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AP Physics 2: Algebra Notes

5.3.3 Snell's Law

AP Syllabus focus: 'Snell's law relates the angles of incidence and refraction to the indices of refraction of the two media.'

Snell's law gives the mathematical connection between a light ray's direction and the optical properties of two materials. It is the main equation used to predict refraction at a boundary.

What Snell's Law Describes

When light reaches a boundary between two media, the direction of the ray in the first medium and the direction of the ray in the second medium are connected by a precise relationship. Snell's law does not describe the ray with words alone; it gives an algebraic rule that links the two angles to the two refractive indices.

The law applies at the point where the ray meets the surface.

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This refraction diagram shows an incident ray crossing a boundary into a second medium, with the normal drawn perpendicular to the interface. The labeled angles help emphasize the correct geometric definition of θ1\theta_1 and θ2\theta_2 as angles measured from the normal, which is essential for using n1sinθ1=n2sinθ2n_1\sin\theta_1=n_2\sin\theta_2 correctly. Source

A line called the normal is drawn perpendicular to the boundary at that point, and both relevant angles are measured from that normal.

Key angles

Angle of incidence: The angle between the incoming light ray and the normal to the surface at the point of incidence.

This is the angle the ray has before it enters the second medium.

Angle of refraction: The angle between the transmitted light ray and the normal after the light enters the second medium.

Both angles must be measured from the normal, not from the surface itself, or the equation will be used incorrectly.

The material property that appears in Snell's law is the index of refraction.

Index of refraction: A dimensionless quantity, written as nn, that characterizes how light behaves in a medium for refraction calculations.

A larger value of nn means the medium has a stronger effect on the direction of the ray in Snell's law.

The equation

n1sinθ1=n2sinθ2 n_1\sin\theta_1=n_2\sin\theta_2

n1 n_1 = index of refraction of the first medium, no unit

n2 n_2 = index of refraction of the second medium, no unit

θ1 \theta_1 = angle of incidence, measured from the normal, usually in degrees

θ2 \theta_2 = angle of refraction, measured from the normal, usually in degrees

This equation shows that the product of refractive index and the sine of angle must match on both sides of the boundary. For a fixed pair of media, you can also rearrange it as sinθ1sinθ2=n2n1 \dfrac{\sin\theta_1}{\sin\theta_2}=\dfrac{n_2}{n_1} . This form emphasizes that the ratio of the sines depends only on the two media.

Because the law uses sines, the change in angle is not linear. Doubling one angle does not generally double the other angle.

What the subscripts mean

The subscripts do not mean “incident” and “refracted” automatically. They label the two media. Medium 1 is the side where the ray begins, and medium 2 is the side the ray enters. The angle and index with the same subscript must always belong to the same medium.

Interpreting Snell's Law

Snell's law is useful because it connects geometry and material properties in one step.

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This OpenStax figure compares two refraction cases: slowing down in a higher-index medium bends the ray toward the normal, while speeding up bends it away. The paired panels reinforce how the geometry (angles to the normal) and material properties (indices of refraction, tied to speed) work together in Snell’s law. Source

  • If the two media have different refractive indices, then the two angles will usually be different.

  • If the two media have the same refractive index, then n1=n2n_1=n_2, so the equation requires θ1=θ2\theta_1=\theta_2 for ordinary refraction.

  • For the same incident angle, a larger difference between the two refractive indices produces a larger change in ray direction.

  • The medium with the larger refractive index corresponds to the smaller angle in the equation, because the sine term must adjust to keep both sides equal.

These statements come directly from the algebraic structure of the law. On AP Physics 2 problems, the main task is usually to identify which quantities are known, substitute them correctly, and solve for the unknown angle or unknown refractive index.

Using Snell's Law in problems

A reliable method helps avoid setup mistakes.

  • Identify the two media and assign them as 1 and 2.

  • Write the given angle as the angle to the normal.

  • Match each angle with the refractive index of the same medium.

  • Substitute into n1sinθ1=n2sinθ2n_1\sin\theta_1=n_2\sin\theta_2.

  • Isolate the unknown quantity algebraically.

  • If solving for an angle, use the inverse sine only after the sine is isolated.

When solving numerically, keep enough digits through the intermediate steps so rounding does not shift the final angle too much. Also make sure your calculator is in the intended angle mode.

Snell's law can be used in two common ways:

  • to find an unknown refracted angle when both refractive indices and the incident angle are known

  • to find an unknown refractive index when both angles and one refractive index are known

If light passes through more than one boundary, Snell's law is applied separately at each boundary rather than all at once.

Common errors to avoid

Many mistakes on refraction questions are not physics mistakes; they are setup mistakes.

  • Measuring angles from the surface instead of from the normal

  • Pairing n1n_1 with θ2\theta_2 or n2n_2 with θ1\theta_1

  • Forgetting that the equation uses sinθ\sin\theta, not just θ\theta

  • Applying the law without clearly identifying which medium is first and which is second

  • Rounding too early in multistep algebra

If your computed value for a sine is greater than 1 or less than 1-1, the setup should be checked carefully because no real angle can come from that result.

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This diagram illustrates total internal reflection and the critical angle, where the refracted ray would emerge at θ2=90\theta_2=90^\circ along the boundary. It provides a geometric reason that Snell’s law can produce an impossible value (a sine outside [1,1][-1,1]): beyond the critical angle, refraction ceases and the ray reflects instead. Source

In AP-level work, that usually signals that a quantity was entered incorrectly or that the simple refraction situation assumed by the equation is not being met.

FAQ

The sine appears because the law comes from the geometry of wavefronts at a boundary.

When a wave crosses from one medium to another, the spacing and direction of the wavefronts must stay consistent along the boundary. That geometric condition leads to a relationship involving $\sin\theta$, not just $\theta$.

Yes. You apply it at the exact point where the ray hits the surface.

At that point, draw the normal perpendicular to the curved surface locally, as if the surface were flat in a very small region. Then measure both angles from that local normal and use Snell's law in the usual way.

The form of the law stays the same, but the refractive index can depend on wavelength.

That means red light and blue light may have slightly different values of $n$ in the same material, so they can refract by different amounts. This is why a beam of white light can separate into colors when it enters some materials.

A common method is to measure many pairs of angles for the same two media and compare their sines.

If you plot $\sin\theta_1$ versus $\sin\theta_2$, the data should form a straight line. The slope is related to the refractive-index ratio, which lets you check whether the measurements are consistent with Snell's law.

Snell's law works best when the situation matches a simple boundary between uniform media.

Important assumptions include:

  • each medium is uniform

  • the boundary is well defined

  • the material is isotropic, so light behaves the same in all directions

  • the ray direction is clearly defined

If those assumptions fail, the simple form of Snell's law may no longer describe the light accurately.

Practice Questions

A light ray travels from air, n=1.00n=1.00, into acrylic, n=1.49n=1.49, with an angle of incidence of 3535^\circ. Calculate the angle of refraction.

  • 1 mark: Uses Snell's law correctly: 1.00sin35=1.49sinθ21.00\sin35^\circ=1.49\sin\theta_2

  • 1 mark: Finds θ222.6\theta_2 \approx 22.6^\circ

A ray travels from a liquid of unknown refractive index into glass with n=1.52n=1.52. The angle of incidence in the liquid is 5555^\circ, and the angle of refraction in the glass is 4444^\circ.

(a) Calculate the refractive index of the liquid.
(b) State whether the liquid has a greater or smaller refractive index than the glass.
(c) Explain, using Snell's law, why the angles are not equal.

  • 1 mark: Writes a correct equation: n1sin55=1.52sin44n_1\sin55^\circ=1.52\sin44^\circ

  • 1 mark: Rearranges correctly: n1=1.52sin44sin55n_1=\dfrac{1.52\sin44^\circ}{\sin55^\circ}

  • 1 mark: Calculates n11.29n_1 \approx 1.29

  • 1 mark: States the liquid has a smaller refractive index than the glass

  • 1 mark: Explains that since n1n2n_1 \ne n_2, Snell's law requires different angle values to keep n1sinθ1=n2sinθ2n_1\sin\theta_1=n_2\sin\theta_2

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