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AP Physics 2: Algebra Notes

7.7.8 Decay Constant, Remaining Nuclei, and Dating

AP Syllabus focus: 'A decay constant relates to half-life and predicts remaining nuclei after time, or material age when the initial amount is known.'

Radioactive samples change unpredictably one nucleus at a time, but large groups follow precise statistical patterns. The decay constant connects that randomness to measurable changes in remaining nuclei and estimated ages.

Decay constant and half-life

Each radioactive isotope has its own decay constant, which describes how quickly the nuclei in a sample tend to decay.

Decay constant: A constant, usually written as λ \lambda , that gives the probability per unit time that a nucleus in a radioactive sample will decay.

The decay constant is a property of the isotope itself, not of the sample size. A larger value of λ \lambda means nuclei decay more quickly, while a smaller value means they decay more slowly.

A closely related idea is half-life, the time required for half of the undecayed nuclei in a sample to remain.

Half-life: The time required for the number of undecayed nuclei in a radioactive sample to decrease to one-half of its original value.

Half-life and decay constant describe the same process in different ways. Half-life is often easier to visualize, while the decay constant is especially useful in mathematical models.

λ=ln2T1/2 \lambda=\dfrac{\ln 2}{T_{1/2}}

λ \lambda = decay constant, in s1 s^{-1} or other reciprocal time units

T1/2 T_{1/2} = half-life, in s s

Because ln2 \ln 2 is a constant, half-life and decay constant are inversely related. If the half-life is short, the decay constant is large. If the half-life is long, the decay constant is small.

Predicting remaining nuclei over time

For a large sample, the number of undecayed nuclei does not decrease by the same amount each second. Instead, it decreases by the same fraction over equal time intervals. That is why radioactive decay follows an exponential pattern.

Pasted image

Decay curve showing the percent remaining as a function of the number of half-lives. The labeled points (50%, 25%, 12.5%, …) make it easy to see that each equal half-life interval multiplies the remaining amount by 12\tfrac{1}{2}, which is the defining feature of exponential decay. Source

In a real sample, the exact nucleus that decays next cannot be predicted. However, when many nuclei are present, the overall behavior becomes highly regular, so the exponential model gives reliable predictions for the number remaining.

N=N0eλt N=N_0 e^{-\lambda t}

N N = number of undecayed nuclei remaining after time t t

N0 N_0 = initial number of undecayed nuclei

λ \lambda = decay constant, in s1 s^{-1}

t t = elapsed time, in s s

This equation shows that the number remaining depends on both the isotope, through λ \lambda , and the elapsed time. The equation can also be written using half-life when that form is more convenient.

N=N0(12)t/T1/2 N=N_0\left(\dfrac{1}{2}\right)^{t/T_{1/2}}

N N = number of undecayed nuclei remaining after time t t

N0 N_0 = initial number of undecayed nuclei

t t = elapsed time, in s s

T1/2 T_{1/2} = half-life, in s s

These two forms are equivalent. The half-life form is especially useful when the elapsed time is an exact whole-number multiple of the half-life.

Useful interpretations include:

  • If one half-life has passed, N=N02 N=\dfrac{N_0}{2} .

  • If two half-lives have passed, N=N04 N=\dfrac{N_0}{4} .

  • If three half-lives have passed, N=N08 N=\dfrac{N_0}{8} .

Age problems are often easiest when the fraction remaining matches one of these simple patterns. Recognizing a familiar fraction can save time and reduce algebra.

Because the decrease is exponential, the sample never reaches zero in the mathematical model. It becomes smaller and smaller, but the fraction remaining keeps shrinking rather than dropping to zero at a fixed time.

Finding the age of a material

These same ideas can be used for dating, which means determining how long it has been since a material started with a known initial amount of a radioactive isotope.

Radiometric dating: A method for finding the age of a material by using radioactive decay and comparing the amount of radioactive nuclei present now with the amount present initially.

To determine age, the key information is the initial amount and the amount remaining now. If those are known, then the elapsed time can be found from the decay model. In AP Physics 2 problems, the initial amount is typically given directly or can be inferred from the way the question is stated.

t=1λln(N0N) t=\dfrac{1}{\lambda}\ln\left(\dfrac{N_0}{N}\right)

t t = age or elapsed time, in s s

λ \lambda = decay constant, in s1 s^{-1}

N0 N_0 = initial number of undecayed nuclei

N N = number of undecayed nuclei remaining now

This equation is the decay law rearranged to solve for time. In many AP Physics 2 situations, the easiest path is to recognize how many half-lives have passed from the fraction remaining, then multiply by the half-life.

When using these ideas, the same ratio idea applies even if the amount is measured in mass rather than by counting nuclei directly, as long as the measurement refers to the same radioactive isotope throughout. The fraction remaining is what matters.

What to emphasize on AP Physics 2 problems

Most questions on this subsubtopic focus on interpreting ratios and choosing the most efficient equation. Common reasoning patterns include:

  • A decay constant gives the rate tendency of the isotope, not a fixed number of nuclei lost each second.

  • The number of remaining nuclei decreases exponentially, not linearly.

  • Half-life stays constant for a given isotope, even though the number of decays during each half-life gets smaller as the sample shrinks.

  • If the initial amount is known, the current amount can be used to find the age.

  • If only the current amount is known, the age cannot be determined without more information about the starting amount or the fraction that remains.

A good check on any answer is whether it matches the physical trend. Older samples should have fewer parent nuclei remaining, and isotopes with larger decay constants should reach the same fraction remaining in less time.

FAQ

The ratio $ N/N_0 $ shows the fraction remaining, which makes the calculation independent of the original sample size.

That means:

  • two different samples of the same isotope can be compared directly

  • the same decay model works whether the amount is measured in nuclei, moles, or mass

  • the mathematics becomes simpler, especially when the fraction is a familiar value like $ 1/2 $, $ 1/4 $, or $ 1/8 $

A closed system is one in which the radioactive isotope being used for dating has not been added to or removed from the sample after the dating process started.

If material enters or leaves, the measured amount no longer reflects only radioactive decay. That can make the age appear:

  • too old, if extra parent nuclei were added

  • too young, if parent nuclei were lost

Dating works best when the sample has remained chemically undisturbed.

In a very young sample, only a small fraction of the original nuclei has decayed.

That means the difference between $ N $ and $ N_0 $ may be tiny, so:

  • measurement uncertainty becomes more important

  • small experimental errors can cause a large percentage error in age

  • the sample may not have changed enough to give a strong time signal

A dating method works best when enough decay has occurred to be measurable.

If a sample is extremely old compared with the isotope’s half-life, very little of the parent isotope may remain.

This creates problems because:

  • the remaining amount may be difficult to measure accurately

  • contamination becomes more significant

  • small absolute errors can strongly affect the age estimate

For this reason, scientists try to choose an isotope with a half-life that matches the approximate age range of the material.

They can have the same decay constant but different numbers of decays per second if the sample sizes are different.

The decay constant depends only on the isotope itself. However:

  • a larger sample contains more radioactive nuclei

  • more nuclei means more chances for decay in any time interval

  • both samples still lose the same fraction in the same amount of time

So the decay pattern is the same in a fractional sense, even if the raw numbers differ.

Practice Questions

A radioactive isotope has a half-life of 1212 days. What fraction of the original undecayed nuclei remains after 3636 days?

  • Recognizes that 3636 days is 33 half-lives. (1)

  • States the fraction remaining is (12)3=18 \left(\dfrac{1}{2}\right)^3=\dfrac{1}{8} . (1)

A mineral originally contained 1.6×10121.6\times10^{12} nuclei of a radioactive isotope. A later measurement shows that 2.0×10112.0\times10^{11} nuclei remain. The decay constant for the isotope is 1.73×104 yr11.73\times10^{-4}\ yr^{-1}.

(a) Determine the fraction of nuclei remaining.
(b) Determine how many half-lives have passed.
(c) Determine the age of the mineral.

  • Calculates the fraction remaining: 2.0×10111.6×1012=0.125=18 \dfrac{2.0\times10^{11}}{1.6\times10^{12}}=0.125=\dfrac{1}{8} . (1)

  • Identifies that 18=(12)3 \dfrac{1}{8}=\left(\dfrac{1}{2}\right)^3 , so 33 half-lives have passed. (1)

  • Uses T1/2=ln2λ T_{1/2}=\dfrac{\ln 2}{\lambda} . (1)

  • Calculates T1/20.6931.73×1044.0×103 yr T_{1/2}\approx\dfrac{0.693}{1.73\times10^{-4}}\approx4.0\times10^3\ yr . (1)

  • Calculates age: t=3T1/21.2×104 yr t=3T_{1/2}\approx1.2\times10^4\ yr . (1)

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