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AP Chemistry Notes

9.6.5 Why Solubility Predictions Can Be Hard: Competing Terms and Cancellations

AP Syllabus focus: ‘Predicting total ΔG° of dissolution can be challenging because the free-energy contributions from different factors can partially cancel.’

Solubility is controlled by a balance of energetic and entropic changes that often oppose each other. Because these competing contributions can be similar in magnitude, small differences in structure, temperature, or solvent can flip the predicted outcome.

Why “predicting solubility” is thermodynamically subtle

Solubility under a given set of conditions reflects whether dissolving is thermodynamically favourable overall. The difficulty is that dissolution is rarely driven by a single effect; instead, multiple free-energy contributions add together, and their sum may be small.

Free-energy cancellation: when large positive and negative contributions to a process’s Gibbs free energy offset, making the net ΔG\Delta G^\circ small and highly sensitive to small changes.

A small net ΔG\Delta G^\circ means the system is “on the fence,” so predictions based on one dominant factor (e.g., “ionic = soluble”) can fail.

Competing terms that can offset during dissolution

Enthalpy–entropy competition

Dissolution commonly features opposing signs in ΔH\Delta H^\circ and ΔS\Delta S^\circ, so the net free energy depends on which term wins at the temperature of interest.

ΔG=ΔHTΔS \Delta G^\circ = \Delta H^\circ - T\Delta S^\circ

ΔG \Delta G^\circ = standard Gibbs free energy change for dissolution, J mol1^{-1}

ΔH \Delta H^\circ = standard enthalpy change for dissolution, J mol1^{-1}

T T = absolute temperature, K

ΔS \Delta S^\circ = standard entropy change for dissolution, J mol1^{-1} K1^{-1}

Even when you can qualitatively guess the signs, the magnitudes of ΔH\Delta H^\circ and TΔST\Delta S^\circ may be close enough to partially cancel.

Enthalpic “give-and-take” can nearly balance

In many dissolutions, enthalpy includes both energy costs and energy releases, such as:

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Born–Haber-type thermochemical cycle diagram showing enthalpy changes as a sequence of steps with arrows (energy increasing upward). This kind of stepwise energy accounting is the same logic used in dissolution: large positive steps (separating species) can be offset by large negative steps (forming stabilizing interactions), so the net ΔH\Delta H^\circ can end up small. Source

  • Costs from separating solute particles (breaking an extended solid structure)

  • Releases from forming new solute–solvent attractions

If these are similar in magnitude, ΔH\Delta H^\circ ends up near zero, and the outcome becomes dominated by entropy (or vice versa). Because these interactions depend on ion size, charge density, and molecular polarity, small chemical changes can shift the balance.

Entropy is not “always increasing” in a simple way

A frequent pitfall is assuming “mixing increases disorder, so ΔS>0\Delta S^\circ > 0.” In reality, ΔS\Delta S^\circ for dissolution is a sum of multiple, sometimes opposing, contributions:

  • Dispersal of solute particles into solution (often increases entropy)

  • Solvent organisation around solute particles (can decrease entropy)

  • Changes in the number and freedom of independently moving species (context-dependent)

Because these can offset, ΔS\Delta S^\circ can be small or even negative, especially when dissolving species that strongly constrain nearby solvent motion.

Why cancellations make predictions fragile

Small net ΔG\Delta G^\circ amplifies “minor” effects

When cancellations occur, the net free energy can be comparable to typical uncertainties in estimation.

Pasted image

Ellingham diagram: a set of straight-line plots of ΔG\Delta G versus temperature, where the slope relates to ΔS-\Delta S and the intercept relates to ΔH\Delta H. The key study takeaway is that modest temperature changes can move a borderline process across ΔG=0\Delta G=0, illustrating why ‘free-energy cancellation’ makes predictions fragile. Source

Then, seemingly minor factors become decisive:

  • Temperature: changing TT rescales the entropy term TΔST\Delta S^\circ, so a borderline process can switch from unfavourable to favourable (or the reverse).

  • Different solid forms: changes in crystal packing (polymorphs) alter the balance of terms.

  • Solvent identity: a solvent that stabilises solute particles slightly better can change the net sign of ΔG\Delta G^\circ.

Qualitative rules can contradict each other

Heuristics like “higher charge = stronger solute–solvent attractions” compete with “higher charge = harder to separate the solid.” Both can be true simultaneously, so the net effect is not obvious without knowing which term dominates for that specific solute–solvent pair.

The net result can be close to zero

If ΔG\Delta G^\circ is small because of cancellation, the system may show:

  • Only modest solubility (neither “insoluble” nor “highly soluble”)

  • Strong sensitivity to conditions (temperature changes or slight formulation changes)

In this regime, predicting solubility is hard precisely because the process is governed by a difference of large numbers, not a single large driving force.

FAQ

Different crystal packing changes the energetic cost of separating particles and can also alter how a solvent organises around released species. If terms nearly cancel, small structural differences can dominate the net $\Delta G^\circ$.

When $\Delta H^\circ$ and $T\Delta S^\circ$ nearly cancel, changing $T$ noticeably shifts the $T\Delta S^\circ$ term.

A borderline $\Delta G^\circ$ can change sign.

The process has no strong thermodynamic push either way: dissolving and not dissolving are similarly favourable. Small effects (impurities, solvent composition, temperature) can then control the observed solubility.

They typically focus on one contribution (e.g., stronger attractions) while ignoring an opposing one (e.g., higher energetic cost to separate the solid). Cancellation means both must be considered together.

If the true net $\Delta G^\circ$ is small, then modest uncertainties in estimated enthalpy/entropy contributions can be comparable to the net value, making predictions unreliable without direct measurement.

Practice Questions

Q1 (2 marks): Explain, in terms of Gibbs free energy, why solubility predictions can be difficult when ΔH\Delta H^\circ and TΔST\Delta S^\circ are similar in magnitude.

  • States that ΔG=ΔHTΔS\Delta G^\circ = \Delta H^\circ - T\Delta S^\circ and that terms can oppose (1)

  • Explains that near-cancellation makes net ΔG\Delta G^\circ small so small changes (e.g., temperature/structure) can change favourability (1)

Q2 (5 marks): A student claims “dissolving always increases entropy, so any substance with strong solute–solvent attractions will definitely be soluble.” Evaluate this claim using the idea of competing terms and cancellations.

  • Identifies that ΔS\Delta S^\circ for dissolution can be positive or negative due to multiple contributions (1)

  • Notes solvent organisation can decrease entropy and offset dispersal/mixing (1)

  • Explains strong solute–solvent attractions may make ΔH\Delta H^\circ more negative but does not guarantee ΔG<0\Delta G^\circ < 0 if other enthalpic costs exist (1)

  • Uses cancellation idea: large opposing contributions can yield small net ΔG\Delta G^\circ (1)

  • Concludes claim is not always correct; solubility is sensitive when net ΔG\Delta G^\circ is near zero (1)

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