Calculate the derivative of the function y = log(2x) base 10.

The derivative of y = log(2x) base 10 is 1/(xln10).

To find the derivative of y = log(2x) base 10, we can use the chain rule. Let u = 2x, then y = log(u) base 10. Using the chain rule, we have:

dy/dx = dy/du * du/dx

To find dy/du, we can use the formula for the derivative of log functions:

d/dx log_a(u) = 1/(u ln a)

In this case, a = 10, so we have:

dy/du = 1/(u ln 10)

Substituting back in for u, we have:

dy/dx = dy/du * du/dx
= 1/(u ln 10) * 2
= 2/(2x ln 10)
= 1/(x ln 10)

Therefore, the derivative of y = log(2x) base 10 is 1/(x ln 10).