AP Syllabus focus:
‘A critical point of a function occurs where the first derivative equals zero or does not exist, provided the x-value is in the domain of the original function.’
Critical points are essential in AP Calculus AB because they signal where a function’s behavior may change, allowing us to investigate possible maxima, minima, or flat regions in its graph.
Understanding the Meaning of Critical Points
A critical point is a location on the graph of a differentiable or piecewise-defined function where meaningful changes in behavior may occur. In calculus, these points help determine where a function may have local extrema, places where the function reaches a relative highest or lowest value. The AP specification emphasizes that critical points rely solely on information from the first derivative, because the derivative captures instantaneous rates of change along the graph.
Critical Point: An -value in the domain of a function where the derivative equals zero or the derivative does not exist.
A function must be defined at the point in question, meaning the -value must lie within the domain of the original function. If the function does not exist at an -value, that point cannot be considered a critical point even if the derivative has unusual behavior there.
Why Derivatives Identify Critical Points
The derivative measures the instantaneous rate of change of a function. When the derivative equals zero, the tangent line is horizontal. This situation is frequently—though not always—associated with local extrema. Conversely, when the derivative does not exist but the function remains defined, the graph often exhibits sharp corners, cusps, or vertical tangents. Each of these features marks a point where the behavior of the function could shift significantly.
Between intervals where the derivative is positive or negative, changes in sign must occur at critical points. Therefore, identifying such points is the foundation for analyzing increasing and decreasing behavior, curvature, and extremal values.
Formal Conditions for Identifying Critical Points
To determine whether an -value qualifies as a critical point, two essential conditions guide the process:
The function must be defined at the point.
The first derivative must either
equal zero, or
fail to exist at that point.
These requirements ensure that critical points are tied to actual, meaningful features of the graph.
A common misconception is that any point where the derivative does not exist automatically becomes a critical point. However, if the function itself is not defined there—such as at a discontinuity or a vertical asymptote—the point cannot be critical because it fails the domain requirement.
Types of Situations That Produce Critical Points
Critical points arise from several structural characteristics of a function. Understanding these situations helps students recognize critical points more efficiently.
1. Horizontal Tangents
Horizontal tangents occur when .
Key features include:
Flat regions on the graph
Turning points where direction may shift
Plateaus where the slope temporarily becomes zero
Horizontal tangents are common sources of local maxima or minima, though not guaranteed indicators.

This graph shows a function with several local and global extrema, each occurring at a point where the tangent line is horizontal. It illustrates how a zero derivative may correspond to a maximum or minimum. The specific function includes more complexity than required in AP Calculus AB, serving only as a concrete visual example. Source.
2. Nondifferentiable Points
A derivative may fail to exist even when the function is defined. These points often correspond to distinct geometric features.
Common nondifferentiable cases include:
Cusps, where the graph sharply changes direction
Corners, where one‐sided derivatives do not match
Vertical tangents, where the slope grows without bound
In all these situations, the derivative is undefined, yet the function’s defined nature at the point qualifies the location as a critical point.

This diagram illustrates a cusp where the function is continuous and defined, yet the derivative fails to exist because the slopes from each side differ infinitely. Such points are nondifferentiable but still qualify as critical points. The image includes more detail than required, such as extended graph arrows, but the cusp feature is the key concept relevant to the syllabus. Source.
3. Points Involving Piecewise Functions
Piecewise functions require special attention. Even if each piece is differentiable on its own interval, the junctions may cause nondifferentiability. When evaluating such points, ensure:
The pieces meet at the domain boundary
The function is defined at the junction
The derivative from each side either disagrees or one side fails to exist
If these conditions hold, the point becomes a critical point, making piecewise-defined functions a rich source of nondifferentiable behavior.
How Critical Points Fit into Broader Function Analysis
Identifying critical points is the first analytical step that precedes later techniques in calculus. These points serve as anchors for deeper investigations because they often signal meaningful transitions in a function’s graph.
After locating critical points, students use them to:
Construct sign charts for the first derivative
Determine intervals of increase or decrease
Apply the First Derivative Test for classifying local extrema
Connect behavior in , , and
Implement optimization methods in applied contexts
Critical points do not guarantee extremal values, but no local maxima or minima can occur without one. Thus, finding critical points isolates the limited set of candidates where more sophisticated tests can be applied.
Clarifying What Critical Points Are Not
To avoid common errors, it is important to distinguish true critical points from other noteworthy features.
Discontinuities are never critical points because the function is not defined there.
Endpoints of a closed interval are not considered critical points, even though they may produce extrema; they simply lie outside the derivative-based definition.
Zeros of the function (where ) are irrelevant unless accompanied by derivative conditions; they do not inherently indicate slope behavior.
Understanding these distinctions ensures that students use precise mathematical reasoning and remain aligned with the AP standard that emphasizes domain-based evaluation when determining critical points.
FAQ
A point must lie in the domain because critical points indicate potential changes in the behaviour of the function itself. If the function is not defined at the point, there is no value of the function to analyse.
This ensures that critical points correspond to genuine features of the graph, not gaps, asymptotes or undefined behaviours.
Yes, some functions have infinitely many critical points, particularly oscillatory functions. This occurs when the derivative equals zero at a repeating pattern of points.
Examples include functions with repeating peaks and troughs, provided the function remains defined and smooth enough for these features to occur endlessly.
Yes. If the derivative exists and is non-zero, the function is changing at a non-zero rate, which rules out any flat or nondifferentiable behaviour.
Such points cannot be critical because they do not satisfy either condition: derivative equal to zero or derivative undefined.
Vertical tangents occur where the graph rises or falls infinitely steeply, causing the derivative to fail to exist while the function remains defined.
These are valid critical points if the function is defined at the tangent location because the derivative’s non-existence is one of the qualifying criteria.
A nondifferentiable point is a critical point only if the function is defined there. If the function has a discontinuity or hole at that location, the point cannot be considered critical.
To decide, check:
• Is the function defined at the point?
• Does the derivative fail to exist?
Only when both conditions are satisfied does the nondifferentiable point become a critical point.
Practice Questions
Question 1 (1–3 marks)
The function g is defined for all real numbers. At x = 2, the function is continuous and g(2) exists, but the derivative g'(2) does not exist because the graph has a sharp corner at this point.
Explain why x = 2 is a critical point of g.
Question 1
• 1 mark: States that a critical point occurs where the derivative is zero or does not exist.
• 1 mark: States that g'(2) does not exist.
• 1 mark: States that g(2) is defined, so x = 2 meets the definition of a critical point.
Question 2 (4–6 marks)
The function f is defined on the interval [−3, 5]. The derivative f' is given for certain values in the table below:
x: −2 −1 0 1 3
f'(x): 4 1 0 DNE −2
(a) Identify all x-values in the table that are critical points of f.
(b) For each critical point, explain which definition of a critical point applies.
(c) State one further check that must be made before identifying any of these critical points as locations of a local maximum or minimum.
Question 2
(a) Identifying critical points (2 marks)
• 1 mark: Identifies x = 0 as a critical point because f'(0) = 0.
• 1 mark: Identifies x = 1 as a critical point because f'(1) does not exist.
(b) Explaining which definition applies (2 marks)
• 1 mark: States that at x = 0, the derivative equals zero, so it is a critical point.
• 1 mark: States that at x = 1, the derivative does not exist while f is defined, so it is a critical point.
(c) Additional check (2 marks)
• 1 mark: States that one must check the sign of f' on either side of the critical point, or evaluate the behaviour of the function nearby.
• 1 mark: Recognises that without such a check, one cannot determine whether a critical point corresponds to a local extremum.
