AP Syllabus focus:
‘Recognize that acceleration is the derivative of velocity and the second derivative of position, and use these relationships to describe how motion is speeding up or slowing down.’
Acceleration and higher derivatives reveal how motion evolves over time, linking position, velocity, and acceleration to describe changes in speed and direction with growing precision in dynamic situations.
Acceleration and Its Role in Describing Motion
Acceleration is a central idea in straight-line motion because it captures how an object’s velocity changes at each instant. The derivative structure of motion builds systematically: position describes where an object is, velocity describes how its position changes, and acceleration describes how its velocity changes. By connecting these quantities through successive derivatives, AP Calculus AB students learn to interpret motion with mathematical accuracy and contextual clarity.
When studying straight-line motion, it is essential to identify the independent variable, which is almost always time. Each derivative taken with respect to time deepens the description of the object’s behavior. A function describing position leads directly to its derivative, velocity, and the derivative of velocity yields acceleration, offering a layered understanding of how motion unfolds.
Acceleration: The instantaneous rate of change of velocity with respect to time; equivalently, the second derivative of position with respect to time.
Because acceleration relates to both speed and direction, its sign carries important meaning. A positive or negative value indicates directional behavior, while comparisons between velocity and acceleration signs reveal whether the object is speeding up or slowing down. This interpretive relationship makes higher derivatives powerful tools for analyzing complex or rapidly changing motion.
Higher Derivatives and Their Interpretive Structure
The higher-derivative relationships in one-dimensional motion form a predictable chain. Beginning with a position function, each derivative produces a new layer of motion information. This structure gives students a consistent framework for interpreting real-world motion through calculus.
= Velocity; rate of change of position (units of distance/time)
= Position; location of the object along a line (units of distance)
A single sentence now intervenes to provide context and maintain appropriate formatting flow before introducing the next equation block.
= Acceleration; rate of change of velocity (units of distance/time²)
= Velocity; instantaneous rate of change of position
= Position function describing motion along a line

A velocity–time graph displaying a curved velocity function and its tangent line, whose slope represents instantaneous acceleration. The shaded region indicates displacement over a time interval, an extra detail beyond the syllabus but conceptually consistent. The diagram highlights how acceleration arises from the rate of change of velocity. Source.
These derivative relationships make it possible to describe subtle details about motion. For instance, knowing only the position function allows students to determine velocity and acceleration directly through differentiation. Conversely, velocity or acceleration data may be used to infer motion characteristics even without the original position function.
Understanding Signs, Speeding Up, and Slowing Down
Interpreting acceleration requires attention not only to the value of but also to how it interacts with velocity. The combined signs of velocity and acceleration determine whether an object increases or decreases its speed. Motion analysis becomes richer when students understand how directional information and rates of change overlap.
Key interpretive relationships include:
Same sign for velocity and acceleration
The object is speeding up because acceleration reinforces its current direction of motion.Opposite signs for velocity and acceleration
The object is slowing down because acceleration acts opposite the current direction of travel.

An airplane landing with velocity arrows pointing forward and acceleration arrows pointing backward illustrates slowing down in straight-line motion. When acceleration opposes velocity, the object's speed decreases even while moving forward. Numerical labels included in the figure extend beyond the calculus syllabus but remain conceptually consistent. Source.
Acceleration equal to zero
The velocity is not changing at that instant, although the object may still be moving.
These relationships show why acceleration is more than just a number: it indicates how the behavior of the motion is evolving. Careful interpretation ensures that students describe motion effectively in context, aligning with the syllabus requirement to use acceleration and higher derivatives to explain how motion is speeding up or slowing down.
Using Higher Derivatives to Analyze Motion Behavior
Beyond simply computing derivatives, students must interpret what these derivatives reveal about an object’s changing motion. Higher derivatives contribute to understanding acceleration patterns, transitions in behavior, and the underlying dynamics of straight-line movement.
Important structures to analyze include:
Intervals where acceleration is positive or negative
These intervals reveal regions of increasing or decreasing velocity.
Changes in the sign of acceleration
Such changes may indicate transitions from speeding up to slowing down or vice versa.
Comparison of velocity and acceleration signs
This allows students to determine the qualitative behavior of motion without computing numerical values.
Concavity of the position function
Because acceleration is the second derivative of position, its value determines whether the position graph bends upward or downward, linking motion to geometric representation.
These interpretive strategies reinforce a deeper understanding of motion and satisfy the AP requirement to recognize acceleration as the derivative of velocity and the second derivative of position, while using these relationships to describe speeding up or slowing down.
Higher-Order Thinking About Motion
Analyzing motion through acceleration and higher derivatives supports precise descriptions of dynamic processes. Students learn to interpret instantaneous behavior, understand how patterns of change develop over time, and connect mathematical derivatives to meaningful physical insights. By mastering these relationships, they gain the tools necessary to describe motion thoroughly and clearly within the framework of calculus.
FAQ
Look at the concavity of the position graph. If the graph is concave up, acceleration is positive; if concave down, acceleration is negative.
You can also interpret changes in the steepness of the slope. If the slope of the position graph is becoming steeper, the object’s velocity is increasing, indicating positive acceleration. A flattening slope suggests negative acceleration.
Constant acceleration means the rate of change of velocity remains fixed, but the velocity itself will still vary over time.
In physical terms, the object experiences a uniform push or pull. As a result:
• The velocity changes linearly.
• The position changes quadratically.
• Motion behaviour becomes predictable across equal time intervals.
Speeding up depends on the relationship between velocity and acceleration, not acceleration alone.
If acceleration and velocity share the same sign, speed increases; if their signs differ, speed decreases.
Thus, even a positive acceleration does not guarantee increasing speed if the velocity is negative.
The second derivative reveals how changes in motion are themselves changing.
Velocity shows how quickly position shifts, but acceleration describes how the motion evolves from moment to moment. It helps identify transitions in behaviour, such as when an object switches between speeding up and slowing down or when directional changes occur.
Acceleration can be zero whenever velocity is momentarily constant, even if the object is still moving.
Common cases include:
• An object moving at a steady speed along a straight track.
• A momentary transition point where velocity reaches a local maximum or minimum.
In such cases, motion continues, but no change in velocity occurs at that instant.
Practice Questions
Question 1 (1–3 marks)
A particle moves along a straight line so that its velocity at time t seconds is given by v(t) = 3t − 4.
(a) Find the acceleration of the particle at t = 2.
Question 1
(a) Velocity is v(t) = 3t − 4, so acceleration is the derivative: a(t) = 3.
• Correct derivative identified: 1 mark
• Correct evaluation a(2) = 3: 1 mark
• Clear statement that acceleration is constant: 1 mark
Question 2 (4–6 marks)
An object moves along a horizontal line with position s(t) measured in metres, where t is measured in seconds.
The velocity of the object is given by v(t) = t² − 5t + 6.
(a) Find the acceleration function a(t).
(b) Determine all times t when the object is speeding up.
(c) Explain, using the signs of velocity and acceleration, why your answer in part (b) is correct.
Question 2
(a)
Acceleration is the derivative of velocity: a(t) = 2t − 5.
• Correct differentiation: 1 mark
(b)
Object speeds up when velocity and acceleration have the same sign.
Velocity factorises to v(t) = (t − 2)(t − 3).
Critical points: velocity zero at t = 2 and t = 3; acceleration zero at t = 2.5.
Sign analysis gives:
• Speeding up for t < 2
• Speeding up for t > 3
• Correct factorisation of velocity: 1 mark
• Correct sign analysis of v(t): 1 mark
• Correct sign analysis of a(t): 1 mark
• Correct intervals identified: 1 mark
(c)
Explanation based on sign agreement:
Velocity and acceleration both positive or both negative in the intervals found.
• Clear explanation connecting signs of v and a: 1 mark
