

Find the distance travelled by each car in the first 30,s30,\text{s}.

Part c
[5]

Determine the time after t=0t=0 when BB next overtakes AA (i.e., the next time their positions are equal).

Part d
[5]

Find the distance from the start at the instant of overtaking in part (c).

[18]

Question 6

A system switches between two states S1S_1 and S2S_2 each minute. The transition matrix is
T=(0.80.3\0.20.7)T=\begin{pmatrix}0.8&0.3\0.2&0.7\end{pmatrix},
where TijT_{ij} is the probability of moving from state jj to state ii in one minute.

Part a
[4]

Starting in S1S_1 with certainty, write the initial state vector s0s_0 and find s1s_1 and s2s_2.

Part b
[6]

Find the steady-state vector ss_\infty exactly.

Part c
[6]

Show that TT has eigenvalues λ1=1\lambda_1=1 and λ2=0.5\lambda_2=0.5. Find a corresponding eigenvector for each eigenvalue.

Part d
[4]

Explain why Tn(0.60.6\0.40.4)T^{n}\to\begin{pmatrix}0.6&0.6\0.4&0.4\end{pmatrix} as nn\to\infty, and interpret this result in context.

[20]

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