AP Syllabus focus: ‘Centripetal acceleration points toward the center of a circular path and has magnitude v squared over r.’
Circular motion is special because an object can be accelerating even when its speed is constant. In AP Physics 1, the key idea is centripetal acceleration: acceleration directed inward that continuously turns the velocity vector.
What centripetal acceleration is
When an object moves along a circular path, its velocity is always tangent to the circle.

Velocity vistangenttothecircularpath,whilecentripetalaccelerationa_c points radially inward toward the center. This visual reinforces that an object can have constant speed but still accelerate because its direction of motion is continuously changing. Source
Even if the object’s speed stays the same, the direction of the velocity changes from instant to instant, which means the object is accelerating.

Two velocity vectors v_1andv_2 at nearby points on a circle produce a change in velocity \Delta vthatpointsapproximatelytowardthecenter.Inthelimitofaverysmalltimestep,thisinwarddirectionbecomesthecentripetalaccelerationdirection.</em><arel="noopenernoreferrernofollow"href="https://openstax.org/books/physics/pages/6−2−uniform−circular−motion"><em>Source</em></a></p><divclass="takeaways−section"><p><strong>Centripetalacceleration</strong>—theaccelerationrequiredtokeepanobjectmovinginacircle,alwayspointingtowardthe<strong>center</strong>ofthecircularpath.</p></div><p>Centripetalaccelerationisnotanew“type”ofmotionseparatefromNewton’slaws;itisageometricconsequenceofchangingdirectionincircularmotion.</p><h2class="editor−heading"id="direction−always−toward−the−center"><strong>Direction:alwaystowardthecenter</strong></h2><p>Acentripetalaccelerationvectorpointsalongthe<strong>radialdirection</strong>,straightinwardtowardthecircle’scenteratthatinstant.</p><p>Keydirectionalfactstouseindiagramsandreasoning:</p><ul><li><p><strong>Inward(center−seeking):</strong>theaccelerationarrowpointsfromtheobjecttowardthecenterofcurvature.</p></li><li><p><strong>Perpendiculartovelocity(inuniformcircularmotion):</strong>becausevelocityistangentandcentripetalaccelerationisradial,theyareatrightangleswhenspeedisconstant.</p><p></p></li><li><p><strong>Changescontinuously:</strong>astheobjectmovesaroundthecircle,theinwarddirectionrotates,sotheaccelerationvector’sdirectionchangesevenifitsmagnitudestaysthesame.</p></li></ul><p>Acommonconceptualcheck:ifthepathisperfectlycircularandtheobjectis“turning,”theaccelerationmusthaveaninwardcomponent;otherwisetheobjectwouldmoveoffalongatangent.</p><h2class="editor−heading"id="magnitude−how−v−and−r−control−the−inward−acceleration"><strong>Magnitude:howvandrcontroltheinwardacceleration</strong></h2><p>Forcircularmotion,themagnitudeofcentripetalaccelerationdependsonhowfasttheobjectismovingandhowtighttheturnis(theradius).</p><divclass="example−section"><p> a_c = \dfrac{v^2}{r} </p><p> a_c =centripetalaccelerationmagnitude(m/s^2)</p><p> v =speed(m/s)</p><p> r =radiusofcircularpath(m)</p><p> a_c = \omega^2 r </p><p> \omega =angularspeed(rad/s)</p></div><p>Thisrelationshipencodestwohigh−utilityideas:</p><ul><li><p>Increasingspeedincreasesinwardaccelerationstrongly:doublingvmakesa_cfourtimeslarger.</p></li><li><p>Largerradiusmeansagentlerturn:doublingrhalvesa_cforthesamespeed.</p></li></ul><h2class="editor−heading"id="units−and−physical−interpretation"><strong>Unitsandphysicalinterpretation</strong></h2><p>Centripetalaccelerationhasthesameunitsasanyacceleration:<strong>m/s^2</strong>.Itmeasureshowquicklythevelocityvectorisbeingredirected,notnecessarilyhowquicklytheobjectisspeedingup.</p><p>Interpretationguidelines:</p><ul><li><p>Ifa_cislarge,theobject’sdirectionischangingrapidly(tightcurveand/orhighspeed).</p></li><li><p>Ifa_c = 0,thereisnocurvatureinthemotionatthatinstant(straight−linemotion).</p></li></ul><h2class="editor−heading"id="practical−checklist−for−identifying−centripetal−acceleration"><strong>Practicalchecklistforidentifyingcentripetalacceleration</strong></h2><p>Usethisprocesswhenyousee“movesinacircle”or“turns”:</p><ul><li><p>Identifythe<strong>instantaneouscenter</strong>ofthecircularpath.</p></li><li><p>Draw\vec a_c<strong>fromtheobjecttowardthecenter</strong>.</p></li><li><p>Usethepathradiusr(notdiameter)andtheobject’sspeedvtodeterminethemagnituderelationship.</p></li><li><p>Treata_c$ as the acceleration component responsible for changing direction; constant speed does not imply zero acceleration in circular motion.