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Practice Questions

1. Parametric Equations, Polar Coordinates, and Vector-Valued Functions

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Question 1

Graphing calculator required

A survey drone moves in a horizontal plane. For 0t60\leq t\leq6, where tt is measured in hours, its velocity components are

vx(t)=2cos(0.6t)+0.4v_x(t)=2\cos(0.6t)+0.4

and

vy(t)=1.2sin(0.8t)0.3v_y(t)=1.2\sin(0.8t)-0.3.

Velocity is measured in km/hour\mathrm{km/hour}. At time t=0t=0, the drone is at the position (1,2)(1,-2) kilometres. The graph shows the two velocity components. Round calculator results to three decimal places.

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Part (a)(i)
[1]

Write an expression for the drone’s position vector at time t=5t=5.

Part (a)(ii)
[2]

Calculate the drone’s position at time t=5t=5.

Part (b)
[1]

Determine the first time in 0<t<60<t<6 at which the drone’s horizontal direction changes from eastward to westward.

Part (c)
[2]

Calculate the total distance travelled by the drone from t=0t=0 to t=5t=5.

Part (d)
[2]

Justify whether the drone’s speed is increasing or decreasing at t=4t=4.

Part (e)
[1]

Interpret the horizontal motion of the drone immediately after the time found in part (b).

Question 2

Graphing calculator not permitted

The graph shows a continuous function gg. The curved portion from x=4x=4 to x=6x=6 is a semicircle of radius 11 lying below the xx-axis. Define

h(x)=3+0xg(t),dt\displaystyle h(x)=3+\int_0^x g(t),dt.

What is h(6)h(6)?

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A. 3π2\displaystyle 3-\frac{\pi}{2}

B. 5π2\displaystyle 5-\frac{\pi}{2}

C. 5+π2\displaystyle 5+\frac{\pi}{2}

D. 7π2\displaystyle 7-\frac{\pi}{2}

[1]
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Question 3

Graphing calculator required

The polar curve is defined by

r=2+sin(2θ)r=2+\sin(2\theta)

for 0θ2π0\leq\theta\leq2\pi. The region RR is bounded by the curve and the rays θ=0\theta=0 and θ=π2\theta=\frac{\pi}{2}. Point PP corresponds to θ=π4\theta=\frac{\pi}{4}. Round calculator results to three decimal places.

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Part (a)(i)
[1]

Calculate the rectangular coordinates of PP.

Part (a)(ii)
[2]

Calculate dydx\frac{dy}{dx} at PP.

Part (b)
[1]

Represent the line tangent to the polar curve at PP with an equation in xx and yy.

Part (c)(i)
[1]

Write an expression for the area of region RR.

Part (c)(ii)
[1]

Evaluate the area of region RR exactly.

Part (d)(i)
[1]

Write an expression for the length of the curve from θ=0\theta=0 to θ=π2\theta=\frac{\pi}{2}.

Part (d)(ii)
[1]

Approximate the length of this part of the curve.

Part (e)
[1]

Explain the direction in which the point on the curve is moving at PP as θ\theta increases.

Question 4

GRAPHING CALCULATOR NOT PERMITTED

A curve is defined parametrically by x=t2+1x=t^2+1 and y=t33ty=t^3-3t for t>0t>0. What is the value of dydx\frac{dy}{dx} at t=2t=2?

A. 32\frac{3}{2}

B. 94\frac{9}{4}

C. 33

D. 92\frac{9}{2}

[1]
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Question 5

Graphing calculator not permitted

A curve is defined parametrically by

x(t)=t33tx(t)=t^3-3t

and

y(t)=t2y(t)=t^2

for 2t2-2\leq t\leq2. Point PP corresponds to t=2t=\sqrt2.

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Part (a)(i)
[1]

Verify that the curve has a horizontal tangent at t=0t=0.

Part (a)(ii)
[2]

Verify that the curve has vertical tangents at t=1t=-1 and t=1t=1.

Part (b)(i)
[1]

Calculate dydx\frac{dy}{dx} at PP.

Part (b)(ii)
[2]

Calculate d2ydx2\frac{d^2y}{dx^2} at PP.

Part (b)(iii)
[1]

Determine whether the curve is concave up or concave down at PP.

Part (c)
[2]

Justify that on 1<t<21<t<2, yy can be treated as a differentiable function of xx and that this function is concave down.

Question 6

Graphing calculator not permitted

A ground robot moves along a path described by

x(t)=t2x(t)=t^2

and

y(t)=23t3y(t)=\frac23t^3

for 0t20\leq t\leq2, where position is measured in metres and time is measured in seconds. Point PP corresponds to t=1t=1.

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Part (a)
[2]

Calculate the velocity vector and acceleration vector at t=1t=1.

Part (b)
[2]

Represent the line tangent to the robot’s path at PP.

Part (c)
[2]

Calculate the total distance travelled from t=0t=0 to t=2t=2.

Part (d)
[2]

Determine the robot’s displacement vector and the magnitude of its displacement from t=0t=0 to t=2t=2.

Part (e)
[1]

Justify that the robot’s speed is increasing for 0<t20<t\leq2.

Question 7

Graphing calculator not permitted

The graph shows the polar curves

r=2cosθr=2\cos\theta

and

r=1r=1.

Region RR lies inside r=2cosθr=2\cos\theta and outside r=1r=1.

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Part (a)
[2]

Determine the two angles at which the curves intersect and that bound region RR.

Part (b)
[2]

Write an expression for the area of region RR.

Part (c)
[2]

Evaluate the area of region RR.

Part (d)
[2]

Calculate the slope of the line tangent to r=2cosθr=2\cos\theta at the upper intersection point.

Part (e)
[1]

Represent the tangent line at the upper intersection point with an equation in xx and yy.

Question 8

Graphing calculator not permitted

A particle has position r(t)=x(t),y(t)\mathbf r(t)=\langle x(t),y(t)\rangle for 0t40\leq t\leq4. The graph shows the velocity components x(t)x'(t) and y(t)y'(t). At t=0t=0, the particle is at (0,1)(0,1). Time is measured in seconds, position in metres, and velocity in m/s\mathrm{m/s}.

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Part (a)
[2]

Calculate the particle’s position at t=2t=2.

Part (b)
[2]

Represent x(t)x(t) and y(t)y(t) algebraically for 0t10\leq t\leq1.

Part (c)
[2]

Represent the portion of the particle’s path for 0t10\leq t\leq1 with a Cartesian equation relating xx and yy.

Part (d)
[2]

Calculate the particle’s average velocity vector on 0t40\leq t\leq4.

Part (e)
[1]

Interpret the particle’s motion at t=3.5t=3.5.

Question 9

Graphing calculator not permitted

A curve is defined parametrically by differentiable functions x(t)x(t) and y(t)y(t) for 2t4-2\leq t\leq4. The graph shows x(t)x'(t) and y(t)y'(t). Both component graphs are linear on each displayed segment.

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Part (a)(i)
[1]

Determine all values of tt at which the curve has a horizontal tangent.

Part (a)(ii)
[1]

Verify that the horizontal-tangent condition is satisfied at those times.

Part (b)(i)
[1]

Determine the value of tt at which the curve has a vertical tangent.

Part (b)(ii)
[1]

Verify that the vertical-tangent condition is satisfied at that time.

Part (c)
[3]

Justify whether the speed of the particle is increasing or decreasing at t=0t=0.

Part (d)(i)
[1]

Calculate d2ydx2\frac{d^2y}{dx^2} at t=0t=0.

Part (d)(ii)
[1]

Determine the concavity of the curve at t=0t=0.

Question 10

Graphing calculator not permitted

The polar curve is

r=1+cosθr=1+\cos\theta.

The shaded region RR is the part of the curve lying above the xx-axis. What is the area of RR?

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A. π2\displaystyle \frac{\pi}{2}

B. 3π4\displaystyle \frac{3\pi}{4}

C. 3π2\displaystyle \frac{3\pi}{2}

D. 2π\displaystyle 2\pi

[1]
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