AP Syllabus focus:
‘Determine appropriate units for an accumulated change, understanding that the units of area under a rate graph equal (units of rate) × (units of the independent variable).’
This subsubtopic emphasizes how units behave when interpreting area under a rate function, helping students understand why accumulated change carries compound units determined by both the rate and the horizontal axis.
Understanding Units in Accumulated Change
Interpreting accumulated change begins with recognizing that a rate function expresses how one quantity changes with respect to another. When you take the area under a rate graph, you are effectively summing tiny contributions of rate multiplied by time or another independent variable. This creates new, combined units that describe the total change of the quantity being measured.
The Structure of a Rate Function
A rate is a quantity that compares how one variable changes relative to another, such as velocity (meters per second) or flow rate (liters per minute). These forms always carry the unit pattern “units of output per unit of input.”
Rate: A function whose units represent the amount of change in one quantity per unit change in another quantity, typically expressed as output units divided by input units.
When this rate is graphed against its input variable on the horizontal axis, the area between the graph and the axis represents accumulated change.

This graph plots velocity on the vertical axis and time on the horizontal axis, with the shaded area representing the object’s displacement. The units of the shaded area are “velocity units × time units,” matching the accumulated change in position. The graph also hints at acceleration as the slope of the line, which is extra context beyond this subsubtopic but consistent with later calculus and physics applications. Source.
Understanding the independent variable ensures that students correctly associate the width of the “rectangles” in a Riemann sum with the appropriate units, allowing accurate unit multiplication.
Why Area Produces Combined Units
The area under a rate graph is computed conceptually as the sum of infinitely many products: each small rectangle has height equal to the rate value and width equal to a small change in the independent variable.

This figure shows a function with several narrow rectangles whose heights are function values and whose widths are . The total area under the curve is approximated by summing the areas , which combines “output units per input unit” with “input units” to produce the units of accumulated change. The surrounding text on the source page discusses limits and definite integrals, which goes beyond this subsubtopic, but the visual itself is focused on the geometric idea of rate times interval length. Source.
Multiplying these produces units that immediately reflect accumulated change.
= Output units per unit of input
= Units along the horizontal axis
This expression shows that area is not merely a geometric concept; it becomes a meaningful physical or contextual quantity when applied to rate functions.
It is important for students to see that accumulated change always inherits its units directly from the structure of the rate itself and the variable being accumulated over.
Identifying Units in Applied Settings
Determining Units from Rate Information
To correctly identify accumulated change units, students should analyze both components of the rate expression. If the rate is stated verbally, graphically, or algebraically, the same principles apply.
Use the following guidelines when determining units:
Identify the output variable of the rate (such as distance, volume, mass, or population).
Identify the input variable with respect to which the rate is measured (such as time, position, or temperature).
Combine these units as
(units of output per unit of input) × (units of input)
Cancel matching units so that the final unit expresses the total amount of the output quantity accumulated.
Each of these steps reinforces the idea that accumulated change is an interpretation of area that intrinsically reflects the context of the rate and the domain.
The Role of the Independent Variable
The independent variable plays a critical role because it provides the dimension across which accumulation occurs. When the independent variable changes, even if the rate remains the same, the units of accumulated change adjust proportionally.
Independent Variable: The variable placed on the horizontal axis that determines the input to a function, influencing the interpretation of units and accumulation.
A normal sentence follows here to maintain required spacing before any equation or definition block appears again.
Interpreting Accumulated Change in Context
Correct unit interpretation is essential when describing changes in real-world systems. Because the accumulated change measures a total quantity, its units tell you exactly what has increased or decreased. Units guide interpretation in several ways:
They indicate what quantity is being accumulated (e.g., miles, gallons, dollars).
They reveal how the quantity changes over the interval (e.g., total distance traveled, total water added, total cost accrued).
They clarify the relationship between rate and accumulation by showing how instantaneous behavior aggregates over time or another dimension.
They prevent conceptual mistakes, such as confusing the rate itself with the accumulated amount.
Units as a Tool for Verification
Using units provides a powerful method for checking whether interpretations of area make sense. When evaluating the meaning of an integral of a rate function:
Ensure that the resulting units correspond to a total amount, not a rate.
Compare the units of the integrand and the variable of integration to confirm that the product produces an appropriate, contextually meaningful quantity.
Use the units to verify whether graphical or numerical approximations of accumulated change reflect the intended physical interpretation.
This attention to units ensures consistency when applying integration to real-world problems and reinforces the conceptual meaning of accumulation in AP Calculus AB.
FAQ
The area represents a net accumulated change because the graph may lie above or below the horizontal axis. Positive regions increase the total, while negative regions reduce it.
If the rate is always positive, the area corresponds to a total amount gained. If the rate changes sign, the area reflects the balance of gains and losses.
Yes. Because units combine through multiplication, the final units may be a compound unit not explicitly stated.
For example, a rate in kilograms per metre accumulated over metres produces kilograms, a unit that may not be mentioned until the interpretation stage.
The method is identical regardless of the input variable.
You simply multiply:
• units of rate (output per input)
• units of the independent variable
If the input is temperature, angle, or position, the accumulated units reflect the total change corresponding to that variable.
Dimensional consistency ensures that the quantity you interpret matches what the real-world context describes.
If units are mismatched, the computed area might have meaningless or unusable units. Correct unit conversion before interpreting the area prevents conceptual errors.
This can happen if the rate is defined with unconventional or incompatible units.
If the vertical and horizontal axes measure unrelated quantities, multiplying the units may produce a composite that does not correspond to any real physical measurement.
Such situations usually indicate that the model or rate definition needs re-evaluation.
Practice Questions
Question 1 (1–3 marks)
The graph of a rate function r(t), measured in litres per minute, is shown for 0 ≤ t ≤ 5. The area under the graph from t = 0 to t = 5 is 18 square units.
(a) State the units of the accumulated change represented by this area.
(b) Explain briefly why these are the correct units.
Question 1
(a) 1 mark
• Correct units: litres.
(b) 1–2 marks
• States that the rate has units litres per minute (1 mark).
• Explains that multiplying litres per minute by minutes gives litres, matching the accumulated amount (1 mark).
Total: 2–3 marks.
Question 2 (4–6 marks)
A car’s velocity v(t) is measured in metres per second, where t is the time in seconds. A graph of v(t) is provided for 0 ≤ t ≤ 10, and the area enclosed by the graph and the time axis over this interval is 42 square units.
(a) Determine the units of the accumulated change represented by this area.
(b) Interpret the meaning of this accumulated change in the context of the motion of the car.
(c) The rate function is measured incorrectly in kilometres per hour while t is still measured in seconds. Explain how the units of the accumulated change would change, and describe what this tells you about unit consistency when interpreting area.
Question 2
(a) 1 mark
• Correct units: metres.
(b) 1–2 marks
• Identifies the accumulated change as total displacement or distance travelled (1 mark).
• Explains that velocity multiplied by time gives distance in metres (1 mark).
(c) 2–3 marks
• Correctly states that using kilometres per hour with seconds gives inconsistent units (1 mark).
• Explains that the area would produce units of kilometres times seconds per hour (1 mark).
• Interprets that this inconsistency shows the need to convert units before interpreting accumulated change (1 mark).
Total: 4–6 marks.
