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AP Calculus AB study notes

6.12.1 Decomposing Rational Functions into Linear Factors

AP Syllabus focus:
‘Decompose certain rational functions into sums of fractions whose denominators are nonrepeating linear factors, preparing each term for basic integration rules.’

Decomposing rational functions into simpler fractional components allows integrals to be evaluated efficiently by reducing complex expressions into basic, easily integrable forms using familiar antiderivative rules.

Decomposing Rational Functions into Linear Factors

This subsubtopic focuses on rewriting a rational function—a quotient of two polynomials—into a sum of simpler fractions whose denominators are nonrepeating linear factors, enabling the use of basic integration formulas. Decomposition is foundational for integrating rational functions and prepares expressions for techniques used later in AP Calculus AB.

A rational function is typically expressed as P(x)Q(x) \frac{P(x)}{Q(x)} , where both PP and QQ are polynomials.

Pasted image

This figure displays a rational function in its original, undecomposed form, illustrating the starting point before splitting into simpler components. The example shown may include coefficients or factors beyond the simplest nonrepeating linear-factor cases required here. Source.

When Q(x)Q(x) factors into distinct linear terms, the original expression can be expanded into a sum of fractions, each with a simpler structure. This conversion turns an otherwise challenging integral into a sum of approachable components.

Understanding the Structure of Rational Functions

When a denominator can be factored into nonrepeating linear factors, each factor contributes a corresponding term to the decomposition. The goal is to isolate numerators that are constants, allowing direct application of basic antiderivative formulas.

Linear Factor: A polynomial factor of the form ax+bax + b with a0a \neq 0, representing a first-degree expression.

A rational function is suitable for decomposition only when the degree of the numerator is strictly less than the degree of the denominator. If this condition is not met, algebraic manipulation is necessary before beginning decomposition.

Ensuring Proper Form Before Decomposition

Before decomposing, confirm that the rational function is in proper form—meaning the numerator’s degree is lower than the denominator’s degree. If the numerator is of equal or higher degree, algebraic long division must be performed first to rewrite the rational function into a sum of a polynomial and a proper rational portion to decompose.

Once the function is confirmed to be proper, factor the denominator fully. Only nonrepeating (distinct) linear factors are handled in this subsubtopic.

Structure of Partial Fraction Decomposition

When the denominator consists of several distinct linear factors, the rational function decomposes into a sum of constants over those factors. This structure is predictable and follows a consistent form.

Standard Decomposition Form

For a rational function with denominator factored as (xa1)(xa2)(xa3)(x - a_1)(x - a_2)(x - a_3)\dots, the decomposition takes the shape:

P(x)(xa1)(xa2)(xan)=A1xa1+A2xa2++Anxan \frac{P(x)}{(x-a_1)(x-a_2)\dots(x-a_n)} = \frac{A_1}{x-a_1} + \frac{A_2}{x-a_2} + \dots + \frac{A_n}{x-a_n}
Ai A_i = Constant chosen so that the decomposition matches the original function

Each AiA_i is a constant that ensures the equality holds for all xx in the domain of the function.

Pasted image

This figure shows a rational function expressed as a sum of simpler fractions after decomposition, illustrating the general structure P(x)(xa1)(xa2)(xan)=A1xa1+A2xa2++Anxan\frac{P(x)}{(x-a_1)(x-a_2)\dots(x-a_n)} = \frac{A_1}{x-a_1} + \frac{A_2}{x-a_2} + \dots + \frac{A_n}{x-a_n}. The specific numerical details reflect one particular example and may extend slightly beyond the minimal cases emphasized here. Source.

The constants are determined algebraically. This predictable structure is essential preparation for integration because each resulting term aligns with known antiderivatives involving logarithmic functions.

The Purpose of Decomposition

Decomposition simplifies a complex rational integrand so that each resulting term can be integrated using basic integration rules. This subsubtopic does not require students to carry out the integration; instead, the emphasis lies in setting up the expression correctly so that integration becomes straightforward.

Key benefits include:

  • Transforming complicated rational expressions into simpler parts

  • Revealing integrable structures hidden within algebraic complexity

  • Preparing functions for integration without applying advanced techniques

Conditions for Applying Partial Fraction Decomposition

Students must recognize when decomposition is possible and appropriate. The essential conditions are:

  • The denominator must factor completely into nonrepeating linear factors.

  • The numerator must be of lower degree than the denominator.

  • The function must be expressed as a proper rational expression before decomposing.

  • Decomposition must assign one constant per linear factor.

Proper Rational Expression: A rational expression whose numerator degree is strictly less than the denominator degree.

Meeting these conditions guarantees that decomposition is valid and yields a set of simplified fractions ready for integration.

Steps for Decomposing into Linear Factors

When approaching decomposition in AP Calculus AB, focus on recognizing structure and setting up the correct form rather than solving for constants computationally.

Key steps include:

  • Factor the denominator completely into distinct linear factors.

  • Check that the expression is a proper rational function; if not, divide first.

  • Assign a constant numerator to each linear factor.

  • Rewrite the function as a sum of these fractions.

  • Confirm that the decomposition structure aligns with the original rational expression.

These steps ensure students can identify when decomposition is the correct strategy and how to prepare an integrand for later calculations using basic integration rules.

FAQ

Factoring the denominator reveals the structure of its linear components, allowing each distinct linear factor to be paired with its own constant numerator in the decomposition.

Without fully factoring, it is impossible to know how many partial fractions are required or what form they should take, since each factor corresponds to a separate term.

Check whether the denominator can be written as a product of first-degree expressions with no repeated roots.

A quick process is:
• Factor the denominator.
• Verify all factors are linear and distinct.
• Ensure the numerator has lower degree.

If all three conditions hold, the function fits this subsubtopic.

Each constant represents an unknown coefficient needed to reconstruct the original rational function when the terms are combined.

These constants ensure the decomposition matches the original expression for all x, which is why they must exist even though their values are not required for this subsubtopic.

No, any order of the individual fractional terms is acceptable as long as each linear factor appears with its corresponding constant numerator.

However, placing the terms in a systematic order, such as increasing root value or the natural factorisation order, helps reduce errors in later steps like integration.

It reveals the hidden structure of a rational expression, showing how it breaks down into simpler pieces. This structural understanding is valuable beyond integration.

It can help diagnose algebraic behaviour, identify discontinuities more clearly, and simplify manipulation when working with rational expressions in broader problem-solving contexts.

Practice Questions

(1–3 marks)
A rational function has denominator (x − 1)(x + 3). Write down the general form of its partial fraction decomposition for a proper rational function with this denominator.

(1–3 marks)
• 1 mark: States a correct general decomposition of the form A/(x − 1) + B/(x + 3).
• 1 additional mark (optional depending on mark allocation): Notes that A and B are constants.

(4–6 marks)
A rational function is given by R(x) = (5x + 2) / (x2 + x − 6).
(a) Factor the denominator fully.
(b) Hence write R(x) in the form A/(x − a) + B/(x − b), where a and b are constants.
(You are not required to find the values of A and B.)

(4–6 marks)
(a)
• 1 mark: Correctly factors the denominator x2 + x − 6 as (x + 3)(x − 2).

(b)
• 1 mark: Writes the correct general form A/(x − 2) + B/(x + 3).
• 1 mark: Shows clear reasoning that the decomposition follows from the distinct linear factors identified.
• 1 further mark (if available): States that A and B are constants determined by matching the original rational function.

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