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AP Physics 2: Algebra Notes

4.2.3 Maximum Field Strength from Moving Charges

AP Syllabus focus: 'The magnetic field magnitude from a moving charged object is greatest when velocity and the position vector to the point are perpendicular.'

When a charge moves, the magnetic field it creates is not equally strong in all directions. This page focuses on the angle condition that makes that field reach its greatest possible value.

Angle Dependence of Field Strength

A moving charged object produces a magnetic field whose magnitude depends on where you measure it. For a fixed charge, speed, and distance from the charge, the remaining factor is geometry: the angle between the charge's velocity and the line from the charge to the observation point.

The position vector is the vector drawn from the moving charge to the point in space where the magnetic field is being evaluated.

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A moving point charge produces a magnetic field whose direction is set by a cross product, so B\vec B is perpendicular to the plane formed by v\vec v and r\vec r. The figure highlights the angle between v\vec v and the position vector, making it clear why the magnitude depends on sinθ\sin\theta and is maximized at 9090^\circ. Source

Position vector: A vector drawn from the moving charge to the location where the magnetic field is measured.

In this context, the key question is not whether a field exists, but where it is strongest.

Bqvsinθr2B \propto \dfrac{qv\sin\theta}{r^2}

BB = magnetic field magnitude, in tesla

qq = magnitude of the charge, in coulombs

vv = speed of the charge, in meters per second

rr = distance from the charge to the point, in meters

θ\theta = angle between vv and the position vector

The factor that determines the maximum is sinθ\sin\theta. Since 0sinθ10 \le \sin\theta \le 1, the largest possible value occurs when sinθ=1\sin\theta = 1, which happens at 9090^\circ. Therefore, when the velocity and position vector are perpendicular, the magnetic field magnitude is greatest.

If the position vector is parallel or antiparallel to the velocity, then θ=0\theta = 0^\circ or 180180^\circ. In either case, sinθ=0\sin\theta = 0, so the magnetic field magnitude is zero at that point for this model.

At intermediate angles, the field is nonzero but smaller than the maximum. Angles such as 3030^\circ, 4545^\circ, and 6060^\circ give progressively larger values as the angle approaches 9090^\circ.

Why Perpendicular Gives the Maximum

The Role of the Perpendicular Component

Only the part of the charge's motion that is perpendicular to the line toward the observation point contributes to the magnetic field magnitude.

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This right-hand-rule figure emphasizes that only the component of motion perpendicular to the other vector contributes, which is why the dependence involves sinθ\sin\theta rather than the full speed. It reinforces the key comparison logic: the effect is largest at θ=90\theta=90^\circ and vanishes when the vectors are parallel or antiparallel. Source

This is why the expression contains vsinθv\sin\theta rather than just vv.

When the velocity is fully perpendicular to the position vector, the entire speed contributes to the field magnitude. None of the motion is in the parallel direction. That produces the largest possible magnetic field at that distance.

When the velocity is partly aligned with the position vector, only a fraction of the speed contributes. The closer the motion is to being parallel with the line to the point, the smaller the magnetic field becomes.

Geometric Interpretation

Where the Strongest Field Is Found

Imagine a charge moving in a straight line. Points located directly to the side of the charge's motion correspond to θ=90\theta = 90^\circ. Those points lie in a plane that is perpendicular to the velocity of the charge and passes through the charge.

For points in that perpendicular plane, the magnetic field magnitude is as large as it can be for that particular charge speed and distance. Points tilted away from that plane have smaller magnitudes because the angle is no longer 9090^\circ.

This also means the strongest field is not concentrated in front of the charge or behind it. Along the line of motion, the position vector and velocity are parallel or antiparallel, so the angle factor makes the field vanish.

Another useful geometric fact is symmetry. Angles θ\theta and 180θ180^\circ - \theta give the same magnetic field magnitude because they have the same sine value. So points at equal distance on opposite sides of the perpendicular plane can produce equal magnitudes even though they are located differently in space.

What to Recognize on AP Physics 2 Algebra Questions

Key Comparisons

On conceptual questions, you should first check whether the compared points are at the same distance from the moving charge. If they are, then the angle alone determines which point has the larger magnetic field magnitude.

Look for these ideas:

  • Maximum field occurs at θ=90\theta = 90^\circ.

  • Zero field magnitude occurs at θ=0\theta = 0^\circ or 180180^\circ.

  • Equal magnitudes can occur for supplementary angles because sinθ=sin(180θ)\sin\theta = \sin(180^\circ - \theta).

  • A larger angle does not always mean a larger field; the comparison depends on the sine of the angle, not the angle value by itself.

Common Reasoning Errors

A common mistake is to treat the magnetic field as if it were equally strong in every direction around a moving charge. It is not. The strength depends on the angle to the observation point.

Another common mistake is to say the field is greatest whenever the point is "far to the side" without checking what perpendicular means. The correct condition is precise: the velocity vector and the position vector must be at right angles.

It is also important to interpret the phrase greatest magnetic field magnitude correctly. It means the maximum value for a fixed charge, fixed speed, and fixed distance from the charge. The angle determines where that maximum occurs, while the perpendicular condition tells you which geometry gives the strongest field.

FAQ

No. The angle for maximum magnitude stays the same: the velocity and position vector must be at $90^\circ$.

The sign of the charge changes the direction of the magnetic field, not the angle that makes its magnitude largest. So a positive charge and a negative charge reach maximum magnitude under the same geometric condition.

The field gets stronger in direct proportion to the speed, as long as the geometry remains the same.

If the speed doubles, the maximum magnetic field magnitude doubles. If the speed is cut in half, the maximum magnetic field magnitude is cut in half. The angle condition chooses the maximum geometry, while the speed sets how large that maximum actually is.

No. The angle is a physical relationship between two vectors, not a feature of the axes you draw.

You can rotate or relabel your coordinate system and still get the same result. If the velocity vector and position vector are perpendicular in one coordinate system, they are perpendicular in every coordinate system.

Usually not. Near $90^\circ$, the sine function is still very close to 1.

For example, $\sin 85^\circ$ and $\sin 95^\circ$ are both close to the maximum possible value. That means small misalignments from perfect perpendicularity usually reduce the magnetic field only slightly, not dramatically.

The maximum-field region changes with the charge's instantaneous velocity.

At each moment, the strongest magnetic field occurs at points whose position vectors are perpendicular to the current direction of motion. If the path curves, the plane of maximum field rotates as the velocity direction changes.

Practice Questions

A charged particle moves with constant speed. At point P, the angle between the particle's velocity and the position vector to P is 9090^\circ. At point Q, the angle is 3030^\circ. The two points are the same distance from the particle.

Which point has the greater magnetic field magnitude? Explain.

  • 1 mark: States that point P has the greater magnetic field magnitude.

  • 1 mark: Explains that the magnetic field magnitude depends on sinθ\sin\theta and is greatest when θ=90\theta = 90^\circ.

A moving charged object is observed from four points, all at the same distance from the charge. The angle between the object's velocity and the position vector to each point is:

A: 00^\circ
B: 4545^\circ
C: 9090^\circ
D: 135135^\circ

(a) Rank the magnetic field magnitudes at A, B, C, and D from greatest to least. (2 marks)
(b) Identify the point where the magnetic field magnitude is maximum. (1 mark)
(c) Explain why the magnitudes at B and D are equal. (1 mark)
(d) State the magnetic field magnitude at A relative to the others and justify your answer. (1 mark)

  • 2 marks: Correct ranking C>B=D>AC > B = D > A

    • 1 mark for placing C greatest and A least

    • 1 mark for stating B=DB = D

  • 1 mark: Identifies C as the maximum.

  • 1 mark: Explains that BB and DD are equal because sin45=sin135\sin 45^\circ = \sin 135^\circ.

  • 1 mark: States that A has zero magnetic field magnitude because θ=0\theta = 0^\circ and therefore sin0=0\sin 0^\circ = 0.

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