AP Syllabus focus:
‘From the graph of f′(x), intervals where the graph lies above the x-axis correspond to f increasing, while intervals where the graph lies below correspond to f decreasing.’
Understanding how the graph of a derivative reflects the behavior of the original function is essential for interpreting change, identifying trends, and analyzing intervals of increase or decrease.
Describing Behavior from a Graph of f′
When analyzing how a function behaves, interpreting the graph of its first derivative provides a powerful way to understand whether the function is rising, falling, or maintaining horizontal tangents. This subsubtopic focuses on translating the visual information from f′(x) into precise statements about the behavior of the original function f(x). Because the derivative represents the instantaneous rate of change, its graph directly reveals where the function increases, decreases, or has stationary points.
Understanding What a Graph of f′ Represents
The graph of f′(x) displays the numerical value of the derivative at each input x, which means it communicates slope information visually. When the graph lies above or below the x-axis, it reveals the sign of the derivative, which directly determines how the original function behaves.
Derivative: The instantaneous rate of change of a function, representing the slope of the tangent line to the graph of the function at each point.
A graph of the derivative therefore provides a continuous illustration of how steeply and in which direction the original function changes.

This figure shows four segments of a function with tangent lines labeled according to whether is positive or negative. It visually connects the sign of the derivative to increasing or decreasing behavior. The focus is exclusively on monotonicity without introducing techniques beyond this subsubtopic. Source.
Interpreting the Sign of f′ from Its Graph
The most essential technique for interpreting f′(x) is examining whether the graph is above the x-axis (positive) or below the x-axis (negative).
When the graph of f′(x) lies above the x-axis, the derivative is positive, so f is increasing on that interval.
When the graph of f′(x) lies below the x-axis, the derivative is negative, so f is decreasing on that interval.
When the graph touches or crosses the x-axis at some value of x, we have f′(x) = 0, meaning the original function has a horizontal tangent at that point.
These observations allow us to describe behavior without manipulating algebraic expressions.
Identifying Horizontal Tangent Points
Points where the derivative crosses or touches the x-axis are extremely important because they indicate potential changes in the direction of the original function.
Horizontal Tangent: A point on the graph of a function where the slope is zero, corresponding to f′(x) = 0.
A horizontal tangent does not necessarily indicate a maximum or minimum; it simply marks a moment when the instantaneous rate of change pauses. Interpreting the sign of f′(x) on either side of such points helps determine how the function behaves near them.
Describing Increasing and Decreasing Behavior Visually
Using the graph of f′, we describe behavior of f by noting changes in the derivative’s sign and position relative to the x-axis.

This diagram compares with its derivative , showing increasing intervals where lies above the x-axis and decreasing intervals where it lies below. It demonstrates how the behavior of is read directly from the sign of . Some additional features such as extrema and inflection behavior appear, though they are not required for this subsubtopic. Source.
Key steps for describing behavior:
Identify intervals above the x-axis → f is increasing.
Identify intervals below the x-axis → f is decreasing.
Mark all x-intercepts of f′ → possible turning points of f.
Connect sign intervals verbally to build a clear narrative about the function’s behavior.
These steps form the basis for writing mathematical justifications in AP Calculus.
Understanding Transitions in the Graph of f′
Transitions provide valuable information about change in behavior. A shift from positive to negative values of f′ means the original function transitions from increasing to decreasing, while a shift from negative to positive values reveals the opposite. However, identifying these transitions is only descriptive in this subsubtopic; classification of extrema belongs elsewhere in the syllabus.
Using f′ Graphs to Understand Trends in f
The graph of f′(x) can also help provide a deeper understanding of how the original function rises or falls.
Important insights include:
Steeper positive values of f′ indicate faster increase in f.
Steeper negative values of f′ indicate faster decrease in f.
Portions of the derivative graph hovering close to the x-axis correspond to intervals where f changes very slowly.
These interpretations strengthen students’ ability to describe a function qualitatively.
Writing Clear Descriptions from f′ Graphs
When writing about behavior from a graph of f′, use precise statements grounded in the sign of the derivative. Strong AP-level descriptions reference where the derivative is positive or negative, not merely where the graph appears to rise or fall.
Helpful phrasing includes:
“Because f′(x) > 0 on the interval…, the function f is increasing there.”
“Since f′(x) < 0 on…, the function f decreases throughout that interval.”
“At x = c, the derivative equals zero, so f has a horizontal tangent at that point.”
These descriptions maintain clarity, mathematical rigor, and alignment to the syllabus.
FAQ
The steepness of f' relative to the x-axis indicates how rapidly f is changing. Large positive values imply rapid increase, while large negative values suggest rapid decrease.
If the graph of f' stays close to the x-axis, f changes very slowly even if f' does not equal zero. This helps identify intervals where the function appears almost flat despite not having a horizontal tangent.
Yes. If f' touches the x-axis without going above it, and does so only at isolated points, f may still be increasing elsewhere.
A derivative equal to zero at isolated points does not stop the function’s overall increasing trend; only sustained negative derivative values indicate decreasing behaviour.
Changes in the steepness of the graph of f' can reveal how the rate of change of f varies, even when the sign stays consistent.
For example:
• A rising f' suggests that f’s increase is accelerating.
• A falling f' suggests that f’s increase is slowing down.
This gives a more nuanced picture than simply classifying intervals as increasing or decreasing.
If the graph lacks clear intersection points with the x-axis or appears irregular, it becomes difficult to judge sign changes accurately.
Ambiguity may arise from:
• Graphs that do not show endpoints clearly.
• Missing sections that conceal sign changes.
• Visual distortions that make it unclear whether f' is exactly zero or slightly above or below.
Interpreting behaviour requires precise sign analysis, so ambiguous graphs can limit certainty.
The x-intercepts of f' reveal where the slope of f becomes zero, marking potential turning points or changes in behaviour.
These points act as boundaries between intervals where f is increasing or decreasing. Without examining where f' crosses or touches the x-axis, it is impossible to segment the function’s behaviour properly and describe how f evolves across different intervals.
Practice Questions
Question 1 (1–3 marks)
The graph of the derivative f'(x) is shown.
• On the interval 1 < x < 4, the graph of f'(x) lies entirely above the x-axis.
• At x = 4, the graph crosses the x-axis and remains below it for x > 4.
(a) State the values of x for which the function f is increasing.
(b) Explain why x = 4 corresponds to a horizontal tangent on the graph of f.
Question 1
(a)
• 1 mark: Correctly stating that f is increasing on 1 < x < 4.
(b)
• 1 mark: Identifying that a horizontal tangent occurs because f'(4) = 0.
• 1 mark: Explaining that the derivative equals zero at x = 4, so the slope of f is zero there.
Question 2 (4–6 marks)
A portion of the graph of f'(x) is shown.
• f'(x) < 0 for 0 < x < 2
• f'(x) = 0 at x = 2
• f'(x) > 0 for 2 < x < 5
• f'(x) = 0 again at x = 5
• f'(x) < 0 for x > 5
(a) Describe fully the intervals on which the function f is decreasing.
(b) Explain what happens to the graph of f at x = 2.
(c) Determine whether x = 5 corresponds to a turning point of f. Give a reason for your answer.
(d) Sketch a possible qualitative shape of f'(x) that matches the description, labelling key features. (Precision of scale is not required.)
Question 2
(a)
• 1 mark: Stating that f is decreasing on 0 < x < 2.
• 1 mark: Stating that f is also decreasing for x > 5.
(b)
• 1 mark: Stating that f has a horizontal tangent at x = 2.
• 1 mark: Explaining that f'(x) changes from negative to positive, so f changes from decreasing to increasing.
(c)
• 1 mark: Correctly identifying that x = 5 is a turning point.
• 1 mark: Justifying that f'(x) changes sign from positive to negative, so the graph of f changes from increasing to decreasing.
(d)
• 1 mark: Producing a qualitative sketch of f'(x) with negative, zero, positive, zero, and negative sections in the correct order.
• 1 mark: Correctly labelling key points at x = 2 and x = 5.
