AP Syllabus focus:
‘Students analyze exponential models by considering the sign and size of the constant k, distinguishing between growth and decay and describing how solutions behave as time increases.’
Understanding whether an exponential model represents growth or decay is essential for interpreting real-world behavior, as the constant k fundamentally determines how solutions evolve over increasing values of the independent variable.
Growth versus Decay in Exponential Differential Equations
In an exponential differential equation of the form , the constant k governs how the dependent variable changes with respect to time. Because this relationship directly ties the rate of change to the current amount, the solution displays predictable long-term behavior based on the sign and magnitude of k.
The Role of the Constant k
The value of k serves as the determining factor for whether the model represents exponential growth or exponential decay. When first analyzing such equations, students should focus on both the sign and the relative size of k, as each affects solution behavior differently.
Students analyze exponential models by considering the sign and size of the constant k, distinguishing between growth and decay and describing how solutions behave as time increases.

This figure compares exponential growth and decay curves, each beginning at the same initial value. Growth corresponds to parameters such as k>0, while decay corresponds to k<0. The labels , , and provide standard exponential notation that extends slightly beyond this subsubtopic but remains appropriate for AP Calculus AB. Source.
Exponential Growth: A process in which a quantity increases at a rate proportional to its current value, occurring when k > 0.
A sentence explaining follows: When the rate of change is positive and proportional to the quantity, the function accelerates upward over time, causing increasingly rapid growth.
Exponential Decay: A process in which a quantity decreases at a rate proportional to its current value, occurring when k < 0.
After introducing decay, it is important to note that negative values of k produce functions that approach zero without ever becoming negative, reflecting many natural diminishing processes.
Solution Form and Behavior Over Time
Both growth and decay share the same general solution structure. Once students understand how the exponential solution behaves, they can identify long-term trends directly from the differential equation without needing to compute additional values.
= Value of the quantity at time
= Initial value at time
= Growth or decay constant (per unit time)
= Independent variable, typically representing time
Although the equation itself is compact, its behavior changes dramatically depending on the characteristics of k, making interpretation essential for AP Calculus AB students.
Interpreting Growth Behavior When k > 0
When k > 0, the graph of y = y₀e^{kt} shows exponential growth: it passes through (0, y₀), increases monotonically, and remains concave up for all relevant values of the independent variable.

This graph illustrates the exponential function , demonstrating continuous, accelerating growth. The curve increases more rapidly as increases and approaches the horizontal asymptote for negative . Its concave-up shape and monotonic increase reflect the behavior expected when k>0. Source.
When k is positive, the function rises increasingly quickly. The slope field associated with will display steeper positive slopes as increases, indicating acceleration. Important features of exponential growth include:
Continuous increase: The function consistently increases for all , provided y_0 > 0.
Increasing slope: Because the slope is proportional to , larger values of the function produce steeper tangent lines.
Unbounded growth: As increases, grows without bound, reflecting many real-world models such as unrestricted population growth or compound interest.
Sensitivity to k: Larger positive values of k cause the function to grow faster, making even small differences in k significant over time.
Interpreting Decay Behavior When k < 0
When k < 0, the graph of y = y₀e^{kt} shows exponential decay, decreasing from its initial value while remaining above the horizontal axis and flattening toward y = 0 as time increases.

This graph shows the decay function , which decreases while remaining positive. The curve approaches asymptotically, flattening as increases. Its shape reflects the qualitative behavior of solutions when k<0. Source.
When k is negative, the function decreases at a rate proportional to its current value. The slope field will show negative slopes that flatten as approaches zero. Key features of exponential decay include:
Continuous decrease: The function declines smoothly over time when y_0 > 0.
Decreasing magnitude of slope: Tangent lines become less steep as diminishes, showing that decay slows.
Asymptotic behavior: The function approaches as but never reaches it, reflecting processes such as radioactive decay or cooling.
Sensitivity to k: Larger negative magnitudes of k result in faster decay, causing the function to decrease more rapidly.
Comparing Growth and Decay Graphs
Students should develop an ability to visualize how exponential solutions behave without computing specific values. When comparing growth and decay:
Growth graphs curve upward, becoming increasingly steep, while decay graphs curve downward, flattening as they approach zero.
Both types of graphs are smooth and continuous, with no sudden changes in direction.
For the same initial value , growth curves diverge upward, and decay curves descend toward zero, making them visually distinguishable even in a family of solutions.
Effect of the Size of k on Graph Behavior
The magnitude of k affects the rate at which the solution grows or decays:
A larger positive k produces rapid upward acceleration.
A smaller positive k still results in growth but more gradually.
A larger negative k yields fast decay.
A smaller negative k produces slow decay over a longer time span.
These distinctions allow students to infer qualitative behaviors simply by examining the differential equation.
Long-Term Behavior as Time Increases
As the syllabus emphasizes, students must describe how solutions behave as time increases:
With k > 0, accelerates upward without bound.
With k < 0, decreases toward zero.
The graph’s long-term trend can be inferred directly from the sign of k.
Understanding these ideas enables students to interpret real-world situations modeled by exponential differential equations and to analyze solution behavior efficiently.
FAQ
A steep exponential curve indicates that the constant k has a larger magnitude, meaning the rate of growth or decay is faster.
A shallow curve corresponds to a smaller magnitude of k, meaning the quantity changes more slowly over time.
For growth curves, steeper graphs rise more quickly.
For decay curves, steeper graphs fall sharply before flattening out sooner.
They never reach zero because the rate of change is always proportional to the current value, which remains positive.
As the quantity decreases, the rate becomes smaller, so the curve slows down and only approaches zero asymptotically.
This behaviour reflects many physical processes where something reduces but cannot completely vanish in finite time.
Yes. The long-term behaviour is determined entirely by the sign of k, not by the initial value.
Two exponential growth functions with different starting values will both grow without bound.
Similarly, two decay functions with different initial values will both decrease towards zero.
The initial value only shifts the vertical starting point; it does not alter the trend.
Both doubling time (growth) and half-life (decay) measure how quickly the quantity changes.
They depend on the magnitude of k:
• Larger positive k gives a shorter doubling time.
• Larger negative k gives a shorter half-life.
These measures allow you to compare exponential processes without explicitly computing the full function.
The second derivative of an exponential function is always proportional to the function itself, meaning its curvature behaves consistently.
For both growth and decay:
• The graph has no corners or discontinuities.
• It curves gently upward, even when decreasing, because the rate of change becomes less negative over time.
This smooth concavity is a hallmark of exponential behaviour and helps distinguish it from other model types.
Practice Questions
Question 1 (2 marks)
A quantity y satisfies the differential equation dy/dt = ky, where k is a constant.
Explain how the sign of k determines whether the solution represents exponential growth or exponential decay.
Question 1 (2 marks)
• 1 mark: Correctly states that k > 0 gives exponential growth.
• 1 mark: Correctly states that k < 0 gives exponential decay.
Question 2 (5 marks)
A population P(t) satisfies the differential equation dP/dt = kP, where k is a constant and t is measured in years.
The initial population is P(0) = 150.
(a) State whether the long-term behaviour of P(t) represents growth or decay when k = -0.08. (1 mark)
(b) Describe the long-term behaviour of the population as t increases when k = -0.08. (2 marks)
(c) Explain how the magnitude of k affects the rate at which the population changes. (2 marks)
Question 2 (5 marks)
(a)
• 1 mark: Identifies that k = -0.08 represents exponential decay.
(b)
• 1 mark: States that the population decreases over time.
• 1 mark: States that it approaches zero but never reaches it.
(c)
• 1 mark: States that a larger magnitude of k makes the population change faster.
• 1 mark: States that a smaller magnitude of k makes the population change more slowly (whether increasing or decreasing).
