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AP Physics 2: Algebra Notes

5.2.6 Plane Mirrors and Image Distance

AP Syllabus focus: 'For a plane mirror, the image distance behind the mirror equals the object distance in front of the mirror.'

Plane mirrors produce images in a highly predictable way. For this subsubtopic, the essential idea is simple: the image appears the same perpendicular distance behind the mirror as the object is in front.

Plane Mirrors and Image Position

A plane mirror is the simplest mirror used in geometric optics. Because its surface is flat, it does not bring light rays together or spread them apart in a way that changes image position from point to point. Instead, each point on an object has a corresponding image point located symmetrically across the mirror surface.

Plane mirror: A flat reflecting surface that produces an image at an apparent position behind the mirror.

When you look into a plane mirror, light from the object reflects from the mirror and then enters your eyes. Your brain interprets those reflected rays as if they came from a point behind the mirror. That apparent point is where the image is located.

Object distance and image distance: The perpendicular distances from the mirror surface to the object and to the apparent image position.

These distances are measured from the mirror itself, not from the observer and not along a slanted line of sight. That measurement choice is what makes the plane-mirror relationship precise and consistent.

Plane Mirror Distance Relation=di=doPlane\ Mirror\ Distance\ Relation=d_i=d_o

did_i = image distance behind the mirror, m

dod_o = object distance in front of the mirror, m

What Equal Distances Means

The phrase equal distances means the image is located at a point directly opposite the object, with the mirror surface exactly halfway between them. If the object is moved farther from the mirror, the image shifts farther behind it by the same amount.

This is a statement about position, not about a physical object existing behind the mirror. No light source is actually located there. Instead, the reflected light behaves as though it came from that point. For image-location questions, that apparent position is treated as the image.

The equality also applies point by point. If different parts of an object are at different distances from the mirror, each part has its own corresponding image point the same distance behind the mirror as that part is in front.

How the Geometry Works

The mirror acts like a line of symmetry. Imagine a line drawn perpendicular to the mirror through the object. The image lies on that same line, on the opposite side of the mirror.

Pasted image

Symmetry diagram for a plane mirror: the object and its virtual image are placed on opposite sides of the mirror along a line normal to the surface. The labeled distances dod_o (object distance) and did_i (image distance) illustrate that the mirror is the midpoint, so the image is the same perpendicular distance behind the mirror as the object is in front. Source

The mirror surface is the midpoint between the object and the image.

This symmetry is why plane-mirror images have such a predictable location. All reflected rays that reach an observer can be traced backward, and those backward extensions meet at the same apparent point behind the mirror.

Pasted image

Ray-tracing for a plane mirror: several rays from a single object point reflect off the mirror and then can be extended backward to a single intersection point. That intersection represents the virtual image location because the real light does not pass through it, but the reflected rays appear to originate there when traced backward. Source

Because that point is symmetric to the object across the mirror surface, the image distance must match the object distance.

A helpful way to think about this is that the mirror “copies” the object position across its surface. The copy is not in front of the mirror, where the light reflects, but behind it, at the same perpendicular depth.

Measuring Distance Correctly

For AP Physics 2, one of the most important skills is measuring the distance in the correct way.

The distance is measured:

  • from the mirror surface

  • along a line perpendicular to the mirror

  • to the object or to the image position

It is not measured:

  • from your eye to the mirror

  • along the path a particular ray travels

  • diagonally across space unless that diagonal happens to be perpendicular to the mirror

Because of this, an observer can move left or right and still assign the same image distance. The observer’s position may change which reflected rays enter the eye, but it does not change where the image is located relative to the mirror.

Using the Relationship in Problems

When solving a problem involving a plane mirror and image distance, keep the geometry simple:

  • Identify the reflecting surface of the mirror.

  • Find the object’s perpendicular distance in front of that surface.

  • Place the image the same perpendicular distance behind the surface.

  • If asked for the separation between the object and image, add the two equal distances.

This last idea is important. Since the mirror lies halfway between the object and its image, the total object-image separation is twice the object distance from the mirror. That result follows directly from the equal-distance relationship.

If the object moves closer by some distance, the image moves closer by the same distance. If the object moves farther away, the image moves farther away by the same amount. The mirror does not change the rule.

Common Errors to Avoid

Students often lose points on plane-mirror questions because of a few repeated mistakes:

  • placing the image on the mirror surface instead of behind it

  • measuring the distance from the observer instead of from the mirror

  • using a slanted distance instead of the perpendicular distance

  • forgetting that the image position changes whenever the object position changes

  • assuming the image distance depends on which side the observer stands on

The safest approach is to focus on symmetry. Find the object’s distance from the mirror, then reflect that position across the mirror surface. That reflected position gives the image distance directly.

FAQ

Your eyes respond to the directions of incoming light rays, not to the actual location of a physical object.

In a plane mirror, the reflected rays reaching your eyes diverge as if they came from a point behind the mirror. Your eye lens focuses those rays onto the retina as though a source were located at that apparent distance.

The ideal rule assumes the reflection happens exactly at the mirror surface.

In many household mirrors, the reflective coating is slightly behind the front glass. That can shift the apparent image position by a very small amount and sometimes produce a faint secondary reflection. For most AP Physics problems, the mirror is treated as ideal, so the equal-distance rule is exact.

If a plane mirror shifts by a distance $x$ while the object stays fixed, the image position in the room shifts by $2x$.

One change comes from the new mirror location, and the second comes from placing the image the same distance behind the new mirror surface. This is why a small mirror motion can make the image appear to move twice as much.

A plane mirror does not literally swap left and right. It reverses the front-back direction relative to the mirror surface.

When you imagine turning yourself around to match the image, your left and right seem exchanged. The distance rule still holds at the same time; the apparent reversal and the image location come from different geometric ideas.

A faint double image can happen when light reflects from both the front glass surface and the deeper reflective coating.

The stronger reflection usually comes from the coated surface, while the weaker one comes from the front glass. Because those reflections occur at slightly different depths, the two apparent image positions are slightly separated. Front-surface mirrors reduce this effect.

Practice Questions

A coin is placed 0.40 m0.40\ m in front of a plane mirror. State the image distance and where the image is located. [2 marks]

  • 1 mark for stating the image distance is 0.40 m0.40\ m

  • 1 mark for stating the image is behind the mirror

A student stands 1.5 m1.5\ m in front of a plane mirror.

(a) Determine the image distance from the mirror. [2 marks]

(b) Determine the distance between the student and the image. [2 marks]

(c) The student walks 0.30 m0.30\ m closer to the mirror. State the new image distance. [1 mark]

(a)

  • 1 mark for using the plane-mirror relation di=dod_i=d_o

  • 1 mark for stating the image is 1.5 m1.5\ m behind the mirror

(b)

  • 1 mark for recognizing the student-image separation is do+did_o+d_i

  • 1 mark for 3.0 m3.0\ m

(c)

  • 1 mark for stating the new image distance is 1.2 m1.2\ m behind the mirror

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