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AP Physics 2: Algebra Notes

1.2.2 Pressure, Volume, Temperature, and Amount of Gas

AP Syllabus focus: 'An ideal gas relates pressure, volume, number of moles or atoms, and temperature using PV = nRT = NkBT.'

The ideal gas law connects the measurable properties of a gas in one compact relationship. For AP Physics 2, it is the main tool for predicting how pressure, volume, temperature, and gas amount change together.

Ideal gas law: A model relationship that connects a gas’s pressure, volume, temperature, and amount of gas.

This single law gives a compact way to describe a gas state and to predict how that state changes when one or more variables are altered.

The ideal gas relationship

An ideal gas is described by four macroscopic quantities: pressure, volume, temperature, and amount of gas. If one of these changes, at least one other quantity must also change unless gas is added or removed.

PV=nRT=NkBTPV=nRT=Nk_BT

PP = pressure, measured in pascals, PaPa

VV = volume, measured in cubic meters, m3m^3

nn = amount of gas, measured in moles, molmol

RR = ideal gas constant, 8.31 J/(molK)8.31\ J/(mol\cdot K)

NN = number of atoms or molecules

kBk_B = Boltzmann constant, 1.38×1023 J/K1.38\times 10^{-23}\ J/K

TT = absolute temperature, measured in kelvins, KK

The two forms express the same physics. Use PV=nRTPV=nRT when the amount of gas is given in moles, and use PV=NkBTPV=Nk_BT when the amount is given as a number of particles.

Meaning of the variables

Pressure and volume

Pressure describes how strongly a gas pushes on its container.

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A kinetic-theory diagram showing a molecule colliding elastically with a container wall and reversing its perpendicular momentum component. The image illustrates how many such collisions produce a measurable force per area (pressure), and why higher particle speed (temperature) or more particles increases pressure. Source

Volume is the space available to the gas. For a fixed amount of gas at a fixed temperature, pressure and volume are inversely related.

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Boyle’s law data shown as (a) a hyperbolic PP vs. VV curve and (b) a linear plot using an inverse variable. It reinforces that at constant nn and TT, decreasing volume increases pressure so that PVPV remains constant for the same gas sample. Source

If the gas is compressed into a smaller volume, its pressure increases. If the volume increases, its pressure decreases. In proportional form, this is P1/VP\propto 1/V when nn and TT are constant.

This inverse relationship matters in many AP problems because an expansion or compression changes the gas state even when no gas is added and no gas is removed.

Temperature and amount of gas

In gas-law problems, temperature must be an absolute temperature, so it must be written in kelvins, not degrees Celsius. Ratios such as T2/T1T_2/T_1 only make physical sense when temperature is measured from an absolute zero point.

For a fixed amount of gas at constant volume, pressure is directly proportional to temperature: PTP\propto T. Heating the gas raises the pressure because the same gas remains in the same space while its temperature increases.

For a fixed amount of gas at constant pressure, volume is directly proportional to temperature: VTV\propto T. Heating the gas then causes it to occupy more space.

The amount of gas can be expressed as moles, nn, or as the number of atoms or molecules, NN. If temperature and volume stay constant, increasing the amount of gas increases the pressure. If pressure and temperature stay constant, adding more gas requires a larger volume.

Using the two forms of the law

The form PV=nRTPV=nRT is usually most convenient when a problem gives the gas amount in moles. The form PV=NkBTPV=Nk_BT is more useful when the problem refers to individual atoms or molecules.

A key idea is that the gas type does not appear directly in the equation. If two different gases are both treated as ideal, the same mathematical relationship applies to both. What matters is the gas state: pressure, volume, temperature, and amount.

Rearranging the ideal gas law

You should be comfortable solving the ideal gas law for any variable. For example, pressure can be written as P=nRT/VP=nRT/V, volume as V=nRT/PV=nRT/P, and temperature as T=PV/(nR)T=PV/(nR). The equation is the same physical law in each case; only the unknown changes.

When the same sample of gas changes from one state to another without any change in gas amount, the law can be compared between two states as P1V1/T1=P2V2/T2P_1V_1/T_1=P_2V_2/T_2. This is useful because the constants cancel, leaving a direct relationship among initial and final conditions.

Proportional reasoning

Many AP questions can be answered without full substitution. If VV and nn are constant, doubling TT doubles PP. If PP and nn are constant, tripling TT triples VV. If TT and VV are constant, doubling nn doubles PP.

This kind of reasoning is especially helpful on conceptual questions. The ideal gas law combines several simpler gas relationships into one statement, so it lets you predict whether a quantity should increase, decrease, or remain unchanged before doing any algebra.

Problem-solving approach

Start by identifying which quantities are known and which one must be found. Then determine whether the gas amount stays constant or changes. After that, decide whether a direct substitution into PV=nRTPV=nRT is best or whether a comparison between two states is simpler.

This prevents common mistakes, such as treating Celsius values as if they were absolute temperatures or assuming that pressure and volume can change independently when the amount of gas and temperature are fixed.

Units and careful setup

Correct units matter. In AP Physics, the safest choice is to use SI units:

  • pressure in PaPa

  • volume in m3m^3

  • temperature in KK

  • amount in molmol when using RR

If a problem gives volume in liters or pressure in kilopascals, convert carefully before substituting unless a consistent constant is provided. The ideal gas law is algebraically simple, so many errors come from units and setup rather than from the physics itself.

FAQ

The ideal gas law uses absolute temperature, not a relative scale. Kelvin starts at absolute zero, so a value like $200\ K$ is physically twice $100\ K$ in a way that $200^\circ C$ is not twice $100^\circ C$.

If Celsius were used directly, ratios and proportional relationships would give incorrect results. That is why AP Physics gas-law calculations always require converting to $K$ first.

The variable $n$ counts gas amount in moles, while $N$ counts the actual number of particles. They are related by $N=nN_A$, where $N_A$ is Avogadro’s number.

Because of that, the constants are also related: $R=N_Ak_B$. So $PV=nRT$ and $PV=Nk_BT$ are not different laws; they are two versions of the same relationship.

First convert the mass to moles using the molar mass: $n=m/M$, where $m$ is the sample mass and $M$ is the molar mass.

Once you have $n$, substitute it into $PV=nRT$. This is common when the problem gives a chemical identity, such as helium or oxygen, along with a sample mass.

Yes. If two gases have the same $P$, $V$, and $T$, then they have the same number of moles according to the ideal gas law.

However, equal moles do not always mean equal mass. A mole of a heavier gas has more mass than a mole of a lighter gas, so the samples can match in gas-law variables while still having different masses.

The ideal gas law requires absolute pressure, because zero pressure in the equation means no pressure at all, not just no pressure above atmospheric pressure.

If a gauge pressure is given, add atmospheric pressure first: $P_{absolute}=P_{gauge}+P_{atmospheric}$. Then use that absolute pressure in $PV=nRT$.

Practice Questions

A rigid container of volume 0.020 m30.020\ m^3 holds 1.0 mol1.0\ mol of an ideal gas at 300 K300\ K. Calculate the gas pressure. Use R=8.31 J/(molK)R=8.31\ J/(mol\cdot K).

  • 1 mark for using P=nRT/VP=nRT/V

  • 1 mark for a correct answer of 1.25×105 Pa1.25\times 10^5\ Pa or equivalent

A sample of ideal gas occupies 2.0×103 m32.0\times 10^{-3}\ m^3 at a pressure of 1.2×105 Pa1.2\times 10^5\ Pa and a temperature of 300 K300\ K.

(a) Determine the number of moles of gas in the sample.

(b) The gas is heated to 450 K450\ K while the pressure remains constant. Determine the new volume.

(c) State whether the number of atoms in the sample changes during this process. Justify your answer.

Use R=8.31 J/(molK)R=8.31\ J/(mol\cdot K).

  • (a) 1 mark for using n=PV/(RT)n=PV/(RT)

  • (a) 1 mark for n=9.6×102 moln=9.6\times 10^{-2}\ mol or equivalent

  • (b) 1 mark for recognizing that at constant pressure VTV\propto T or using V2/V1=T2/T1V_2/V_1=T_2/T_1

  • (b) 1 mark for V2=3.0×103 m3V_2=3.0\times 10^{-3}\ m^3

  • (c) 1 mark for stating that the number of atoms does not change because the same gas sample is being heated, with no gas added or removed

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