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AP Physics 2: Algebra Notes

7.8.4 Beta-Minus Decay

AP Syllabus focus: 'Beta-minus decay occurs when a neutron changes to a proton by emitting an electron and an antineutrino.'

In beta-minus decay, the nucleus changes internally rather than simply ejecting one of its existing electrons. Understanding which quantities change, and which stay the same, is essential for interpreting nuclear equations.

Beta-Minus Decay

Term: Beta-minus decay: A nuclear decay process in which a neutron changes into a proton and the nucleus emits an electron and an antineutrino.

Beta-minus decay is a nuclear process, so it happens in the nucleus, not in the atom’s surrounding electron cloud. One neutron in the nucleus is transformed into a proton. That change immediately alters the composition of the nucleus: the number of protons goes up by one, and the number of neutrons goes down by one.

Because the proton number changes, the nucleus becomes a different element after the decay. However, the total number of nucleons stays the same, so the mass number does not change. This combination is the key pattern to recognize in beta-minus decay.

Particle-Level Description

At the particle level, beta-minus decay is described as a neutron turning into a proton while emitting an electron and an antineutrino.

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Diagram of beta-minus decay illustrating the fundamental particle reaction np+e+νˉen \to p + e^- + \bar{\nu}_e. The labels emphasize that the proton remains in the nucleus while the emitted electron (beta particle) and antineutrino exit. Source

Particle reaction=np+e+νˉe Particle\ reaction = n \to p + e^- + \bar{\nu}_e

n n = neutron

p p = proton

e e^- = emitted electron

νˉe \bar{\nu}_e = electron antineutrino

This equation describes what happens to a single neutron.

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Feynman diagram representation of neutron beta-minus decay, showing the weak interaction mediated by a virtual WW^-. This reinforces conservation at the vertices while matching the net outcome np+e+νˉen \to p + e^- + \bar{\nu}_e. Source

In a real nucleus, the new proton remains inside the nucleus, while the electron and antineutrino leave the atom. The emitted electron is produced in the decay process; it is not an ordinary orbital electron that was already circling the nucleus and then got knocked out.

If a parent nucleus is written with mass number AA and atomic number ZZ, the daughter nucleus after beta-minus decay still has mass number AA, but its atomic number becomes Z+1Z+1. In words, the nucleus keeps the same total number of nucleons while gaining one extra proton.

What Changes in the Nucleus

The easiest way to track beta-minus decay is to compare the parent nucleus with the daughter nucleus.

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Textbook-style diagram of beta decay in a nucleus, depicting a neutron converting into a proton while an electron and neutrino are emitted. The visual supports the conservation idea used in nuclear equations: nucleon count (mass number AA) stays fixed even though the atomic number changes. Source

  • Protons: increase by 1

  • Neutrons: decrease by 1

  • Mass number: stays the same

  • Atomic number: increases by 1

This happens because a neutron is changing identity rather than being removed from the nucleus. Before the decay, that particle counted as a neutron. After the decay, it counts as a proton. Since both neutrons and protons are nucleons, the total nucleon count is unchanged.

A useful way to think about the process is to separate which quantity counts element identity from which quantity counts total nuclear matter. Element identity depends on the number of protons, so beta-minus decay changes the element. Mass number counts protons plus neutrons, so beta-minus decay leaves that value unchanged.

The Emitted Electron

The emitted electron is often called a beta particle.

Beta particle: The high-speed electron emitted from the nucleus during beta-minus decay.

This electron carries negative charge and typically leaves the nucleus at high speed. In nuclear equations, it may be written as ee^- or as β\beta^-. Both symbols represent the same emitted particle in beta-minus decay.

It is important to interpret this correctly. The nucleus did not contain a normal atomic electron waiting to escape. Instead, the decay itself produces the emitted electron at the same time the neutron changes into a proton. That is why beta-minus decay is classified as a nuclear transformation, not a rearrangement of the atom’s electron cloud.

The Emitted Antineutrino

Beta-minus decay also emits an electron antineutrino. This particle has no electric charge and interacts only very weakly with matter. As a result, it usually passes through surrounding material without leaving an obvious trace in simple laboratory detectors.

Even though the antineutrino is difficult to observe directly, it is still an essential part of the beta-minus decay description. A correct nuclear equation for this decay includes both the emitted electron and the emitted antineutrino.

Recognizing Beta-Minus Decay in Problems

On AP Physics 2 Algebra problems, beta-minus decay is usually identified from the particles shown or from the changes in the nucleus. You should look for the same basic features every time:

  • a neutron changes to a proton

  • an electron is emitted

  • an antineutrino is emitted

  • the atomic number increases by 1

  • the mass number stays the same

A common mistake is to focus only on the emitted electron. Beta-minus decay is not defined just by “an electron coming out.” The full process includes the neutron-to-proton change inside the nucleus and the emission of the electron and the antineutrino.

Another common mistake is to assume the atom’s mass number should fall because a particle left the nucleus. In beta-minus decay, the emitted electron is not reducing the nucleon count. The neutron has become a proton, so the nucleus still contains the same total number of nucleons after the decay.

FAQ

The word beta is a historical label for one category of radiation emitted by unstable nuclei.

The word minus shows that the emitted beta particle has negative electric charge, because the particle is an electron.

Yes. A neutron does not have to be inside a nucleus to undergo this process.

A free neutron can decay into a proton, an electron, and an electron antineutrino. Whether a neutron inside a nucleus decays depends on the stability and energy conditions of that nucleus.

The released energy is not carried by the electron alone.

In beta-minus decay, the available energy is shared among the emitted electron, the antineutrino, and the recoiling daughter nucleus. Because that sharing can vary from one decay to another, the electron can emerge with many different energies.

Beta particles are charged, so they can ionize matter and be measured with detectors.

Common methods include:

  • Geiger-Müller tubes

  • scintillation detectors

  • cloud chambers or similar track detectors

  • magnetic fields to bend the electron’s path

These methods usually detect the emitted electron rather than the antineutrino.

Because beta radiation consists of fast electrons, it can often be reduced with materials of moderate thickness.

Common shielding materials include:

  • plastic

  • acrylic

  • glass

  • aluminum

In practice, low-atomic-number materials are often preferred first, because very dense shielding can produce additional X-rays when fast electrons slow down.

Practice Questions

A nucleus undergoes beta-minus decay. State: (a) which particle in the nucleus changes, (b) the two particles emitted, (c) how the atomic number changes. [3 marks]

  • Neutron changes to a proton. (1)

  • An electron and an electron antineutrino are emitted. (1)

  • The atomic number increases by 1. (1)

A parent nucleus ZAX^{A}_{Z}X undergoes beta-minus decay and becomes nucleus YY. (a) Write the complete decay equation. [3 marks] (b) Compare the numbers of protons and neutrons in the daughter nucleus with those in the parent nucleus. [2 marks]

(a)

  • Daughter nucleus has mass number AA. (1)

  • Daughter nucleus has atomic number Z+1Z+1. (1)

  • Emitted particles are ee^- and νˉe\bar{\nu}_e. (1)

A fully correct equation is: A<em>ZXA</em>Z+1Y+e+νˉe^{A}<em>{Z}X \to ^{A}</em>{Z+1}Y + e^- + \bar{\nu}_e

(b)

  • Daughter nucleus has one more proton than the parent nucleus. (1)

  • Daughter nucleus has one fewer neutron than the parent nucleus. (1)

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