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AP Chemistry Notes

8.1.4 Neutral water, pKw, and temperature effects

AP Syllabus focus: ‘In pure neutral water at 25 °C, pH = pOH = 7.0 and pKw = 14.0; because Kw depends on temperature, neutral pH differs from 7.0 at other temperatures.’

Pure water is not chemically “inactive”: it self-ionizes slightly, and the extent of that ionization changes with temperature.

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Diagram of water autoprotolysis (autoionization): two water molecules exchange a proton to form hydronium, H3O+H_3O^+, and hydroxide, OHOH^-. The figure makes it explicit that both ions are produced simultaneously, so in pure water their concentrations are equal at neutrality. This equilibrium underlies the definition of Kw=[H3O+][OH]K_w = [H_3O^+][OH^-]. Source

This shifts Kw, pKw, and therefore the pH of neutral water away from 7.00 except at 25 °C.

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Temperature dependence of water’s ionization constant (KwK_w) shown as a plotted trend versus temperature. As temperature changes, the autoionization equilibrium shifts, so KwK_w does not remain fixed at 1.0×10141.0\times10^{-14}. This is why the neutral-point pH is not always 7.00. Source

Neutral water at 25 °C

What “neutral” means (and what it does not mean)

Neutrality is defined by equal hydronium and hydroxide concentrations, not by a fixed pH value.

Neutral solution: a solution in which [H3O+]=[OH][H_3O^+] = [OH^-] (so there is no net acidic or basic character).

At 25 °C, that equality happens to correspond to pH = 7.0 and pOH = 7.0, but that numerical value is temperature-specific.

The role of pKw at 25 °C

The equilibrium constant for water’s autoionization is Kw, and its logarithmic form pKw is often used to connect acidity and basicity on the pH scale. At 25 °C, pKw = 14.0, which is consistent with neutral water having equal pH and pOH values.

pKw=log(Kw) pK_w = -\log(K_w)

pKw pK_w = negative base-10 logarithm of KwK_w (unitless)

Kw K_w = water ion-product constant (unitless, defined in terms of concentrations for AP-level work)

Because neutral water has [H3O+]=[OH][H_3O^+] = [OH^-], the neutrality condition links directly to pKw: when the two ion concentrations are equal, their p-notation values are equal as well (pH = pOH). At 25 °C, that shared value is 7.0 because pKw is 14.0.

Why neutral pH changes with temperature

Kw depends on temperature

The syllabus requirement is that you understand this relationship qualitatively: Kw depends on temperature, so the pH of neutral water differs from 7.0 at other temperatures. In other words, “neutral” does not mean “pH 7” unless the temperature is 25 °C.

A temperature change alters the position of the autoionization equilibrium for water. When Kw changes, the product [H3O+][OH][H_3O^+][OH^-] changes, and the “equal-ion” point (neutrality) shifts to a different numerical pH.

pKw is the temperature-sensitive reference point

Because pKwpK_w is defined from KwK_w, it also varies with temperature. That matters because the numerical relationship between pH and pOH is anchored to pKw, not automatically to 14.

pH+pOH=pKw pH + pOH = pK_w

pH pH = log[H3O+]-\log[H_3O^+] (unitless)

pOH pOH = log[OH]-\log[OH^-] (unitless)

pKw pK_w = temperature-dependent sum of pHpH and pOHpOH (unitless)

When temperature changes:

  • KwK_w changes

  • therefore pKwpK_w changes

  • therefore the neutral-point condition pH = pOH = 12pKw\tfrac{1}{2}pK_w shifts

  • so neutral pH is not necessarily 7.00

Interpreting “neutral” across temperatures (AP expectation)

For AP Chemistry, focus on these takeaways:

  • At 25 °C (the standard reference temperature), neutral water has pH = pOH = 7.0 and pKw = 14.0.

  • At other temperatures, you should not assume pH 7 indicates neutrality.

  • If you are given a non-25 °C value of Kw or pKw, neutrality is found by enforcing [H3O+]=[OH][H_3O^+] = [OH^-] (equivalently, pH = pOH) and using the temperature-appropriate pKw.

FAQ

Water’s autoionisation is endothermic overall.

Increasing temperature favours products, increasing $K_w$; decreasing temperature lowers $K_w$.

No.

“Neutral” only describes $[H_3O^+] = [OH^-]$; it says nothing about toxicity, oxidising power, or other reactivity.

It comes from using concentration-based expressions in practice.

Strictly, equilibrium constants are defined using activities (unitless); concentrations are an approximation.

Electrode response depends on temperature, so meters use temperature compensation.

Without compensation, the displayed pH can drift even if the chemical composition is unchanged.

The definition $pH = -\log[H_3O^+]$ does not change.

What changes is the reference point for neutrality, because $K_w$ (and thus $[H_3O^+]$ in pure water) changes with temperature.

Practice Questions

(2 marks) State the pH of pure neutral water at 25,C25,^\circ\mathrm{C} and state the value of pKwpK_w at 25,C25,^\circ\mathrm{C}.

  • pH =7.0= 7.0 (1)

  • pKw=14.0pK_w = 14.0 (1)

(5 marks) At 40,C40,^\circ\mathrm{C}, Kw=2.9×1014K_w = 2.9 \times 10^{-14}. Determine the pH of neutral water at this temperature. Show your working.

  • Uses neutrality: [H3O+]=[OH][H_3O^+] = [OH^-] (1)

  • Sets [H3O+]2=Kw[H_3O^+]^2 = K_w (1)

  • Finds [H3O+]=2.9×1014[H_3O^+] = \sqrt{2.9 \times 10^{-14}} (1)

  • Computes pH=log[H3O+]pH = -\log[H_3O^+] (1)

  • Final pH (\approx 6.77) (allow suitable rounding) (1)

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