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The derivative of y = log(x) base 10 is 1/(xln(10)).
To find the derivative of y = log(x) base 10, we can use the formula for the derivative of a logarithmic function:
d/dx log_a(x) = 1/(xln(a))
where a is the base of the logarithm. In this case, a = 10, so we have:
d/dx log_10(x) = 1/(xln(10))
Therefore, the derivative of y = log(x) base 10 is 1/(xln(10)).
We can also check this result using the rules of logarithms. Recall that:
log_a(x) = log_b(x)/log_b(a)
where b is any base. In particular, we can write:
log_10(x) = ln(x)/ln(10)
Using this expression, we can rewrite y = log(x) base 10 as:
y = ln(x)/ln(10)
Taking the derivative of both sides with respect to x, we get:
dy/dx = (1/ln(10)) d/dx ln(x)
Using the chain rule, we have:
d/dx ln(x) = 1/x
Substituting this back into the previous equation, we get:
dy/dx = (1/ln(10)) (1/x)
Simplifying, we get:
dy/dx = 1/(xln(10))
which is the same result we obtained earlier.
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