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AP Calculus AB study notes

8.12.2 Washer Integrals for Horizontal or Vertical Lines

AP Syllabus focus:
‘Students express inner and outer radii as differences between functions and the axis of revolution, then integrate π[(outer)² − (inner)²] with respect to x or y.’

Washer integrals for horizontal or vertical lines allow volumes of solids of revolution to be computed by measuring changing radii relative to shifted axes using definite integrals.

Washer Integrals for Horizontal or Vertical Lines

A washer-based volume arises when a region is revolved around a horizontal or vertical line, producing a solid with a hollow center. This hollow center creates a ring-shaped cross section whose area must be computed by comparing an outer radius to an inner radius. Because these radii depend on the distance from the region’s bounding curves to the chosen line of revolution, setting up the correct expressions is essential for accurate volume calculations. In this subsubtopic, the AP Calculus AB focus is on expressing these radii as differences between functions and the axis of revolution, then writing the corresponding integral using the washer formula.

Understanding Horizontal and Vertical Lines of Revolution

When revolving a region around a horizontal line such as y=ky = k, the radii measure vertical distances between the curve(s) and the axis. When revolving around a vertical line such as x=cx = c, the radii measure horizontal distances. The orientation determines whether the integral must be written with respect to xx or yy, based on how the radius naturally varies across the region.

Key Idea: Measuring Distance to the Axis

The radius of revolution is always defined as a nonnegative distance from a curve to the axis being used. Distances depend on whether the curve lies above or below a horizontal axis or to the right or left of a vertical axis.

Radius of Revolution: The nonnegative distance from a bounding curve of the region to the line around which the region is revolved.

A sentence between blocks is needed, so here it is to maintain proper spacing and explanation before introducing the equation.

V=π[(outer radius)2(inner radius)2],dx or dy V = \int \pi[(\text{outer radius})^{2} - (\text{inner radius})^{2}],dx\ \text{or}\ dy
outer radius \text{outer radius} = distance from farther curve to the axis of revolution
inner radius \text{inner radius} = distance from nearer curve to the axis of revolution

The integral sums the volumes of these infinitesimally thin washers to give the total volume of the solid of revolution.

Pasted image

A planar region is sliced by a thin rectangle perpendicular to a horizontal axis of revolution. When the slice is revolved, it generates a washer-shaped cross-section whose outer and inner edges track the bounding curves. This image emphasizes how a continuous family of such washers accumulates to form the full solid. Source.

Determining Whether to Integrate with Respect to x or y

Choosing the correct variable prevents unnecessary complications and ensures the washer method is applied efficiently. The selection depends on the orientation of the axis:

  • Revolving around a horizontal line (y=ky = k)

    • Radii are vertical distances.

    • Use integration with respect to xx, provided the curves are functions of xx.

  • Revolving around a vertical line (x=cx = c)

    • Radii are horizontal distances.

    • Use integration with respect to yy, provided the curves are functions of yy.

If the region has boundaries more naturally expressed in the opposite orientation, re-expressing the curves may simplify the radii expressions.

Constructing the Outer and Inner Radii

The washer method always requires identifying two distances:

  • Outer radius: distance from the most distant bounding curve to the axis

  • Inner radius: distance from the closest bounding curve to the axis

These distances must always remain nonnegative and must correctly reflect which curve is farther or nearer across the entire interval.

When the Axis Is Horizontal (y=ky = k)

To compute radii:

  • Outer radius:

    • If the upper curve is y=f(x)y = f(x), then

      • distance = f(x)k|f(x) - k|.

  • Inner radius:

    • If the lower curve is y=g(x)y = g(x),then</p><ul><li><p>distance=, then</p><ul><li><p>distance = |g(x) - k|.</p></li></ul></li></ul></li></ul><p>Becausethegeometryusuallyensuresonecurvestaysabovetheotherontheinterval,theabsolutevaluemaybereplacedwithdirectsubtractioninthecorrectorder.Still,conceptualizingitasadistancehelpsstudentsavoiderrors.</p><p>Foraregionrotatedaroundahorizontalline.</p></li></ul></li></ul></li></ul><p>Because the geometry usually ensures one curve stays above the other on the interval, the absolute value may be replaced with direct subtraction in the correct order. Still, conceptualizing it as a distance helps students avoid errors.</p><p>For a region rotated around a horizontal line y=k,theouterradiusistheverticaldistancefrom, the outer radius is the vertical distance from y=ktothetopfunctionandtheinnerradiusisthedistancetothebottomfunction.</p><imgsrc="https://tutorchaseproduction.s3.euwest2.amazonaws.com/0a47abb2efb049c7b5cba0d4a3f780e6file.png"alt="Pastedimage"style="maxwidth:100 to the top function and the inner radius is the distance to the bottom function.</p><img src="https://tutorchase-production.s3.eu-west-2.amazonaws.com/0a47abb2-efb0-49c7-b5cb-a0d4a3f780e6-file.png" alt="Pasted image" style="max-width: 100%; height: auto; cursor: pointer;" draggable="true"><p><em>The left panel shows a region bounded by y=4−xy = 4 - xy=4−x, the xxx-axis, and the interval in xxx, together with the horizontal line y=−2y = -2y=−2. The right panel shows the solid produced when this region is revolved about y=−2y=-2y=−2, creating washers whose radii are measured up to the graph and down to the axis. This figure highlights how shifting the axis from the xxx-axis to y=−2y = -2y=−2 changes the radii used in the washer integral. </em><a target="_blank" rel="noopener noreferrer nofollow" href="https://courses.lumenlearning.com/calculus1/chapter/disk-and-washer-methods/"><em>Source.</em></a></p><h3 class="editor-heading"><strong>When the Axis Is Vertical (x = c)</strong></h3><p>Tocomputeradii:</p><ul><li><p><strong>Outerradius:</strong></p><ul><li><p>Iftherightmostcurveis)</strong></h3><p>To compute radii:</p><ul><li><p><strong>Outer radius:</strong></p><ul><li><p>If the rightmost curve is x = f(y),then</p><ul><li><p>distance=, then</p><ul><li><p>distance = |f(y) - c|.</p></li></ul></li></ul></li><li><p><strong>Innerradius:</strong></p><ul><li><p>Iftheleftmostcurveis.</p></li></ul></li></ul></li><li><p><strong>Inner radius:</strong></p><ul><li><p>If the leftmost curve is x = g(y),then</p><ul><li><p>distance=, then</p><ul><li><p>distance = |g(y) - c|.</p></li></ul></li></ul></li></ul><p>Workingwithfunctionsof.</p></li></ul></li></ul></li></ul><p>Working with functions of yoftenprovidesasimplersetupinverticalaxisproblems,especiallywhentheregionhastopandbottomboundariesthataredifficulttoexpressintermsof often provides a simpler setup in vertical-axis problems, especially when the region has top and bottom boundaries that are difficult to express in terms of x.</p><h2class="editorheading"id="structuralstepsforsettingupwasherintegrals"><strong>StructuralStepsforSettingUpWasherIntegrals</strong></h2><p>Studentsbenefitfromaclearprocedurethatorganizesthegeometryandalgebrainvolved.Thesyllabusemphasizesinterpretinggraphsandexpressingradiiusingcorrectdistanceformulas.</p><h3class="editorheading"><strong>ProcessforAnyWasherMethodProblem</strong></h3><ul><li><p><strong>Identifythelineofrevolution.</strong></p><ul><li><p>Determinewhetheritishorizontalorvertical.</p></li></ul></li><li><p><strong>Labeltheouterandinnercurves.</strong></p><ul><li><p>Decidewhichcurveisfartherfromtheaxisoneachslice.</p></li></ul></li><li><p><strong>Expressradiiasdistances.</strong></p><ul><li><p>Useabsolutedifferencebetweenfunctionandaxisuntilthecorrectorderisconfirmed.</p></li></ul></li><li><p><strong>Determinethevariableofintegration.</strong></p><ul><li><p>Matchverticalslicesto.</p><h2 class="editor-heading" id="structural-steps-for-setting-up-washer-integrals"><strong>Structural Steps for Setting Up Washer Integrals</strong></h2><p>Students benefit from a clear procedure that organizes the geometry and algebra involved. The syllabus emphasizes interpreting graphs and expressing radii using correct distance formulas.</p><h3 class="editor-heading"><strong>Process for Any Washer Method Problem</strong></h3><ul><li><p><strong>Identify the line of revolution.</strong></p><ul><li><p>Determine whether it is horizontal or vertical.</p></li></ul></li><li><p><strong>Label the outer and inner curves.</strong></p><ul><li><p>Decide which curve is farther from the axis on each slice.</p></li></ul></li><li><p><strong>Express radii as distances.</strong></p><ul><li><p>Use absolute difference between function and axis until the correct order is confirmed.</p></li></ul></li><li><p><strong>Determine the variable of integration.</strong></p><ul><li><p>Match vertical slices to xintegrationandhorizontalslicesto-integration and horizontal slices to yintegration.</p></li></ul></li><li><p><strong>Writethewasherintegral.</strong></p><ul><li><p>Use-integration.</p></li></ul></li><li><p><strong>Write the washer integral.</strong></p><ul><li><p>Use \pi[(\text{outer radius})^{2} - (\text{inner radius})^{2}]$ with appropriate limits.

  • Ensure radii remain nonnegative over the entire interval.

Visual Reasoning with Axes of Revolution

Conceptualizing the geometry strengthens understanding. A horizontal line of revolution produces washers stacked left to right, while a vertical line of revolution produces washers stacked bottom to top. Because the shape of each washer depends on distance to the axis, graph inspection and boundary verification prevent sign errors in radius expressions.

FAQ

The correct choice depends on which boundary lies farther from the axis of revolution at each point in the domain. A constant boundary such as a horizontal or vertical line can act as either the inner or outer boundary, depending on its position relative to the curve.

Check the geometry across the entire interval. If the curve crosses or approaches the axis at any point, the role of the radii may switch, requiring a split into sub-intervals.

A shifted axis creates a hollow space, because the region no longer touches the axis of revolution. This gap produces an inner radius greater than zero, which prevents the region from forming a solid disc.

The washer method accounts for this gap by subtracting the volume removed by the inner radius from the volume generated by the outer radius.

Students often incorrectly subtract in the wrong order, producing negative radii. Distances must always be non-negative.

Another frequent mistake is mixing up whether distances should be taken vertically or horizontally. Always use vertical distances for horizontal axes and horizontal distances for vertical axes.

Sketching the region and axis before writing expressions reduces these errors significantly.

If the washer radii vary in the direction perpendicular to the slices, switching the variable often creates simpler expressions.

For example:
• A vertical line of revolution usually favours integration with respect to y.
• A horizontal line of revolution usually favours integration with respect to x.

If the functions are difficult to rearrange into the needed form, sticking with the original variable may be more efficient.

Confirm that the same curve remains consistently farther from the axis than the other boundary across the interval. If this relationship changes, the region no longer forms a simple washer on that interval.

Check for:
• Intersection points between curves
• Points where a curve approaches or crosses the axis of revolution
• Regions where the inner radius might become zero or negative

These features indicate the need to split the integral for accuracy.

Practice Questions

Question 1 (1–3 marks)
A region in the xy-plane is bounded above by the line y = 5, below by the curve y = x, and between x = 0 and x = 4. The region is revolved about the horizontal line y = 1.

(a) State an expression for the outer radius in terms of x.
(b) State an expression for the inner radius in terms of x.
(c) Write, but do not evaluate, a definite integral representing the volume of the resulting solid using the washer method.

Question 1

(a)
• Outer radius correctly stated as distance from y = 5 to y = 1, giving radius = 5 − 1 = 4, or written as a constant 4.
(1 mark)

(b)
• Inner radius correctly stated as distance from y = x to y = 1, giving radius = x − 1 or 1 − x depending on candidate’s convention, but must be non-negative for the interval.
(1 mark)

(c)
• Correct washer integral written: integral from x = 0 to x = 4 of pi[(outer radius) squared − (inner radius) squared] dx.
(1 mark)

Total: 3 marks

Question 2 (4–6 marks)
The region bounded by the curves x = y + 2 and x = 6, for 0 ≤ y ≤ 3, is revolved about the vertical line x = 0 to form a solid.

(a) Determine the outer radius as a function of y.
(b) Determine the inner radius as a function of y.
(c) Write a definite integral in terms of y that represents the volume of the solid.
(d) Explain briefly why integration with respect to y is the appropriate choice in this problem.

Question 2

(a)
• Outer radius correctly stated as distance from x = 6 to x = 0, giving radius = 6.
(1 mark)

(b)
• Inner radius correctly stated as distance from x = y + 2 to x = 0, giving radius = y + 2.
(1 mark)

(c)
• Correct washer integral written: integral from y = 0 to y = 3 of pi[(outer radius) squared − (inner radius) squared] dy.
(2 marks: 1 for structure, 1 for correct substitution of radii)

(d)
• Explanation identifies that radii vary horizontally and depend on y, so horizontal slices produce washers aligned with the axis of revolution.
(1–2 marks depending on clarity)

Total: 5–6 marks

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