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AP Calculus AB study notes

8.11.1 Ring-Shaped Cross Sections and the Washer Idea

AP Syllabus focus:
‘When a region with a hole is revolved about the x- or y-axis, cross sections are washers with inner and outer radii, leading to ring-shaped slices of the solid.’

Ring-Shaped Cross Sections and the Washer Idea

A solid of revolution formed from a region with a hollow center produces washer-shaped cross sections, allowing volume to be computed by integrating circular areas with missing inner portions.

Understanding Ring-Shaped Cross Sections

When a plane region that does not touch the axis of revolution is revolved around that axis, the resulting three-dimensional slices perpendicular to the axis are not solid discs but washers. A washer resembles a flat ring: a circular region with another circular region removed from its center. This structure emerges naturally whenever the original region includes a gap between part of the boundary and the axis of revolution. The gap forms the inner radius, while the outer boundary of the region forms the outer radius. The distinction between these radii is essential because it determines how much material appears in each cross section of the solid.

Because washers have a central hole, their cross-sectional area must account for two circular measurements: the outer circle's area and the inner circle's area. Each slice’s area is the difference between these two, making the washer method a natural extension of the disc method. The method relies on understanding how radii vary along the chosen axis and how those radii arise from the geometry of the region being revolved.

Each thin slice perpendicular to the axis is therefore a washer: a circular ring with an outer edge and a central hole rather than a solid disk.

Pasted image

This diagram shows how a planar region between two curves generates a washer-shaped cross section and a solid of revolution when rotated about the axis. It emphasizes that each slice is a ring because the region does not extend to the axis of rotation. Extra details such as the specific curves and interval offer helpful context beyond the syllabus requirements. Source.

The Concept of Radii in Washer Problems

The outer radius is defined as the distance from the axis of revolution to the outer boundary of the region.
The inner radius is the distance from the axis to the inner boundary, which creates the hole. These distances are essential because they determine the shape and size of each washer. The difference between the squared values of these radii generates the cross-sectional area used to accumulate volume.

Outer radius: The distance from the axis of revolution to the farthest boundary of the region being revolved.

A sentence must come between definition blocks to maintain clarity and avoid clustering of formal statements.

Inner radius: The distance from the axis of revolution to the nearest boundary of the region, creating the central hole of the washer.

These radii depend on the orientation of the revolution. If the solid is revolved around the x-axis, the radii must be expressed as vertical distances, written as functions of the variable of integration. If the solid is revolved around the y-axis, the radii correspond to horizontal distances and must be written in terms of the variable appropriate for integrating with respect to y. Understanding these directional relationships ensures that the formulation of the volume integral correctly reflects the geometry of the solid.

Revolving such a region around an axis that runs outside the region produces a three-dimensional solid with a hollow core extending along the axis of revolution.

Pasted image

These diagrams illustrate how revolving a region that does not touch the axis produces a hollow solid. The images highlight the central void and the outer surface that together define washer-shaped slices. Labels such as R(x) and r(x) provide additional detail not strictly required by the syllabus but support understanding of inner and outer radii. Source.

Connecting Washers to Accumulated Volume

The washer method reflects the broader Calculus AB emphasis on viewing volume as an accumulation of infinitesimal quantities. In this case, the infinitesimal quantity is the area of a washer-shaped slice, and the volume is the accumulated sum of such slices across the interval of revolution. The method formalizes this idea using a definite integral whose integrand captures the difference between the outer circular area and the inner circular area.

Washer Cross-Sectional Area=π(Router2Rinner2) \text{Washer Cross-Sectional Area} = \pi (R_{\text{outer}}^2 - R_{\text{inner}}^2)
Router R_{\text{outer}} = Distance from axis of revolution to outer boundary
Rinner R_{\text{inner}} = Distance from axis of revolution to inner boundary

A sentence here provides continuity before further mathematical structure is introduced, ensuring the exposition remains readable and well paced.

V=abπ(Router2Rinner2),dx V = \int_{a}^{b} \pi (R_{\text{outer}}^2 - R_{\text{inner}}^2), dx
a,b a, b = Endpoints of the interval along the axis of revolution

This integral expresses the essential idea: volume is the accumulation of cross-sectional areas, each computed as a ring formed by subtracting the area of the inner circle from the area of the outer circle. The method is particularly effective when the region’s boundaries are clearly identified and when both radii can be expressed as functions of a single variable across the interval. In AP Calculus AB, this technique is used only for solids revolved around the x- or y-axis when a central cavity exists.

Identifying When to Use the Washer Method

Students should recognize the need for washers whenever the region being revolved does not touch the axis of revolution or when the region is bounded by two separate functions relative to the axis. Key indicators include:

  • The presence of a gap between part of the region and the axis.

  • A boundary curve that produces an inner radius smaller than the outer radius.

  • A region enclosed by two curves, where rotation causes the nearer curve to form the inner boundary of the washer.

  • A geometric description that specifies a hole in the resulting solid.

We usually describe the distance from the axis to the outer curve as the outer radius and the distance from the axis to the inner curve as the inner radius, each measured along the same perpendicular slice.

Visual and Conceptual Interpretation

Visualizing washers helps reinforce the conceptual understanding of volume as accumulated area. Each slice resembles a ring whose thickness corresponds to the differential element along the axis of revolution. As these slices stack, they build the overall three-dimensional shape. This perspective aligns with the AP Calculus AB emphasis on interpreting integrals as accumulated change, connecting geometric intuition with analytic computation.

Understanding washer-shaped cross sections ensures students can construct accurate integrals for volumes of revolution whenever a hollow interior appears in the solid.

FAQ

A washer occurs whenever there is a visible gap between the region and the axis of revolution. This appears on the graph as the boundary of the region sitting entirely above, below, or to one side of the axis, with no point touching it.

If the region touches the axis even once along the interval of integration, some cross-sections may become discs instead.

Students often confuse which curve determines each radius. A reliable approach is:

• Outer radius: always the curve farther from the axis of revolution.
• Inner radius: always the curve nearer to the axis of revolution.

Another common error is mixing up vertical and horizontal distances when the axis of rotation is different from the variable of integration.

The washers accumulate along the axis of integration. Each slice must therefore use radii measured perpendicular to that axis expressed as a function of the same variable.

If the radii are expressed in the wrong variable, the integral will not correspond to the actual geometry of the slices, leading to an incorrect volume.

Yes. This occurs when the relationship between the curves and the axis of rotation changes across the domain, altering which curve forms the inner or outer radius.

Such cases require splitting the integral into separate intervals, each with its own correct pairing of inner and outer radii.

The washer method works well when:

• Both boundaries can be written easily as distances from the axis of revolution.
• The region is aligned so that a single variable describes both radii cleanly.
• The hollow interior is uniform enough that a single expression captures the inner radius.

These conditions make the cross-sectional area straightforward to express as outer radius squared minus inner radius squared.

Practice Questions

Question 1 (1–3 marks)
A region in the plane is bounded above by the curve y = 4, below by y = 1, and lies entirely to the right of the y-axis. The region is revolved about the y-axis, creating a solid of revolution.
(a) Explain why the cross-sections perpendicular to the axis of rotation are washers rather than discs.
(b) State which distance represents the outer radius and which represents the inner radius for a typical cross-section.

Question 1
(a) 1 mark: States that the region does not touch the axis of rotation, so there is a gap, creating a hole in the solid.
(b) 1 mark: Identifies the outer radius as the distance from the axis of rotation to the far boundary of the region.
  1 mark: Identifies the inner radius as the distance from the axis of rotation to the nearer boundary of the region.

Total: 3 marks

Question 2 (4–6 marks)
A region is bounded by the curves y = 2x + 1 and y = x + 3 for 0 ≤ x ≤ 2. The region is revolved about the x-axis, forming a solid with a hollow interior.
(a) Write an expression for the outer radius and the inner radius of a typical washer in terms of x.
(b) Write down, but do not evaluate, the definite integral that represents the volume of the solid.
(c) Briefly explain why the washer method is required rather than the disc method in this situation.

Question 2
(a) 1 mark: Correct outer radius stated as the distance from the x-axis to the higher curve y = 2x + 1.
  1 mark: Correct inner radius stated as the distance from the x-axis to the lower curve y = x + 3.
(b) 2 marks: Writes a correct definite integral of the form integral from 0 to 2 of pi[(outer radius squared) minus (inner radius squared)] dx.
(c) 1 mark: States that the washer method is needed because the region does not touch the axis of rotation and therefore produces a hollow solid.

Total: 5 marks

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