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AP Physics 1: Algebra Notes

2.7.2 What Kinetic Friction Depends On

AP Syllabus focus: ‘The kinetic friction force equals the coefficient of kinetic friction times the normal force and does not depend on contact area.’

Kinetic friction is modeled with a simple proportional relationship that lets you predict sliding forces without microscopic detail. This page focuses on what sets the size of kinetic friction in AP Physics 1 Algebra problems.

Core model: what kinetic friction depends on

Kinetic friction is the frictional force present when two surfaces slide relative to each other. In AP Physics 1 Algebra, its magnitude depends on:

  • the normal force between the surfaces, NN

  • the coefficient of kinetic friction, μk\mu_k, for that pair of surfaces

Coefficient of kinetic friction

Coefficient of kinetic friction (μk\mu_k): a dimensionless constant that relates the kinetic friction force to the normal force for a given pair of surfaces in sliding contact.

In this course model, μk\mu_k is treated as a given property for the situation (often provided in the prompt).

Relationship to the normal force

fk=μkN f_k = \mu_k N

fk f_k = kinetic friction force magnitude (N)

μk \mu_k = coefficient of kinetic friction (unitless)

N N = normal force magnitude (N)

This equation states a direct proportionality: if NN increases, then the kinetic friction magnitude increases in the same ratio (assuming μk\mu_k is unchanged).

Contact area: what kinetic friction does NOT depend on (in AP Physics 1)

A key AP Physics 1 statement is that kinetic friction does not depend on contact area. That means:

  • doubling the apparent touching area does not automatically double fkf_k

  • shrinking the apparent touching area does not automatically reduce fkf_k

In typical exam problems, you should not introduce an “area” term into kinetic friction.

Pasted image

Diagram illustrating that rough surfaces touch only at a small number of microscopic high points, so the real contact area is much smaller than the apparent area. As the normal force increases, more microscopic contact points engage, which helps explain why the macroscopic model makes kinetic friction scale with NN rather than with the apparent contact area. Source

If the same materials are sliding and the normal force is unchanged, the model predicts the same fkf_k even if the object is flipped onto a different face.

Practical implications for problem solving

How changes in situation change fkf_k

Use the model to reason quickly about proportional changes:

  • If NN increases (for example, due to a stronger push into a surface), then fkf_k increases.

  • If NN decreases (for example, reduced pressing force), then fkf_k decreases.

  • If the prompt changes the surface pairing (different materials), then μk\mu_k may change, so fkf_k changes even if NN stays the same.

  • If only the object’s contact area changes, but NN and μk\mu_k are the same, then fkf_k stays the same in the AP model.

Using the model consistently with directions

Although the equation gives the magnitude, kinetic friction as a force acts:

Pasted image

A free-body diagram for an object sliding on an incline, showing NN perpendicular to the surface and friction parallel to the surface opposing the motion. The diagram also decomposes weight into components, emphasizing that NN is set by the perpendicular component of gravity, which then sets fkf_k through fk=μkNf_k=\mu_k N. Source

  • parallel to the surface

  • opposite the direction of relative sliding motion

For this subsubtopic, the key dependency is magnitude: do not treat kinetic friction as “self-adjusting” to any value during sliding; in the model it is set by μkN\mu_k N.

Common AP-style constraints

To stay aligned with AP Physics 1 Algebra assumptions:

  • treat μk\mu_k as constant for a given interaction

  • ignore contact area effects

  • avoid adding extra dependencies (speed, time, “roughness area,” etc.) unless explicitly stated by the problem (rare for AP 1)

FAQ

Because increasing apparent area typically decreases pressure, and the microscopic real contact adjusts so the total resistive force stays roughly proportional to $N$ in many everyday cases.

At very high speeds, unusual materials (e.g., rubber), lubricated contacts, or when heating significantly changes the surfaces. In such cases $\mu_k$ may vary during motion.

Measure $N$ and the steady pulling force needed to keep constant speed. Then compute $\mu_k = f_k/N$. Repeating trials improves reliability.

In many real systems it can vary with speed, but AP Physics 1 typically treats $\mu_k$ as constant unless the problem explicitly gives a speed-dependent friction model.

Real traction involves deformation, temperature, tread, and material behaviour; “grip” can involve effects beyond simple kinetic friction, so the basic $f_k=\mu_k N$ model may not capture those details.

Practice Questions

Q1 (3 marks) A 2.0,kg2.0,\text{kg} block slides on a horizontal surface with coefficient of kinetic friction μk=0.30\mu_k = 0.30. Take g=10,N,kg1g = 10,\text{N},\text{kg}^{-1}. Determine the magnitude of the kinetic friction force.

  • States/uses N=mgN = mg on a horizontal surface: N=2.0×10=20,NN = 2.0 \times 10 = 20,\text{N} (1)

  • Uses fk=μkNf_k = \mu_k N (1)

  • Calculates fk=0.30×20=6.0,Nf_k = 0.30 \times 20 = 6.0,\text{N} (1)

Q2 (5 marks) A block slides while being pushed against a vertical wall. The coefficient of kinetic friction is μk\mu_k. The person pushes horizontally with force PP so the normal force on the block from the wall is N=PN=P. The block slides downward at constant speed. (a) Write an expression for the kinetic friction magnitude in terms of μk\mu_k and PP. (2) (b) State whether the kinetic friction depends on the contact area between block and wall in the AP model. (1) (c) Using your answers, explain what change to PP is required to keep the block sliding downward at constant speed if the block is replaced with one that has double the contact area but the same mass and same materials. (2)

  • (a) Uses fk=μkNf_k = \mu_k N (1)

  • (a) Substitutes N=PN=P to give fk=μkPf_k = \mu_k P (1)

  • (b) States kinetic friction does not depend on contact area (1)

  • (c) Concludes PP should be unchanged (1)

  • (c) Links reasoning to fk=μkPf_k = \mu_k P and area-independence in the model (1)

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