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AP Physics 2: Algebra Notes

6.7.4 Path Length Difference in Single-Slit Diffraction

AP Syllabus focus: 'Interference between wavefronts depends on path length difference. For a single opening, this difference can be described using opening width and the angle from the normal.'

Single-slit diffraction becomes easier to interpret when you track how much farther light from one part of the opening travels than light from another part on the way to the same point.

Path Length Difference and Wavefronts

Single-slit diffraction is produced by one opening, but the light emerging from that opening can be treated as coming from many points across the slit. To understand what happens at a point on a screen, you compare how far light from different parts of the slit has traveled.

When those travel distances are equal, the waves arrive in step. When the distances are different, the waves arrive with a phase difference, so some parts of the wave can reinforce while others cancel.

Path length difference: The difference in distance traveled by two waves from different parts of the opening to the same observation point.

Path length difference is therefore the geometric reason that interference occurs in a diffraction pattern. In single-slit diffraction, you are not comparing two separate slits. You are comparing different parts of the same opening. That is why a single slit can still produce bright and dark regions.

Another important idea is that path length difference is connected to phase difference. If one wave travels farther than another, it may arrive shifted by part of a cycle. Whether the waves reinforce or cancel depends on how that extra distance compares with the wavelength.

Geometry of a Single Opening

Imagine a slit of width aa and a point on a screen viewed at an angle θ\theta from the normal. The normal is the line drawn perpendicular to the opening. A point directly in front of the slit has θ=0\theta=0^\circ.

At θ=0\theta=0^\circ, light from the top and bottom edges of the slit travels essentially the same distance to the screen point. That means the path length difference is zero. In that direction, the contributions from across the slit are aligned most strongly.

At a point off to one side, the paths are no longer equal. One edge of the slit has a slightly longer route to the screen point than the other. As the observation angle increases, that difference increases.

The key geometric idea is projection. The full slit width does not become extra travel distance. Only the component of the slit width along the direction of travel contributes to the extra distance. Because the angle is measured from the normal, this projected part leads to a sine relationship.

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Ray diagram for single-slit diffraction showing how the path length difference between light from opposite edges of a slit of width aa depends on observation angle θ\theta. The figure visually motivates the projection argument that leads to ΔL=asinθ\Delta L=a\sin\theta and connects specific angles to bright/dark directions via constructive/destructive interference. Source

Mathematical Description

For the two extreme edges of the slit, the path length difference is:

ΔL=asinθ \Delta L = a\sin\theta

ΔL \Delta L = path length difference between light from opposite edges of the opening, m

a a = opening width, m

θ \theta = angle measured from the normal

This expression gives the largest path length difference across the entire slit for a particular direction. It does not only apply to the edges as a special case; it also helps you reason about smaller sections within the slit.

If you compare two points inside the opening separated by a distance xx, then their path length difference is xsinθx\sin\theta. This is useful because single-slit diffraction is often understood by pairing points inside the slit and checking whether each pair arrives in or out of phase.

The equation also shows several important trends:

  • If aa increases, the same angle produces a larger path length difference.

  • If θ\theta increases, the projected separation along the travel direction becomes larger.

  • If θ=0\theta=0^\circ, then sinθ=0\sin\theta=0, so the path length difference is zero.

Why Path Length Difference Controls Interference

Interference depends on phase, and phase depends on how path length difference compares with wavelength. A difference of one full wavelength means the waves arrive one full cycle apart and are effectively back in step. A difference of half a wavelength means the waves arrive opposite in phase and can cancel.

In a single slit, many wavefronts overlap at the same screen point, so destructive interference is often described in pairs. Suppose the total edge-to-edge path length difference is λ\lambda. Then two points separated by a/2a/2 have a path length difference of λ/2\lambda/2. Each such pair arrives 180180^\circ out of phase, so the contributions cancel pair by pair across the slit.

This is why a single opening can produce dark regions on a screen. The darkness is not caused by light being blocked at that angle after the slit. It comes from self-interference between waves from different parts of the opening after they have traveled slightly different distances.

If the path length difference is not the right value for complete cancellation, the cancellation is only partial. That is why diffraction patterns change smoothly with angle rather than switching abruptly from bright to dark.

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Calculated single-slit diffraction intensity curve (normalized) alongside a photograph of a real single-slit pattern. The plot highlights a dominant central maximum and successive minima/maxima, helping connect geometric path difference to the observed intensity variation with angle. Source

Reading Single-Slit Diagrams

When reading a diffraction diagram, identify these features first:

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Schematic of a single slit and the corresponding diffraction pattern, emphasizing the bright central maximum and weaker side maxima. This supports diagram-reading by linking the labeled slit width aa and geometry to the observed intensity distribution on the screen. Source

  • the slit width aa

  • the normal line through the center of the opening

  • the angle θ\theta from the normal

  • the two rays or wavelets being compared

Then ask a geometric question: what part of the slit separation lies along the direction of travel toward the screen point? That projected part is the path length difference.

The sign of the path length difference depends on which side of the slit is chosen as the reference. In most diffraction reasoning, the important quantity is the magnitude, because the magnitude determines the phase relationship and therefore the type of interference.

FAQ

The expression $ \Delta L = a\sin\theta $ compares the two extreme edges of the opening, so it uses the full width.

If you compare any two points inside the slit instead, you use their separation distance. For points separated by $x$, the path length difference is $x\sin\theta$.

The path length difference comes from the component of the slit width along the direction the light is traveling toward the screen point.

Because the angle is measured from the normal, that projected component is proportional to $\sin\theta$. If the angle were measured from a different reference line, the trig function could look different.

Yes. The sign depends on which side of the slit you choose as the reference point.

A negative value does not mean the physics changes. It only tells you which side has the longer path. For interference, the magnitude of the difference is usually the important part.

No. The geometric path length difference depends on the slit width and the observation angle, not on the wavelength.

What wavelength changes is the phase shift produced by that distance difference. The same $ \Delta L $ can correspond to different amounts of phase difference for different wavelengths.

It works best when the observation point is far enough away that the rays from different parts of the slit to that point are nearly parallel.

If the screen is very close to the slit, the geometry becomes more complicated because different parts of the slit no longer share the same single angle in a simple way.

Practice Questions

A monochromatic light wave passes through a single slit of width aa. At a point on the screen, the light is observed at an angle θ\theta from the normal.

State the expression for the path length difference between light from the two edges of the slit, and describe what happens to this path length difference as θ\theta increases.

  • 1 mark for stating ΔL=asinθ \Delta L = a\sin\theta

  • 1 mark for stating that the path length difference increases as θ\theta increases away from 00^\circ

Light passes through a single slit of width aa. At a particular observation angle θ\theta, the edge-to-edge path length difference is such that asinθ=λa\sin\theta=\lambda.

Using the idea of path length difference, explain why this direction corresponds to a dark region in the diffraction pattern.

  • 1 mark for recognizing that the total path length difference across the slit is λ\lambda

  • 1 mark for stating that the slit can be divided into two equal halves

  • 1 mark for stating that corresponding points in the two halves are separated by a/2a/2

  • 1 mark for stating that each corresponding pair has a path length difference of λ/2\lambda/2

  • 1 mark for concluding that each pair is out of phase and cancels, producing destructive interference and a dark region

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