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AP Physics 2: Algebra Notes

3.3.2 Geometry and Resistance

AP Syllabus focus: 'For a uniform resistor, resistance is proportional to resistivity and length and inversely proportional to cross-sectional area.'

The resistance of a resistor depends not only on its material, but also on its shape. In uniform resistors, geometry controls how far charge travels and how much space it has to move.

Geometry and Resistance

A uniform resistor has the same material throughout and the same cross-sectional area along its length.

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A uniform resistor can be modeled as a цилиндrical conductor of length LL and cross-sectional area AA made of a material with resistivity ρ\rho. The diagram visually encodes why RR increases with LL (longer path for charge) and decreases with AA (more space for charge flow), consistent with R=ρLAR=\dfrac{\rho L}{A}. Source

That uniformity allows one simple relationship to describe its resistance.

The material contribution is represented by resistivity.

Resistivity: A property of a material that indicates how strongly the material resists the motion of electric charge.

For a uniform resistor, resistance increases when charge must pass through more material in the direction of motion, and decreases when the resistor gives charge more room to flow through.

R=ρLA R=\dfrac{\rho L}{A}

R R = resistance, in ohms

ρ \rho = resistivity, in ohm-meters

L L = length of the resistor, in meters

A A = cross-sectional area, in square meters

This relationship applies only when the resistor is uniform. If the material or area changes from one place to another, the resistance cannot be found by using one single value of AA for the whole object.

How Geometry Changes Resistance

Length

The symbol LL represents the distance charge travels through the resistor. A longer resistor makes charge move through more material, so resistance is larger.

If resistivity and cross-sectional area stay constant, then:

  • doubling the length doubles the resistance

  • tripling the length triples the resistance

  • cutting the length in half cuts the resistance in half

This is why a long wire made of a given material resists charge flow more than a short wire made of the same material with the same thickness.

Cross-sectional Area

The cross-sectional area is the area of a slice taken perpendicular to the direction of current. In a wire, this is the area of its circular end. For a cylindrical wire, A=πr2A=\pi r^2.

A larger area means there is more space for charge to move through the material. Because of that, resistance decreases as area increases.

If resistivity and length stay constant, then:

  • doubling the area cuts the resistance to one-half

  • tripling the area cuts the resistance to one-third

  • making the area smaller raises the resistance

The inverse relationship is important. Resistance does not increase with area; it does the opposite.

Why Thickness Matters So Much

Students often describe a wire as “thicker” or “thinner.” In physics, that thickness is really about cross-sectional area, not just appearance. A small change in radius can cause a much larger change in area because area depends on the square of the radius.

For cylindrical wires:

  • a larger radius gives a much larger area

  • a much larger area gives a much smaller resistance

  • a thinner wire has significantly greater resistance even if the material and length are unchanged

This is why thin conductors can have high resistance, while thick metal cables can have much lower resistance.

The Role of Material

Geometry alone does not determine resistance. Two resistors with identical length and cross-sectional area can still have different resistances if they are made from different materials. That difference is captured by resistivity.

A material with a larger resistivity produces a larger resistance for the same geometry. A material with a smaller resistivity produces a smaller resistance for the same geometry.

When comparing uniform resistors, it helps to separate the effects:

  • resistivity tells you about the material

  • length tells you how far charge must travel

  • cross-sectional area tells you how much room charge has to move

Using Proportional Reasoning

Many AP Physics 2 questions on this topic can be answered without full numerical substitution. If the material stays the same, then RLR \propto L and R1AR \propto \dfrac{1}{A}.

That means you can compare two uniform resistors by looking at how their dimensions change:

  • longer means more resistance

  • wider means less resistance

  • same material means the comparison depends only on geometry

  • same geometry means the comparison depends only on resistivity

Proportional reasoning is especially useful when a problem asks for a factor change instead of a numerical resistance.

Common Misunderstandings

Area Is Not Length

Students sometimes confuse the length of the resistor with its size in every direction. Only the dimension along the path of charge motion is the length in the formula.

Cross-sectional Area Is Not Surface Area

The relevant area is the area charge moves through, not the outside area of the resistor. For a wire, the useful area is the area of the circular cross section.

Uniform Matters

The formula R=ρLAR=\dfrac{\rho L}{A} assumes one material and one cross-sectional area all along the resistor. If either changes from place to place, the simple form no longer describes the entire object directly.

FAQ

Diameter affects resistance through cross-sectional area, not directly.

For a cylindrical wire, $A=\pi r^2$, so if the diameter doubles, the radius also doubles. That makes the area four times larger, and since resistance is inversely proportional to area, the resistance becomes one-fourth as large.

Stretching increases the wire’s length, which tends to increase resistance.

At the same time, the wire usually becomes thinner, so its cross-sectional area decreases. Since both changes raise resistance, the total resistance increases by more than you would expect from the length change alone.

A tapered wire does not have one constant cross-sectional area from one end to the other.

That means there is no single value of $A$ that represents the whole wire accurately. In more advanced physics, the wire is treated as many tiny sections, each with its own area, and their resistances are combined.

Yes. If they are made of the same material, they can have the same resistance when the ratio $\dfrac{L}{A}$ is the same for both.

For example, a longer wire can match the resistance of a shorter wire if it also has a larger cross-sectional area in the right proportion.

For a uniform wire of one material and one thickness, resistance increases linearly with length.

That means every extra meter adds the same amount of resistance. Listing resistance per meter makes it easy to predict the resistance of any chosen length without recalculating from the full formula each time.

Practice Questions

A uniform metal wire is replaced by a wire of the same material and the same length, but with twice the cross-sectional area. How does the resistance change?

  • States that resistance is inversely proportional to area, or correctly uses R=ρLAR=\dfrac{\rho L}{A}. (1)

  • Concludes that the new resistance is one-half the original resistance. (1)

Wire A and Wire B are uniform cylindrical resistors made of the same material. Wire A has length LL and radius rr. Wire B has length 2L2L and radius r2\dfrac{r}{2}.

(a) Write the cross-sectional area of each wire in terms of rr.

(b) Determine the ratio RBRA\dfrac{R_B}{R_A}.

  • Gives AA=πr2A_A=\pi r^2. (1)

  • Gives AB=π(r2)2=πr24A_B=\pi \left(\dfrac{r}{2}\right)^2=\dfrac{\pi r^2}{4}. (1)

  • Uses R=ρLAR=\dfrac{\rho L}{A} or recognizes that, for the same material, RLAR \propto \dfrac{L}{A}. (1)

  • Correctly sets up the ratio using the changed length and area. (1)

  • Concludes that RBRA=8\dfrac{R_B}{R_A}=8. (1)

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