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AP Calculus AB study notes

6.5.1 Relating f and Its Accumulation Function g

AP Syllabus focus:
‘Given g(x) defined as an integral of f(t) from a to x, use information about f to describe how g behaves, including where g is increasing or decreasing.’

Accumulation functions connect a rate of change to total change, allowing us to understand how the behavior of f, a rate function, determines the growth, decrease, and key features of g, its accumulation function.

Understanding the Relationship Between f and g

An accumulation function is a function defined using a definite integral with a variable upper limit. In this subsubtopic, g(x) is defined in terms of a given function f(t), and the goal is to interpret how the graph, sign, and behavior of f determine the qualitative behavior of g. Because the integral accumulates signed area, every feature of f carries interpretive consequences for g, making this relationship a core conceptual skill in AP Calculus AB.

Accumulation Function: A function defined as g(x)=axf(t),dtg(x) = \int_a^x f(t),dt, representing the total accumulated change of ff from aa to xx.

The accumulation function serves as a record of the net area between the rate curve and the horizontal axis from the starting value aa to the point xx, and its behavior depends entirely on the sign and magnitude of f(t).

The accumulation function serves as a record of the net area between the rate curve and the horizontal axis from the starting value aa to the point xx, and its behavior depends entirely on the sign and magnitude of f(t).

How f Determines Whether g is Increasing or Decreasing

Because accumulation functions are built from integrals, their behavior is governed by a fundamental relationship between derivatives and integrals.

g(x)=f(x) g'(x) = f(x)
g(x) g'(x) = Instantaneous rate of change of the accumulation function
f(x) f(x) = Given rate function whose values dictate growth or decline

A sentence is required between adjacent blocks. The sign of f provides a direct and intuitive guide to understanding the overall shape of g.

Key Relationships Between f and the Behavior of g

  • g is increasing when f(x) > 0

    • Positive values of f accumulate positive signed area, making g(x) rise.

  • g is decreasing when f(x) < 0

    • Negative values accumulate negative signed area, causing g(x) to fall.

  • g has a horizontal tangent where f(x) = 0

    • When f(x) equals zero, the rate of change of g is zero, marking a potential maximum, minimum, or point of inflection for g depending on sign changes of f.

These relationships allow one to examine a graph of f and accurately predict changes in g without ever computing the integral explicitly.

Identifying Key Features of g from f

The accumulation function’s graph can be analyzed using information from f. Because g reflects the running total of signed area, several graphical and conceptual cues from f reveal important features in g.

Features of g Derived from f

  • Local maxima of g occur when f changes from positive to negative.

  • Local minima of g occur when f changes from negative to positive.

  • Points of inflection of g correspond to points where f has local extrema, since these indicate where the rate of accumulation is changing most rapidly.

  • Steepness of g's graph is determined by the magnitude of f(x):

    • Larger absolute values of f(x) produce steeper slopes in g.

    • Smaller absolute values of f(x) produce flatter regions in g.

Each of these relationships follows directly from the fact that the accumulation function is the antiderivative of f.

Interpreting Signed Area to Understand g

Because g(x) represents accumulated area from aa to xx, the notion of signed area is essential.

A graph of f(x)f(x) with regions above and below the x-axis shaded demonstrates how positive and negative contributions form the signed area in g(x)=axf(t),dtg(x)=\int_a^x f(t),dt. Extra labeled values exceed syllabus requirements but remain consistent with the concept. Source.

Because g(x) represents accumulated area from aa to xx, the notion of signed area is essential. Positive area above the x-axis increases the value of g, while negative area below the x-axis decreases it. This creates a smooth, intuitive geometric interpretation that complements the derivative-based view.

How Signed Area Contributes to g

  • When f(t) is above the axis, the accumulated area increases, and g(x) rises.

  • When f(t) is below the axis, accumulated area becomes more negative, causing g(x) to fall.

  • Where f crosses the axis, g transitions between rising and falling.

  • The total accumulated area up to a point tells how far g(x) has moved from its initial value g(a) = 0.

This geometric perspective reinforces that g is not merely a function defined by a formula but a function representing real accumulated change.

A smooth curve with its entire subgraph shaded highlights how accumulated area visually represents g(x)=axf(t),dtg(x)=\int_a^x f(t),dt. Interval specifics in the figure exceed syllabus needs but accurately illustrate the concept. Source.

This geometric perspective reinforces that g is not merely a function defined by a formula but a function representing real accumulated change.

Describing g Using Only Information About f

Often, in AP Calculus AB, f is given graphically or verbally. Students must be able to analyze g using only the observable behavior of f. The focus is always on how g behaves, not on computing its exact values.

Strategies for Interpreting g from a Graph of f

  • Look for intervals where f is above or below the axis.

  • Identify zeros of f, which signal turning points in g.

  • Compare relative heights of f to estimate where g increases more quickly.

  • Notice peaks and valleys in f, which indicate shifts in the curvature of g.

  • Track the cumulative effect of positive and negative area to understand how far g has moved from its starting point.

These strategies allow a full qualitative sketch and verbal description of g solely by observing features of f, aligning precisely with the syllabus requirement for this subsubtopic.

FAQ

You can judge steepness by comparing the heights of f at different x-values. A taller value of f means a larger instantaneous rate of change of g.

If f is close to zero, g will flatten out even if the sign of f remains positive or negative. Very small values of f therefore indicate slow accumulation.

If f equals zero on an entire interval, then g does not increase or decrease there. It remains constant.

This happens because g records the accumulated change, and a rate of zero produces no further accumulation.

Yes. Concavity in g depends on how f itself changes, not on its sign.

If f has a turning point (a local maximum or minimum), then the rate at which g increases or decreases shifts, creating a change in concavity.

Look for a pattern where f starts large but gradually decreases toward zero. In such cases:
• g will initially rise quickly because f is large.
• As f decreases, g will continue rising but more slowly.
• If f reaches zero, g levels off completely.

This reflects diminishing rates of accumulation over time.

An oscillating f causes g to rise and fall depending on the sign of f, but the overall trend depends on the balance of positive and negative areas.

If the positive portions of f have greater total area, g will drift upward over the interval; if the negative portions dominate, g will drift downward.

Practice Questions

Question 1 (1–3 marks)
The graph of a continuous function f is shown. The function g is defined by
g(x) = ∫ from 0 to x of f(t) dt.
At x = 4, the graph of f crosses the x-axis from above to below.
(a) State whether g has a local maximum, a local minimum, or neither at x = 4. Give a reason.

Question 1
(a)
• 1 mark for stating “g has a local maximum at x = 4”.
• 1 mark for identifying that f changes from positive to negative at x = 4.
• 1 mark for linking this to g’(4) = f(4), so the sign change in f determines the turning point of g.

Question 2 (4–6 marks)
A function g is defined by
g(x) = ∫ from 2 to x of f(t) dt,
where the graph of f is shown. On the interval 2 ≤ x ≤ 10, the function f satisfies the following:
• f is positive on 2 ≤ x < 5
• f(5) = 0
• f is negative on 5 < x ≤ 8
• f(8) = 0
• f is increasing on 2 ≤ x ≤ 4 and decreasing on 4 ≤ x ≤ 7

(a) Determine the open intervals where g is increasing and where it is decreasing.
(b) Explain why g has a point of inflection at x = 4.
(c) Determine whether g has a local maximum, local minimum, or neither at x = 5. Give a reason.

Question 2
(a)
• 1 mark for identifying g is increasing where f is positive: 2 < x < 5.
• 1 mark for identifying g is decreasing where f is negative: 5 < x < 8.

(b)
• 1 mark for stating that g has a point of inflection at x = 4.
• 1 mark for explaining that this is because f has a local maximum or minimum at x = 4, meaning g’ changes its rate of increase/decrease.
• 1 mark for recognising that the change in the behaviour of f indicates a change in the concavity of g.

(c)
• 1 mark for stating that g has a local maximum at x = 5.
• 1 mark for explaining that f changes sign from positive to negative at x = 5, causing g to change from increasing to decreasing.

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