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AP Calculus AB study notes

6.9.2 Indefinite Integrals Using Substitution

AP Syllabus focus:
‘Apply substitution of variables to find antiderivatives of functions by introducing a new variable u and rewriting the integrand in terms of u.’

Indefinite integrals using substitution allow students to reverse the chain rule by rewriting complex expressions in a simpler variable, enabling easier computation of antiderivatives in common calculus settings.

Indefinite Integrals Using Substitution

When functions appear in composite or nested forms, direct application of basic antiderivative rules may be difficult. The substitution method transforms an integral into an equivalent form that is easier to evaluate by temporarily replacing part of the expression with a new variable. This technique is essential for reversing the chain rule and lies at the heart of many AP Calculus AB integrals requiring symbolic manipulation.

The Purpose of Substitution

The main goal of substitution is to simplify the integrand by identifying an inner function whose derivative also appears within the expression. The new substitution variable, traditionally uu, allows the integrand to be rewritten in a more manageable form. Once the substitution is made, the integral resembles a basic antiderivative rule, which students can evaluate efficiently.

The Key Idea: Reversing the Chain Rule

Because differentiation applies the chain rule to composite functions, antidifferentiation often requires reversing it.

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This diagram summarizes the chain rule, showing how the derivative of a composite function is formed from derivatives of inner and outer functions. It supports the idea that uu-substitution reverses this structure to simplify integration. The symbolic layout includes slightly more detail than required but remains consistent with AP-level expectations. Source.

Substitution Method: A technique for evaluating indefinite integrals by defining a new variable to replace an expression, rewriting the differential accordingly, and integrating in the new variable.

The substitution method relies on the fundamental relationship between differentials. When uu is defined as a function of xx, the differential dudu expresses how uu changes with respect to xx. This relationship makes it possible to convert the integral into a form involving only uu and dudu instead of xx and dxdx.

The Structure of a Substitution

A well-chosen substitution has several components that must work together. Students should learn to check that each step is coherent before proceeding. A typical substitution involves:

  • Selecting a useful inner function as uu.

  • Computing dudu, which expresses the derivative of the substitution.

  • Rewriting the integrand completely in terms of uu and dudu.

  • Integrating using known formulas.

  • Re-substituting the original variable after integrating.

u=g(x) u = g(x)
u u = New variable defined to simplify the integrand

du=g(x),dx du = g'(x),dx
du du = Differential expressing how uu changes with respect to xx; dxdx = Differential of the original variable

After substitution, the integral typically becomes f(u),du\int f(u),du, which can then be integrated using standard antiderivative rules.

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This graph illustrates a function f(x)f(x) with the signed area between the curve and the axis, reinforcing that integrals measure accumulated change. It connects substitution-based antiderivatives to the geometric meaning of integration. The colored positive and negative regions offer additional context consistent with the AP treatment of definite integrals. Source.

A full substitution must replace every appearance of the original variable from the integrand. Students should avoid leaving any xx terms behind once the rewriting process begins. The entire integrand must match the new variable system before the integration step is performed.

Identifying When Substitution Is Appropriate

Substitution is most effective when the integrand contains a composite expression whose derivative is also present, either exactly or up to a constant multiple. Students should look for:

  • A function nested inside another function.

  • A derivative of the inner function appearing elsewhere in the integrand.

  • Expressions complicated enough that simpler antiderivative rules are insufficient.

  • Structures reminiscent of the chain rule in reverse.

These indicators help determine whether substitution will appropriately simplify the integral or whether another strategy is needed.

Steps for Using Substitution in Indefinite Integrals

The process for applying substitution is systematic and consistent. AP Calculus AB students should learn to follow these steps carefully to avoid common algebraic errors. A well-organized approach helps ensure that the rewritten integral is valid and solvable.

  • Choose an expression within the integrand to serve as uu.

  • Differentiate uu to compute dudu, expressing the differential in terms of dxdx.

  • Rewrite the entire integrand using uu and dudu, ensuring no remnants of xx remain.

  • Integrate the resulting expression with respect to uu using known antiderivative rules.

  • Replace uu with the original expression to return the integral to the variable xx.

  • Add the constant of integration CC, required for all indefinite integrals.

The Role of the Constant of Integration

Every indefinite integral must include the constant of integration CC, since antiderivatives differ by vertical shifts. Substitution does not change this requirement. Regardless of how complex the transformation may be, the final answer always represents one member of a family of functions, each differing only by this constant.

Constant of Integration: The arbitrary constant added to an antiderivative representing the entire family of functions whose derivative equals the integrand.

FAQ

Choose the expression whose derivative appears most clearly elsewhere in the integrand. This ensures the algebraic rewriting step is straightforward.

If more than one candidate seems plausible:
• Select the inner part of a composite function first.
• Prefer choices that reduce the integrand to a standard form such as a power or a trigonometric expression.
• Avoid choosing expressions that complicate du or make it impossible to eliminate x fully.

Leaving any x terms in the rewritten integral creates two variable systems at once, which makes the integral invalid.

Every valid substitution depends on treating u as the sole variable during integration. If x remains:
• The relationship between u and du cannot be applied consistently.
• The resulting antiderivative would not differentiate back to the original integrand.

Yes. You may factor out constants or rearrange algebraically to achieve a match.

For example, if du is a constant multiple of what appears in the integrand, you can compensate by multiplying or dividing by that constant.

Substitution only fails if du and the integrand share no meaningful relationship.

The effectiveness of substitution depends on how closely the integrand resembles the chain rule structure.

Strong candidates:
• Have a clear inner–outer relationship.
• Display the inner derivative multiplied somewhere in the integrand.
• Reduce to a standard antiderivative after rewriting.

Weaker candidates require more algebra and may not simplify enough to be useful.

Students often forget to replace u with its original expression before adding the constant of integration.

This matters because:
• Leaving the answer in terms of u is incomplete unless the question explicitly permits it.
• Evaluating initial conditions, graphing, or interpreting the antiderivative requires the result to be back in terms of x.

Practice Questions

Question 1 (1–3 marks)
Evaluate the indefinite integral:
∫ (6x + 4)(x² + 4x + 1)³ dx
Use substitution.

Question 1 (1–3 marks)
• 1 mark: Correct substitution such as u = x² + 4x + 1 and du = (2x + 4) dx or equivalent manipulation.
• 1 mark: Rewriting the integral fully in terms of u and du.
• 1 mark: Correct final antiderivative, for example (3/2)(x² + 4x + 1)⁴ + C or any equivalent form.

Question 2 (4–6 marks)
Let f(x) = cos(3x + 5).
(a) Use substitution to find the indefinite integral ∫ f(x) dx.
(b) Hence find the general solution y to the differential equation dy/dx = cos(3x + 5).
(c) Given that y = 2 when x = 0, find the particular solution.

Question 2 (4–6 marks)
(a)
• 1 mark: Correct substitution such as u = 3x + 5 and du = 3 dx.
• 1 mark: Rewriting the integral as (1/3) ∫ cos(u) du.
• 1 mark: Correct antiderivative (1/3) sin(3x + 5) + C.

(b)
• 1 mark: Stating the general solution y = (1/3) sin(3x + 5) + C.

(c)
• 1 mark: Correct substitution of x = 0 and y = 2 into the general solution.
• 1 mark: Solving for C and giving the particular solution y = (1/3) sin(3x + 5) + final constant.

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