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To integrate (e^x)/(1+e^x), use substitution u = 1+e^x and simplify.
To integrate (e^x)/(1+e^x), use substitution u = 1+e^x. Then, du/dx = e^x and dx = du/e^x. Substituting these into the integral gives:
∫(e^x)/(1+e^x) dx = ∫(1/u) du
Integrating this gives:
= ln|u| + C
Substituting back in for u gives:
= ln|1+e^x| + C
Therefore, the integral of (e^x)/(1+e^x) is ln|1+e^x| + C.
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