AP Syllabus focus:
‘If f′(c)=0 but f″(c)=0 or does not exist, the Second Derivative Test is inconclusive, and another method, such as the First Derivative Test, must be used.’
This shows why the Second Derivative Test can fail to classify a point and how to proceed when curvature information is insufficient for determining behavior.
When the Second Derivative Test Fails
Understanding when the Second Derivative Test becomes inconclusive is essential because not all critical points behave predictably under curvature analysis. Although the test often provides a quick way to classify extrema, some functions have points where second‐derivative information is too weak or unavailable to reveal local behavior. In such cases, AP Calculus AB students must rely on alternative derivative-based strategies.
A critical point is an -value where or where does not exist, provided the value is in the domain of the original function.
Critical Point: A point where or where is undefined, as long as the point lies in the domain of .
The Second Derivative Test attempts to classify these points by evaluating the sign of , but this method relies heavily on the existence and nonzero value of the second derivative. When those conditions fail, the test becomes inconclusive.
Why the Second Derivative May Be Inconclusive
There are two primary reasons this loss of reliability occurs:
1. The Second Derivative Equals Zero
If and , the second derivative provides no curvature information. A zero second derivative means the graph may be flattening, but that flattening could correspond to many different shapes.
Situations that can produce this outcome include:
Higher-order flatness, where several derivatives vanish before curvature appears.
Horizontal points of inflection, where the graph flattens but does not change direction.
Symmetric or balanced behavior, where competing tendencies cancel out at the point.
This situation forces us to avoid relying on second-derivative curvature cues because they cannot distinguish between a minimum, maximum, or neither.
If f′(c)=0 and f″(c)=0, the second derivative provides no curvature information at x=c, so the test cannot tell whether c is a max, min, or neither.

A cubic function is plotted in black with its first derivative shown in red and second derivative in blue. The labeled local maximum, local minimum, and inflection point illustrate how may correspond to different behaviors. This demonstrates why the Second Derivative Test is inconclusive when both and . Source.
2. The Second Derivative Does Not Exist
If but does not exist, the Second Derivative Test cannot be applied. This occurs when:
The graph has a sharp flattening or cusp-like behavior in .
The function’s rate of change changes abruptly, preventing differentiation.
The curvature is undefined or infinite.
Even though shows a horizontal tangent line, the missing curvature information makes the standard test unsuitable.
Revisiting the Structure of the Second Derivative Test
The essence of the test depends on evaluating the concavity at a critical point. Concavity for AP Calculus AB purposes relies on the sign of the second derivative.
Concavity: A function is concave up where f″(x)>0 and concave down where f″(x)<0 on an interval.
Normal sentence here to provide explanatory continuity. When either issue arises, no reliable curvature-based classification can occur, which is exactly what makes the test inconclusive.
How to Proceed After the Test Fails
Once students recognize that the Second Derivative Test breaks down, they must shift to a different method. The AP specification emphasizes the First Derivative Test as the primary backup strategy.
Using the First Derivative Test After Inconclusiveness
The First Derivative Test analyzes sign changes in the first derivative around the critical point and is more broadly applicable because it does not require smoothness beyond the existence of on intervals around the point.
To apply this test:
Identify the critical point where the Second Derivative Test failed.
Determine intervals directly to the left and right of that point.
Evaluate the sign of on each interval.
Interpret the change (or lack of change) to classify behavior.
This process is effective because increasing and decreasing behavior provides direct evidence of local maxima or minima.
Additional Indicators When Needed
When both curvature and sign-chart methods seem unclear, students can turn to additional information, including:
Local graph behavior, when graphical representations are provided.
Derivative tables, which summarize the sign of across key points.
Contextual smoothness assumptions, such as knowing the function is polynomial.
However, these are only secondary aids; the primary fallback remains the First Derivative Test.
Why the Inconclusive Case Matters
The inconclusive scenario highlights an important conceptual point in calculus: higher-order derivatives provide information about shape, but they do not always tell the full story. A function may appear flat at a point, yet its behavior on either side determines the actual extremum classification. AP Calculus students must therefore be comfortable switching analytical tools when necessary.
Understanding this limitation strengthens students’ conceptual grasp of derivative-based analysis and reinforces that no single test works universally.
Key Takeaways for AP Students
The Second Derivative Test can only classify a critical point when and .
If or does not exist, curvature information is insufficient.
In such cases, the First Derivative Test provides the required classification method.
Recognizing when a method fails is just as important as knowing when it succeeds.
When the Second Derivative Test is inconclusive, we return to the First Derivative Test and analyze sign changes in f′ or use graphs and tables to understand the function’s behavior near c.

The graph displays a continuous second derivative that touches the -axis at while remaining positive elsewhere. Because without a change of sign, the Second Derivative Test cannot classify the critical point. Examining instead provides the needed information about slope changes to determine the point’s behavior. Source.
FAQ
Yes. An inconclusive result only means the Second Derivative Test cannot classify the point.
If the function is defined on a closed interval, the point may still be an absolute maximum or minimum after comparing function values at:
Critical points
Endpoints of the interval
This requires evaluating the original function, not just its derivatives.
A zero second derivative is only a necessary condition for an inflection point, not a sufficient one.
For an inflection point to exist:
The concavity must change on either side of the point
If concavity remains the same, the point is not an inflection point, even though the second derivative is zero.
Yes. If the second derivative does not exist at a critical point, the test cannot be applied.
This often happens when:
The function is not smooth enough
The first derivative has a sharp change in behaviour
In such cases, other methods must be used to analyse the function.
The First Derivative Test directly examines how the function behaves on either side of a critical point.
It works whenever:
The first derivative exists on intervals around the point
Because it focuses on increasing and decreasing behaviour, it remains effective even when curvature information is unavailable.
Yes. Even though polynomials are smooth and differentiable everywhere, they can have critical points where the second derivative is zero.
This typically occurs with:
Higher-degree polynomials
Horizontal points of inflection
In these cases, additional derivative analysis is required to determine the nature of the point.
Practice Questions
Question 1 (2 marks)
A function f is twice differentiable for all real x. It is given that f′(2) = 0 and f″(2) = 0.
(a) State what the Second Derivative Test concludes about the nature of f at x = 2.
(b) Name one method that could be used instead to determine whether x = 2 is a local maximum, a local minimum, or neither.
Mark Scheme for Question 1 (2 marks)
(a) Award 1 mark for stating that the Second Derivative Test is inconclusive at x = 2 because the second derivative is zero.
(b) Award 1 mark for correctly naming an alternative method, such as the First Derivative Test or analysing the sign of f′(x) on either side of x = 2.
Question 2 (5 marks)
A function g is defined on an interval containing x = 1. The derivative g′(x) exists for all x in this interval, and the second derivative g″(x) exists except possibly at x = 1.
You are given that:
g′(1) = 0
g″(1) = 0
g′(x) is negative for x < 1 and positive for x > 1
(a) Explain why the Second Derivative Test cannot be used to classify the point at x = 1.
(b) Use the information about g′(x) to determine the nature of the point at x = 1.
(c) Justify your conclusion using correct calculus reasoning.
Mark Scheme for Question 2 (5 marks)
(a) Award 1 mark for stating that the Second Derivative Test is inconclusive because g″(1) = 0, so it gives no information about concavity at x = 1.
(b) Award 2 marks for correctly identifying that g changes from decreasing to increasing at x = 1 and therefore has a local minimum at x = 1.
1 mark for recognising the sign change in g′(x).
1 mark for correctly naming the nature of the point.
(c) Award 2 marks for a clear justification using the First Derivative Test, explaining that:
g′(x) < 0 for x < 1 implies g is decreasing to the left of x = 1.
g′(x) > 0 for x > 1 implies g is increasing to the right of x = 1.
Full marks require correct terminology and a logically structured explanation.
