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IB DP Chemistry SL Study Notes

2.1.1 Ion Formation and Prediction

Understanding how atoms form ions, their charges and predicting these charges based on the electron configuration of the atom is pivotal in comprehending chemical bonding. Dive into the formation of ions and their importance.

Formation of Ions

Atoms aim to achieve a full outer electron shell, resembling noble gases. This drive is often met through the gain or loss of electrons, resulting in the formation of ions.

Metals and Cations

  • Metals: Found mainly on the left-hand side and centre of the periodic table.
    • Tend to lose one or more electrons to achieve a full outer shell.
    • When they lose electrons, they become positively charged ions, termed cations.

For instance:

  • Sodium (Na) loses one electron to form the Na⁺ cation.
  • Magnesium (Mg) loses two electrons to become Mg²⁺.

Non-metals and Anions

  • Non-metals: Located mainly on the right-hand side of the periodic table.
    • Generally gain one or more electrons to achieve a full outer shell.
    • Upon gaining electrons, they transform into negatively charged ions, known as anions.
Difference between cation and anion.

Image courtesy of Ali

Examples include:

  • Chlorine (Cl) gains one electron to form the Cl⁻ anion.
  • Oxygen (O) gains two electrons to become O²⁻.
A diagram showing cations and anions.

Cations and anions, using hydrogen as an example.

Image courtesy of Jkwchui

Predicting Ion Charge from Electron Configuration

The electron configuration of an atom can hint at its most stable ion form.

  • Groups 1 and 2 (Alkali and Alkaline Earth Metals):
    • Lose 1 or 2 electrons respectively to form +1 or +2 cations.
  • Group 17 (Halogens):
    • Tend to gain an electron to form -1 anions.
  • Group 16:
    • Typically gain two electrons, forming -2 anions.

By examining the electron configuration, one can discern how many electrons an atom would prefer to lose or gain to reach a full outer shell, giving insights into its typical ion charge.

Transition Metals and Variable Charges

Transition metals, seated in the central block of the periodic table, exhibit intriguing behaviour.

  • Unlike s-block metals, they can form cations with varying charges.
  • Electron loss primarily originates from the 4s subshell before the 3d subshell, despite 4s filling before 3d.

For instance:

  • Iron can form both Fe²⁺ and Fe³⁺ cations.
  • Copper commonly forms Cu⁺ and Cu²⁺.

Position on the Periodic Table and Ion Charge

The position of an element in the periodic table provides valuable clues about the charge of its ions.

  • Groups (Vertical columns):
    • Elements within the same group generally have the same number of outer-shell electrons.
    • Hence, they often form ions with comparable charges.
  • Periods (Horizontal rows):
    • As one moves from left to right across a period, the atomic number increases, leading to more electrons.
    • Metals on the left tend to form positive ions, while non-metals on the right form negative ions.
Diagram of the periodic table.

Periodic table showing atomic number above each element.

Image courtesy of Dmarcus100

Successive Ionisation Energies and Transition Metals

Successive ionisation energies refer to the energy needed to remove each electron in turn.

  • For transition metals, these energies offer insights into their variable oxidation states.
  • The energy required to remove the first electron is usually much less than that needed to remove subsequent ones.
  • These increasing energies can hint at which oxidation states (or ion charges) are more stable for a given transition metal.

For example, the large jump between the second and third ionisation energies for iron suggests that Fe²⁺ is more stable than Fe³⁺, although both exist.

A graph showing trends in Ionisation Energies of Transition Metals

Trend of ionization energy for 1st, 2nd and 3rd row transition metals.

Image courtesy of Oncandor

FAQ

Electron shielding, or the repulsion between electrons in various shells, plays a critical role in ion formation, particularly in transition metals. As the number of inner electrons (those in lower energy levels) increases, they shield the outer electrons from the nucleus's full positive charge. In transition metals, the d and f orbitals fill up, adding more inner electrons. However, these d and f electrons don't shield as effectively as s or p electrons. This weaker shielding in transition metals means that the outermost electrons feel a stronger attraction to the nucleus, making them harder to remove. This contributes to the variable oxidation states of transition metals since the energy required to remove these outer electrons can vary significantly.

The formation of a particular ion for a transition metal in a specific scenario is influenced by multiple factors, including the chemical environment and the metal's electron configuration. Factors such as ligands present, the pH of the environment, and the potential reactants can influence which ion is more stable and therefore more likely to form. For example, the presence of strong oxidising agents might favour the formation of a higher oxidation state ion. Additionally, the specific electron configuration of the metal can play a role; if removing one more electron leads to a half-filled or completely filled d orbital, this might be energetically favourable, pushing the metal to adopt that particular ion state.

The charges of ions dictate how they interact with other ions, thereby determining the physical and chemical properties of the compounds they form. For instance, the strength of the electrostatic attraction between ions in a compound, termed lattice enthalpy, is influenced by the charges of the ions: higher charges lead to stronger attractions. This directly impacts properties like melting and boiling points. Additionally, the charge on an ion can influence its solubility in different solvents, electrical conductivity, and reactivity. In chemical reactions, the charge dictates how the ion will interact with other species, its likelihood to participate in a reaction, and the products that will be formed.

Yes, there are exceptions, albeit rare. While metals predominantly form cations and non-metals usually form anions, certain situations can deviate from this norm. For example, under specific conditions, some metals can accept electrons to form anionic species known as metal anions or metalloid anions. One such instance is the formation of the Zintl phase in certain solid-state compounds. Additionally, in specific complex chemical environments or under extreme conditions, non-metals might lose electrons to form cationic species. However, these scenarios are not common and often require unique conditions or specific reactions to occur.

Atoms strive for a full outer electron shell because this configuration grants them increased stability. This drive is based on the noble gas configuration, where noble gases (like helium, neon, and argon) have full outer shells and are remarkably stable and unreactive. Atoms with incomplete outer shells have a tendency to react with other atoms, either sharing, losing, or gaining electrons to attain this stable configuration. By doing so, they lower their potential energy, thereby becoming more stable. It's this quest for stability that governs many chemical reactions and interactions.

Practice Questions

Based on their positions in the periodic table, predict the charges of the ions formed by the following elements and justify your predictions: Sodium (Na), Oxygen (O), and Iron (Fe).

Sodium (Na) is in Group 1 of the periodic table, which means it has one electron in its outermost shell. Elements in this group tend to lose one electron to achieve a full outer shell, forming cations with a +1 charge. Therefore, sodium forms the Na⁺ ion. Oxygen (O) belongs to Group 16, having six electrons in its valence shell. To achieve a full outer shell, it gains two electrons, resulting in anions with a -2 charge, thus forming the O²⁻ ion. Iron (Fe), being a transition metal, can form ions with variable charges, such as Fe²⁺ and Fe³⁺. The exact charge would depend on the specific chemical environment or reaction in which iron is involved.

Explain the significance of successive ionisation energies in understanding the variable oxidation states of transition metals, using copper (Cu) as an example.

Successive ionisation energies indicate the energy required to remove electrons in sequence from an atom. For transition metals, there's an increase in ionisation energy with each successive electron removed, which provides insights into their variable oxidation states. Taking copper (Cu) as an example, the first and second ionisation energies correspond to the removal of the 4s electrons, forming Cu²⁺. However, the significant rise in energy required for the third ionisation suggests the 3d electrons are more difficult to remove. This energy jump gives evidence for the stability of Cu²⁺, and it helps explain why copper often exhibits a +2 oxidation state, though the +1 state (Cu⁺) can also exist in certain conditions.

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