AP Syllabus focus: 'AP Physics 2 includes qualitative and quantitative conservation of momentum in two dimensions for Compton scattering.'
In Compton scattering, momentum must be conserved as a vector, so the interaction is analyzed separately in perpendicular directions. This helps predict recoil directions and connect geometry to measurable momentum changes.
Momentum conservation as a vector rule
Conserving perpendicular components
When a photon collides with an electron and changes direction, the interaction is usually not confined to a single straight line. That makes two-dimensional momentum conservation essential. Instead of using one scalar momentum equation, you treat momentum in the horizontal and vertical directions separately. The total momentum vector before the interaction must equal the total momentum vector after the interaction.
Momentum conservation in two dimensions: In an isolated interaction, the total momentum vector stays constant, so the total x-momentum and total y-momentum are each conserved separately.
This is the same conservation law used in one-dimensional collisions, but now direction matters more explicitly. In AP Physics 2, the important idea is that each component must work out on its own. A result that looks reasonable overall but fails in one direction is not physically valid.
= total initial momentum in the x-direction, in
= total final momentum in the x-direction, in
= total initial momentum in the y-direction, in
= total final momentum in the y-direction, in
These two equations are independent. Solving only for the total magnitude of momentum is not enough when particles leave in different directions.
Applying the rule to Compton scattering
Standard AP setup
A common setup takes the incoming photon to move along the positive x-axis before the interaction. If the electron is initially at rest, the system begins with no y-momentum at all. After the interaction, the photon may scatter at an angle above or below the original direction, and the electron recoils at its own angle.

Schematic of the Compton-scattering momentum geometry: the incident photon travels along the initial axis, the scattered photon leaves at angle , and the recoil electron leaves at angle . This picture is the starting point for writing separate conservation equations for the - and -components of momentum. Source
Because the initial y-momentum is zero, the final y-components must cancel. If the photon leaves with an upward y-component, the electron must have a downward y-component of equal magnitude. That is often the quickest qualitative check in a diagram.
If the scattered photon makes an angle with the original direction and the electron makes an angle , the component equations come from trigonometry. The cosine term gives the x-component, and the sine term gives the y-component.

Vector-component diagram for Compton scattering showing how each outgoing momentum is resolved into horizontal and vertical components (e.g., and ). With the incoming photon along , the figure makes it clear why the -components must sum to zero when the initial -momentum is zero. Source
= initial photon momentum, in
= scattered photon momentum, in
= photon scattering angle from the initial direction, measured in degrees or radians
= electron momentum after the interaction, in
= electron recoil angle from the initial direction, measured in degrees or radians
= initial y-momentum for an incoming photon along the x-axis and an electron initially at rest
= y-component of the scattered photon momentum, in
= y-component of the electron momentum, in
The sign in the y-equation depends on your coordinate choice. Different sign conventions can all be correct if they are used consistently.
Qualitative reasoning in two dimensions
Even without plugging in numbers, two-dimensional momentum conservation gives strong physical insight.
If the initial motion is entirely along the x-axis, the final y-components must cancel.
If one final particle moves above the original line of motion, the other must balance that with an equal and opposite y-component.
The final x-components must add up to the original forward momentum.
A proposed diagram is impossible if the outgoing y-components point the same way with no initial y-momentum to balance them.
A very large scattering angle changes how much momentum appears in the x- and y-directions, so the other particle’s momentum must adjust accordingly.
This kind of reasoning is especially useful on multiple-choice questions, where one or more choices may violate component conservation even if the picture seems plausible at first glance.
Solving quantitative problems
A consistent method reduces sign and trigonometry errors.
Draw a momentum sketch and label every angle clearly.
Choose axes so the incoming photon lies on the x-axis whenever possible.
Identify which components are initially zero.
Resolve each final momentum into x- and y-components using sine and cosine.
Apply conservation in x and y separately.
Solve the resulting algebraic equations for unknown components, angles, or momentum magnitudes.
Check that the final directions make sense physically.
In many AP Physics 2 problems, it is easier to find the electron’s x- and y-components first. If a final momentum magnitude is needed, combine the components afterward. The essential physics step is always the separate conservation of momentum in each direction.
Common mistakes to avoid
Several errors appear frequently in two-dimensional Compton scattering problems:
Treating momentum like a single number instead of a vector.
Writing only one conservation equation for the entire interaction.
Using the wrong trigonometric function because the angle was measured from a different axis.
Forgetting that a downward or leftward component is negative in many coordinate choices.
Assuming that the outgoing photon and electron must have equal angles or equal momentum magnitudes.
Combining magnitudes before checking whether the x- and y-directions are both conserved.
A strong self-check is to inspect the y-direction first. If the initial y-momentum is zero but your final y-components do not cancel, the setup, signs, or algebra must be corrected.
FAQ
You must include the electron’s initial x- and y-components in the total initial momentum.
That means you cannot automatically set the initial y-momentum to zero. The same conservation idea still applies, but both sides of each component equation now contain contributions from both particles.
Yes. A backward-scattered photon has a negative x-component of momentum.
Momentum can still be conserved if the electron carries enough positive x-momentum so that the total final x-momentum matches the initial x-momentum. The component method handles this naturally.
Measured angles and momentum values always have some uncertainty.
A small error in angle can noticeably change a sine or cosine component, so experimental totals may be close to conserved values rather than exactly equal. Physicists judge the result by whether the mismatch is reasonable compared with the measurement uncertainty.
No. A negative component only means the vector points opposite the chosen positive axis.
The full momentum magnitude is still nonnegative. For example, $p_y<0$ means the motion has a downward component, not that the particle has a negative total momentum.
Yes. Many problems are solved entirely with momentum components.
If the given information already includes momentum values or enough information to determine them, speed is not required. On AP Physics 2, component conservation is often the main goal, not a full kinematic description of the electron.
Practice Questions
(2 marks)
An incoming photon travels along the positive x-axis and scatters at an angle above the x-axis. The electron is initially at rest.
State the direction of the electron’s y-component of momentum after the collision and explain briefly.
States that the electron’s y-component of momentum is downward, or in the negative y-direction. (1)
Explains that the initial y-momentum is zero, so the final y-components must cancel to conserve momentum. (1)
(6 marks)
A photon with initial momentum kg·m/s travels along the positive x-axis and scatters with momentum kg·m/s at above the x-axis. The electron is initially at rest and recoils into the fourth quadrant.
(a) Write the momentum conservation equation for the x-direction.
(b) Write the momentum conservation equation for the y-direction.
(c) Calculate the electron’s x- and y-components of momentum.
(d) Determine the magnitude of the electron’s momentum and its angle below the x-axis.
(a) Writes . (1)
(b) Writes , or an equivalent sign-consistent form. (1)
(c) Finds kg·m/s. (1)
(c) Finds kg·m/s. (1)
(d) Finds kg·m/s. (1)
(d) Finds the recoil angle below the x-axis. (1)
